Why do we call complex numbers “numbers” but we don’t consider 2 vectors numbers?
$begingroup$
We refer to complex numbers as numbers. However we refer to vectors as arrays of numbers. There doesn’t seem to be anything that makes one more numeric than the other. Is this just a quirk of history and naming or is there something more fundamental?
matrices complex-numbers philosophy
$endgroup$
|
show 1 more comment
$begingroup$
We refer to complex numbers as numbers. However we refer to vectors as arrays of numbers. There doesn’t seem to be anything that makes one more numeric than the other. Is this just a quirk of history and naming or is there something more fundamental?
matrices complex-numbers philosophy
$endgroup$
6
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
4 hours ago
4
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
4 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
3 hours ago
5
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
3 hours ago
2
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
3 hours ago
|
show 1 more comment
$begingroup$
We refer to complex numbers as numbers. However we refer to vectors as arrays of numbers. There doesn’t seem to be anything that makes one more numeric than the other. Is this just a quirk of history and naming or is there something more fundamental?
matrices complex-numbers philosophy
$endgroup$
We refer to complex numbers as numbers. However we refer to vectors as arrays of numbers. There doesn’t seem to be anything that makes one more numeric than the other. Is this just a quirk of history and naming or is there something more fundamental?
matrices complex-numbers philosophy
matrices complex-numbers philosophy
edited 3 hours ago
Bernard
122k740116
122k740116
asked 4 hours ago
Q the PlatypusQ the Platypus
2,799933
2,799933
6
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
4 hours ago
4
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
4 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
3 hours ago
5
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
3 hours ago
2
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
3 hours ago
|
show 1 more comment
6
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
4 hours ago
4
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
4 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
3 hours ago
5
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
3 hours ago
2
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
3 hours ago
6
6
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
4 hours ago
$begingroup$
Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
$endgroup$
– Nate Eldredge
4 hours ago
4
4
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
4 hours ago
$begingroup$
What's a "number" anyway?
$endgroup$
– Asaf Karagila♦
4 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
3 hours ago
$begingroup$
I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
$endgroup$
– Q the Platypus
3 hours ago
5
5
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
3 hours ago
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
3 hours ago
2
2
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
3 hours ago
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
3 hours ago
|
show 1 more comment
4 Answers
4
active
oldest
votes
$begingroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number systems, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
$endgroup$
add a comment |
$begingroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
$endgroup$
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
3 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
3 hours ago
$begingroup$
You can also add and multiply matrices, but I don't think I've ever heard anyone call a matrix a "number".
$endgroup$
– Hong Ooi
45 mins ago
$begingroup$
@user247327: It's worth pointing out that IEEE 754 floating point numbers are non-associative, closed under division, non-reflexive (i.e. they violate $forall a:a = a$), non-substitutable (i.e. numbers which are "equal" cannot always be substituted for one another in expressions or equations), and also the most widely used approximation of the reals in practical computing applications.
$endgroup$
– Kevin
45 mins ago
add a comment |
$begingroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
$endgroup$
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
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– Q the Platypus
4 hours ago
$begingroup$
What is a property of either complex numbers or 2-vectors that the other does not have, other than representation?
$endgroup$
– Brad Thomas
1 hour ago
add a comment |
$begingroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
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2
$begingroup$
People do think of complex numbers as points on the number plane.
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– Q the Platypus
3 hours ago
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
3 hours ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number systems, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
$endgroup$
add a comment |
$begingroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number systems, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
$endgroup$
add a comment |
$begingroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number systems, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
$endgroup$
They're called "numbers" for historical reasons, since the motivation in the development of the complex numbers was solving polynomial equations. They were viewed as natural extensions of the real numbers. It's somehow quite natural and satisfying to say "every polynomial equation can be solved by some (complex) number". Is it more natural to regard $i$ as being a number which, when squared, is equal to $-1$, or is it more natural to regard $i$ as being some non-number thingamajig which when squared is equal to $-1$? Clearly the former.
"Higher" number systems, like quaternions, aren't really called numbers very often, for the simple fact that they are not as intimately connected with number theory and analysis in the same way that complex numbers are.
Beyond these social conventions, I can't see any other reason. The word "number" doesn't have a strict or absolute definition in pure mathematics. $mathbb{N}$, $mathbb{Z}$, $mathbb{Q}$, $mathbb{R}$ and $mathbb{C}$ are technically just sets with a certain algebraic structure.
I partially disagree with the other answers which claim that complex numbers are numbers simply by virtue of the fact that you can add and multiply them. Well, if that's the rationale, is every ring also a set of numbers?
edited 22 mins ago
answered 3 hours ago
MathematicsStudent1122MathematicsStudent1122
8,74622467
8,74622467
add a comment |
add a comment |
$begingroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
$endgroup$
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
3 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
3 hours ago
$begingroup$
You can also add and multiply matrices, but I don't think I've ever heard anyone call a matrix a "number".
$endgroup$
– Hong Ooi
45 mins ago
$begingroup$
@user247327: It's worth pointing out that IEEE 754 floating point numbers are non-associative, closed under division, non-reflexive (i.e. they violate $forall a:a = a$), non-substitutable (i.e. numbers which are "equal" cannot always be substituted for one another in expressions or equations), and also the most widely used approximation of the reals in practical computing applications.
$endgroup$
– Kevin
45 mins ago
add a comment |
$begingroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
$endgroup$
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
3 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
3 hours ago
$begingroup$
You can also add and multiply matrices, but I don't think I've ever heard anyone call a matrix a "number".
$endgroup$
– Hong Ooi
45 mins ago
$begingroup$
@user247327: It's worth pointing out that IEEE 754 floating point numbers are non-associative, closed under division, non-reflexive (i.e. they violate $forall a:a = a$), non-substitutable (i.e. numbers which are "equal" cannot always be substituted for one another in expressions or equations), and also the most widely used approximation of the reals in practical computing applications.
$endgroup$
– Kevin
45 mins ago
add a comment |
$begingroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
$endgroup$
The two fundamental operations for numbers are "addition" and "multiplication" which obey very nice "laws" of arithmetic. Taking powers is also important. You can do all of those things with complex numbers. You can add two vectors but the "dot" product of two vectors is not a vector and the "cross" product of two vectors does not satisfy the "nice laws". Neither the dot product nor the cross product of vectors can be used to define powers.
answered 4 hours ago
user247327user247327
11.3k1515
11.3k1515
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
3 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
3 hours ago
$begingroup$
You can also add and multiply matrices, but I don't think I've ever heard anyone call a matrix a "number".
$endgroup$
– Hong Ooi
45 mins ago
$begingroup$
@user247327: It's worth pointing out that IEEE 754 floating point numbers are non-associative, closed under division, non-reflexive (i.e. they violate $forall a:a = a$), non-substitutable (i.e. numbers which are "equal" cannot always be substituted for one another in expressions or equations), and also the most widely used approximation of the reals in practical computing applications.
$endgroup$
– Kevin
45 mins ago
add a comment |
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
3 hours ago
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
3 hours ago
$begingroup$
You can also add and multiply matrices, but I don't think I've ever heard anyone call a matrix a "number".
$endgroup$
– Hong Ooi
45 mins ago
$begingroup$
@user247327: It's worth pointing out that IEEE 754 floating point numbers are non-associative, closed under division, non-reflexive (i.e. they violate $forall a:a = a$), non-substitutable (i.e. numbers which are "equal" cannot always be substituted for one another in expressions or equations), and also the most widely used approximation of the reals in practical computing applications.
$endgroup$
– Kevin
45 mins ago
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
3 hours ago
$begingroup$
So Quaternions which have Non commutativity multiplication would also be considered as non numbers?
$endgroup$
– Q the Platypus
3 hours ago
3
3
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
3 hours ago
$begingroup$
That's a good point- though I have never liked quaternions! Multiplication of quaternions is not commutative but it is associative which allows powers. That's what I was really thinking of.
$endgroup$
– user247327
3 hours ago
$begingroup$
You can also add and multiply matrices, but I don't think I've ever heard anyone call a matrix a "number".
$endgroup$
– Hong Ooi
45 mins ago
$begingroup$
You can also add and multiply matrices, but I don't think I've ever heard anyone call a matrix a "number".
$endgroup$
– Hong Ooi
45 mins ago
$begingroup$
@user247327: It's worth pointing out that IEEE 754 floating point numbers are non-associative, closed under division, non-reflexive (i.e. they violate $forall a:a = a$), non-substitutable (i.e. numbers which are "equal" cannot always be substituted for one another in expressions or equations), and also the most widely used approximation of the reals in practical computing applications.
$endgroup$
– Kevin
45 mins ago
$begingroup$
@user247327: It's worth pointing out that IEEE 754 floating point numbers are non-associative, closed under division, non-reflexive (i.e. they violate $forall a:a = a$), non-substitutable (i.e. numbers which are "equal" cannot always be substituted for one another in expressions or equations), and also the most widely used approximation of the reals in practical computing applications.
$endgroup$
– Kevin
45 mins ago
add a comment |
$begingroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
$endgroup$
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
4 hours ago
$begingroup$
What is a property of either complex numbers or 2-vectors that the other does not have, other than representation?
$endgroup$
– Brad Thomas
1 hour ago
add a comment |
$begingroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
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2
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I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
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– Q the Platypus
4 hours ago
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What is a property of either complex numbers or 2-vectors that the other does not have, other than representation?
$endgroup$
– Brad Thomas
1 hour ago
add a comment |
$begingroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
$endgroup$
Complex numbers do not have the same properties as vectors but they have similar properties (see dot product). We can represent complex numbers as vectors, but that is just a representation.
Complex numbers are also called imaginary numbers because the first appearance of them was quite confusing. They appeared in the solution of the cubic equation for the case of three distinct real roots. It took quite a time until people understood that they could calculate with complex numbers like with normal numbers but will some additional rules e.g. $i^2=-1$.
Complex numbers also do not have a comparison operator like $<$ or $>$. For example, assume
$i<0$ then $icdot i > 0 implies -1>0$ which is wrong. $i=0$ makes no sense. And $i>0$ then $icdot i >0 implies -1 >0$ which is wrong.
Hence, the name makes sense as these numbers have some imaginary or complex behavior which normal numbers do not show.
answered 4 hours ago
MachineLearnerMachineLearner
5077
5077
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
4 hours ago
$begingroup$
What is a property of either complex numbers or 2-vectors that the other does not have, other than representation?
$endgroup$
– Brad Thomas
1 hour ago
add a comment |
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
4 hours ago
$begingroup$
What is a property of either complex numbers or 2-vectors that the other does not have, other than representation?
$endgroup$
– Brad Thomas
1 hour ago
2
2
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
4 hours ago
$begingroup$
I’m not asking why complex numbers are call complex. I am asking why they are called numbers. BTW they are not called complex numbers because they are difficult but because complex can mean “made up of parts” like a “shopping complex”.
$endgroup$
– Q the Platypus
4 hours ago
$begingroup$
What is a property of either complex numbers or 2-vectors that the other does not have, other than representation?
$endgroup$
– Brad Thomas
1 hour ago
$begingroup$
What is a property of either complex numbers or 2-vectors that the other does not have, other than representation?
$endgroup$
– Brad Thomas
1 hour ago
add a comment |
$begingroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
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2
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People do think of complex numbers as points on the number plane.
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– Q the Platypus
3 hours ago
1
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Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
3 hours ago
add a comment |
$begingroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
$endgroup$
2
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
3 hours ago
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
3 hours ago
add a comment |
$begingroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
$endgroup$
Numbers appeared first when we started to count things. $1$ tree, $2$ trees, $3$ trees, and so forth. That make up the set of non-zero natural numbers: $mathbb{N}$. Afterwards, people started to "count backwards" to get $mathbb{Z}$ (I'm just kidding, you can do some research on how negative numbers appeared historically). With the urge to divide things without remainders, the set of rational numbers $mathbb{Q}$ made its way to the world. A certain idea of geometric continuity gives us $mathbb{R}$. Finally we want all equations to have a root, that's how $mathbb{C}$ comes into play.
I guess what is considered "numbers" is rather a social question. The use of $mathbb{C}$
in physics and its $2$-D representation must have given a good intuition for a large set of people to accept it's intuitive enough to be considered "numbers".
I think it's not that natural to think of $mathbb{C}$ as a $mathbb{R}$-vector space of dimension $2$, not more natural than to think of $mathbb{R}$ as an infinite-dimensional $mathbb{Q}$-vector space, nor of $mathbb{Q}$ as a non-infinitely-generated $mathbb{Z}$-module.
edited 3 hours ago
answered 3 hours ago
LeaningLeaning
1,221718
1,221718
2
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
3 hours ago
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
3 hours ago
add a comment |
2
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
3 hours ago
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
3 hours ago
2
2
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
3 hours ago
$begingroup$
People do think of complex numbers as points on the number plane.
$endgroup$
– Q the Platypus
3 hours ago
1
1
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
3 hours ago
$begingroup$
Thank you. I'm sorry, that final part is just a personal opinion. edited.
$endgroup$
– Leaning
3 hours ago
add a comment |
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6
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Usually, the difference would be whether you're in a context where complex multiplication would be interesting. It's kind of like the question: is $mathbb{Z}$ a group or a ring? It depends on which operations are of interest for the question you're studying.
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– Nate Eldredge
4 hours ago
4
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What's a "number" anyway?
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– Asaf Karagila♦
4 hours ago
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I would say that $mathbb{Z}$ is not a ring or a group as you have to have an operator in order to be a magma. However that would be over pedantic so I get where you are coming from.
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– Q the Platypus
3 hours ago
5
$begingroup$
@QthePlatypus: No, that's exactly the point. The question of whether the set $mathbb{R}^2$ of pairs of real numbers should be considered as the set of complex numbers, or as a set of vectors, depends on which operations you wish to equip that set with.
$endgroup$
– Nate Eldredge
3 hours ago
2
$begingroup$
I think the correct question were: is there a rigorous definition of the object "number" (without further characteristics such as "integer", "real", "complex" etc.)?
$endgroup$
– user
3 hours ago