Problems with rounding giving too many digits












1












$begingroup$


My current code is:



round = .1;

f[x_] := x + 4 - Sqrt[3 x^2 - 5]

xx = Solve[f[x] == 0, Reals];

StringForm["x=`1`", 

If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round], 

"none"]]



x=5.800000000000001`




which i want to give me an output of "x = 5.8" instead.



Any advice would be appreciated.






formatting round







share|improve this question











$endgroup$












  • $begingroup$
    StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
    $endgroup$
    – Bob Hanlon
    4 hours ago






  • 1




    $begingroup$
    Could round exactly and then use N: N[Round[Max[xx[[All, 1, 2]]], 1/10]]
    $endgroup$
    – Daniel Lichtblau
    4 hours ago
















1












$begingroup$


My current code is:



round = .1;

f[x_] := x + 4 - Sqrt[3 x^2 - 5]

xx = Solve[f[x] == 0, Reals];

StringForm["x=`1`", 

If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round], 

"none"]]



x=5.800000000000001`




which i want to give me an output of "x = 5.8" instead.



Any advice would be appreciated.






formatting round







share|improve this question











$endgroup$












  • $begingroup$
    StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
    $endgroup$
    – Bob Hanlon
    4 hours ago






  • 1




    $begingroup$
    Could round exactly and then use N: N[Round[Max[xx[[All, 1, 2]]], 1/10]]
    $endgroup$
    – Daniel Lichtblau
    4 hours ago














1












1








1





$begingroup$


My current code is:



round = .1;

f[x_] := x + 4 - Sqrt[3 x^2 - 5]

xx = Solve[f[x] == 0, Reals];

StringForm["x=`1`", 

If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round], 

"none"]]



x=5.800000000000001`




which i want to give me an output of "x = 5.8" instead.



Any advice would be appreciated.






formatting round







share|improve this question











$endgroup$




My current code is:



round = .1;

f[x_] := x + 4 - Sqrt[3 x^2 - 5]

xx = Solve[f[x] == 0, Reals];

StringForm["x=`1`", 

If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round], 

"none"]]



x=5.800000000000001`




which i want to give me an output of "x = 5.8" instead.



Any advice would be appreciated.






formatting round




formatting round






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 3 hours ago









Alexey Popkov

38.5k4108263




38.5k4108263










asked 4 hours ago









WomblesWombles

584




584












  • $begingroup$
    StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
    $endgroup$
    – Bob Hanlon
    4 hours ago






  • 1




    $begingroup$
    Could round exactly and then use N: N[Round[Max[xx[[All, 1, 2]]], 1/10]]
    $endgroup$
    – Daniel Lichtblau
    4 hours ago


















  • $begingroup$
    StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
    $endgroup$
    – Bob Hanlon
    4 hours ago






  • 1




    $begingroup$
    Could round exactly and then use N: N[Round[Max[xx[[All, 1, 2]]], 1/10]]
    $endgroup$
    – Daniel Lichtblau
    4 hours ago
















$begingroup$
StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
4 hours ago




$begingroup$
StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
4 hours ago




1




1




$begingroup$
Could round exactly and then use N: N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
4 hours ago




$begingroup$
Could round exactly and then use N: N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
4 hours ago










3 Answers
3






active

oldest

votes


















3












$begingroup$

You could add a StandardForm wrapper:



StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]



x=5.8







share|improve this answer









$endgroup$













  • $begingroup$
    Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
    $endgroup$
    – Wombles
    4 hours ago



















3












$begingroup$

StringForm["x=`1`", If[Length[xx] >= 1, 

  DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2], 

  "none"]]



x = 5.8




Same result with NumberForm in place of DecimalForm.






share|improve this answer











$endgroup$













  • $begingroup$
    Thank you, this worked great
    $endgroup$
    – Wombles
    2 hours ago



















1












$begingroup$

StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]]



x = 5.8







share|improve this answer











$endgroup$













  • $begingroup$
    Just fixed a typo (was missing a right bracket (])).
    $endgroup$
    – mjw
    9 mins ago













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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

You could add a StandardForm wrapper:



StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]



x=5.8







share|improve this answer









$endgroup$













  • $begingroup$
    Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
    $endgroup$
    – Wombles
    4 hours ago
















3












$begingroup$

You could add a StandardForm wrapper:



StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]



x=5.8







share|improve this answer









$endgroup$













  • $begingroup$
    Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
    $endgroup$
    – Wombles
    4 hours ago














3












3








3





$begingroup$

You could add a StandardForm wrapper:



StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]



x=5.8







share|improve this answer









$endgroup$



You could add a StandardForm wrapper:



StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]



x=5.8








share|improve this answer












share|improve this answer



share|improve this answer










answered 4 hours ago









Carl WollCarl Woll

69.4k393179




69.4k393179












  • $begingroup$
    Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
    $endgroup$
    – Wombles
    4 hours ago


















  • $begingroup$
    Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
    $endgroup$
    – Wombles
    4 hours ago
















$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
4 hours ago




$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
4 hours ago











3












$begingroup$

StringForm["x=`1`", If[Length[xx] >= 1, 

  DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2], 

  "none"]]



x = 5.8




Same result with NumberForm in place of DecimalForm.






share|improve this answer











$endgroup$













  • $begingroup$
    Thank you, this worked great
    $endgroup$
    – Wombles
    2 hours ago
















3












$begingroup$

StringForm["x=`1`", If[Length[xx] >= 1, 

  DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2], 

  "none"]]



x = 5.8




Same result with NumberForm in place of DecimalForm.






share|improve this answer











$endgroup$













  • $begingroup$
    Thank you, this worked great
    $endgroup$
    – Wombles
    2 hours ago














3












3








3





$begingroup$

StringForm["x=`1`", If[Length[xx] >= 1, 

  DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2], 

  "none"]]



x = 5.8




Same result with NumberForm in place of DecimalForm.






share|improve this answer











$endgroup$



StringForm["x=`1`", If[Length[xx] >= 1, 

  DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2], 

  "none"]]



x = 5.8




Same result with NumberForm in place of DecimalForm.







share|improve this answer














share|improve this answer



share|improve this answer








edited 4 hours ago

























answered 4 hours ago









kglrkglr

187k10203421




187k10203421












  • $begingroup$
    Thank you, this worked great
    $endgroup$
    – Wombles
    2 hours ago


















  • $begingroup$
    Thank you, this worked great
    $endgroup$
    – Wombles
    2 hours ago
















$begingroup$
Thank you, this worked great
$endgroup$
– Wombles
2 hours ago




$begingroup$
Thank you, this worked great
$endgroup$
– Wombles
2 hours ago











1












$begingroup$

StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]]



x = 5.8







share|improve this answer











$endgroup$













  • $begingroup$
    Just fixed a typo (was missing a right bracket (])).
    $endgroup$
    – mjw
    9 mins ago


















1












$begingroup$

StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]]



x = 5.8







share|improve this answer











$endgroup$













  • $begingroup$
    Just fixed a typo (was missing a right bracket (])).
    $endgroup$
    – mjw
    9 mins ago
















1












1








1





$begingroup$

StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]]



x = 5.8







share|improve this answer











$endgroup$



StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]]



x = 5.8








share|improve this answer














share|improve this answer



share|improve this answer








edited 11 mins ago

























answered 4 hours ago









mjwmjw

5328




5328












  • $begingroup$
    Just fixed a typo (was missing a right bracket (])).
    $endgroup$
    – mjw
    9 mins ago




















  • $begingroup$
    Just fixed a typo (was missing a right bracket (])).
    $endgroup$
    – mjw
    9 mins ago


















$begingroup$
Just fixed a typo (was missing a right bracket (])).
$endgroup$
– mjw
9 mins ago






$begingroup$
Just fixed a typo (was missing a right bracket (])).
$endgroup$
– mjw
9 mins ago




















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