Table of Chebyshev psi function












3












$begingroup$


This should be easy, but for some reason I'm struggling. The Chebyshev psi function is given as the sum from 0 to x of the von Mangoldt function MangoldtLambda[x]. I want to tabulate it. Ideally, I'd like to express the function using Sum, but I can't find the right form. This doesn't work:



TableForm[
Table[With[{k = 10}, Sum[N[MangoldtLambda[x], 5], {x, 0, k}]],
{x, 0, 10}]]


This produces a series that makes no sense at all:



TableForm[
Table[With[{k = 10}, Sum[N[MangoldtLambda[x], 5], {k, 0, x}]],
{x, 0, 10}]]


Accumulate doesn't work either:



TableForm[Table[Accumulate[N[MangoldtLambda[x], 5]], {x, 0, 10}]]


Clearly I'm suffering from a failure of imagination, but I'd appreciate help.










share|improve this question









$endgroup$

















    3












    $begingroup$


    This should be easy, but for some reason I'm struggling. The Chebyshev psi function is given as the sum from 0 to x of the von Mangoldt function MangoldtLambda[x]. I want to tabulate it. Ideally, I'd like to express the function using Sum, but I can't find the right form. This doesn't work:



    TableForm[
    Table[With[{k = 10}, Sum[N[MangoldtLambda[x], 5], {x, 0, k}]],
    {x, 0, 10}]]


    This produces a series that makes no sense at all:



    TableForm[
    Table[With[{k = 10}, Sum[N[MangoldtLambda[x], 5], {k, 0, x}]],
    {x, 0, 10}]]


    Accumulate doesn't work either:



    TableForm[Table[Accumulate[N[MangoldtLambda[x], 5]], {x, 0, 10}]]


    Clearly I'm suffering from a failure of imagination, but I'd appreciate help.










    share|improve this question









    $endgroup$















      3












      3








      3





      $begingroup$


      This should be easy, but for some reason I'm struggling. The Chebyshev psi function is given as the sum from 0 to x of the von Mangoldt function MangoldtLambda[x]. I want to tabulate it. Ideally, I'd like to express the function using Sum, but I can't find the right form. This doesn't work:



      TableForm[
      Table[With[{k = 10}, Sum[N[MangoldtLambda[x], 5], {x, 0, k}]],
      {x, 0, 10}]]


      This produces a series that makes no sense at all:



      TableForm[
      Table[With[{k = 10}, Sum[N[MangoldtLambda[x], 5], {k, 0, x}]],
      {x, 0, 10}]]


      Accumulate doesn't work either:



      TableForm[Table[Accumulate[N[MangoldtLambda[x], 5]], {x, 0, 10}]]


      Clearly I'm suffering from a failure of imagination, but I'd appreciate help.










      share|improve this question









      $endgroup$




      This should be easy, but for some reason I'm struggling. The Chebyshev psi function is given as the sum from 0 to x of the von Mangoldt function MangoldtLambda[x]. I want to tabulate it. Ideally, I'd like to express the function using Sum, but I can't find the right form. This doesn't work:



      TableForm[
      Table[With[{k = 10}, Sum[N[MangoldtLambda[x], 5], {x, 0, k}]],
      {x, 0, 10}]]


      This produces a series that makes no sense at all:



      TableForm[
      Table[With[{k = 10}, Sum[N[MangoldtLambda[x], 5], {k, 0, x}]],
      {x, 0, 10}]]


      Accumulate doesn't work either:



      TableForm[Table[Accumulate[N[MangoldtLambda[x], 5]], {x, 0, 10}]]


      Clearly I'm suffering from a failure of imagination, but I'd appreciate help.







      functions table summation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 10 hours ago









      Richard Burke-WardRichard Burke-Ward

      5769




      5769






















          1 Answer
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          5












          $begingroup$

          There seems to be a duplicate use of the symbol x in your formulas.



          ChebyshevPsi[x_] := Sum[MangoldtLambda[y], {y, x}]
          Table[ChebyshevPsi[x], {x, 10}]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          You can also directly construct a list of these with Accumulate:



          Accumulate@Array[MangoldtLambda, 10]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          Plot the deviation of the Chebyshev $psi$ function from $x$:



          ListLinePlot[MapIndexed[{#2[[1]], #1 - #2[[1]]} &, 
          Accumulate@Array[MangoldtLambda, 1000]], Frame -> True,
          FrameLabel -> {x, ψ[x] - x}]


          enter image description here






          share|improve this answer











          $endgroup$













          • $begingroup$
            I'll tick this when it lets me! Appreciated.
            $endgroup$
            – Richard Burke-Ward
            10 hours ago











          Your Answer





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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          5












          $begingroup$

          There seems to be a duplicate use of the symbol x in your formulas.



          ChebyshevPsi[x_] := Sum[MangoldtLambda[y], {y, x}]
          Table[ChebyshevPsi[x], {x, 10}]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          You can also directly construct a list of these with Accumulate:



          Accumulate@Array[MangoldtLambda, 10]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          Plot the deviation of the Chebyshev $psi$ function from $x$:



          ListLinePlot[MapIndexed[{#2[[1]], #1 - #2[[1]]} &, 
          Accumulate@Array[MangoldtLambda, 1000]], Frame -> True,
          FrameLabel -> {x, ψ[x] - x}]


          enter image description here






          share|improve this answer











          $endgroup$













          • $begingroup$
            I'll tick this when it lets me! Appreciated.
            $endgroup$
            – Richard Burke-Ward
            10 hours ago
















          5












          $begingroup$

          There seems to be a duplicate use of the symbol x in your formulas.



          ChebyshevPsi[x_] := Sum[MangoldtLambda[y], {y, x}]
          Table[ChebyshevPsi[x], {x, 10}]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          You can also directly construct a list of these with Accumulate:



          Accumulate@Array[MangoldtLambda, 10]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          Plot the deviation of the Chebyshev $psi$ function from $x$:



          ListLinePlot[MapIndexed[{#2[[1]], #1 - #2[[1]]} &, 
          Accumulate@Array[MangoldtLambda, 1000]], Frame -> True,
          FrameLabel -> {x, ψ[x] - x}]


          enter image description here






          share|improve this answer











          $endgroup$













          • $begingroup$
            I'll tick this when it lets me! Appreciated.
            $endgroup$
            – Richard Burke-Ward
            10 hours ago














          5












          5








          5





          $begingroup$

          There seems to be a duplicate use of the symbol x in your formulas.



          ChebyshevPsi[x_] := Sum[MangoldtLambda[y], {y, x}]
          Table[ChebyshevPsi[x], {x, 10}]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          You can also directly construct a list of these with Accumulate:



          Accumulate@Array[MangoldtLambda, 10]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          Plot the deviation of the Chebyshev $psi$ function from $x$:



          ListLinePlot[MapIndexed[{#2[[1]], #1 - #2[[1]]} &, 
          Accumulate@Array[MangoldtLambda, 1000]], Frame -> True,
          FrameLabel -> {x, ψ[x] - x}]


          enter image description here






          share|improve this answer











          $endgroup$



          There seems to be a duplicate use of the symbol x in your formulas.



          ChebyshevPsi[x_] := Sum[MangoldtLambda[y], {y, x}]
          Table[ChebyshevPsi[x], {x, 10}]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          You can also directly construct a list of these with Accumulate:



          Accumulate@Array[MangoldtLambda, 10]



          {0, Log[2], Log[2] + Log[3], 2 Log[2] + Log[3],
          2 Log[2] + Log[3] + Log[5], 2 Log[2] + Log[3] + Log[5],
          2 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7],
          3 Log[2] + 2 Log[3] + Log[5] + Log[7]}




          Plot the deviation of the Chebyshev $psi$ function from $x$:



          ListLinePlot[MapIndexed[{#2[[1]], #1 - #2[[1]]} &, 
          Accumulate@Array[MangoldtLambda, 1000]], Frame -> True,
          FrameLabel -> {x, ψ[x] - x}]


          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 20 mins ago

























          answered 10 hours ago









          RomanRoman

          2,594717




          2,594717












          • $begingroup$
            I'll tick this when it lets me! Appreciated.
            $endgroup$
            – Richard Burke-Ward
            10 hours ago


















          • $begingroup$
            I'll tick this when it lets me! Appreciated.
            $endgroup$
            – Richard Burke-Ward
            10 hours ago
















          $begingroup$
          I'll tick this when it lets me! Appreciated.
          $endgroup$
          – Richard Burke-Ward
          10 hours ago




          $begingroup$
          I'll tick this when it lets me! Appreciated.
          $endgroup$
          – Richard Burke-Ward
          10 hours ago


















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