How to copy the rest of lines of a file to another file
I have the string xyz which is a line in file1.txt, I want to copy all the lines after xyz in file1.txt to a new file file2.txt. How can I achieve this?
I know about cat command. But how to specify the starting line?
files grep cat file-copy file-transfer
asked 2 hours ago
user9371654user9371654
30617
add a comment |
I have the string xyz which is a line in file1.txt, I want to copy all the lines after xyz in file1.txt to a new file file2.txt. How can I achieve this?
I know about cat command. But how to specify the starting line?
files grep cat file-copy file-transfer
asked 2 hours ago
user9371654user9371654
30617
2
Do you want to include thatxyzline or exclude it from being copied ? Also, what happens if you have multiple lines matchingxyz?
– don_crissti
1 hour ago
2
Possible duplicate of How to print all lines after a match up to the end of the file?
– Kusalananda
1 hour ago
add a comment |
I have the string xyz which is a line in file1.txt, I want to copy all the lines after xyz in file1.txt to a new file file2.txt. How can I achieve this?
I know about cat command. But how to specify the starting line?
files grep cat file-copy file-transfer
asked 2 hours ago
user9371654user9371654
30617
I have the string xyz which is a line in file1.txt, I want to copy all the lines after xyz in file1.txt to a new file file2.txt. How can I achieve this?
I know about cat command. But how to specify the starting line?
files grep cat file-copy file-transfer
files grep cat file-copy file-transfer
asked 2 hours ago
user9371654user9371654
30617
asked 2 hours ago
user9371654user9371654
30617
asked 2 hours ago
user9371654user9371654
30617
asked 2 hours ago
user9371654user9371654
30617
asked 2 hours ago
user9371654user9371654
30617
30617
2
Do you want to include thatxyzline or exclude it from being copied ? Also, what happens if you have multiple lines matchingxyz?
– don_crissti
1 hour ago
2
Possible duplicate of How to print all lines after a match up to the end of the file?
– Kusalananda
1 hour ago
add a comment |
2
Do you want to include thatxyzline or exclude it from being copied ? Also, what happens if you have multiple lines matchingxyz?
– don_crissti
1 hour ago
2
Possible duplicate of How to print all lines after a match up to the end of the file?
– Kusalananda
1 hour ago
2
2
Do you want to include that
xyz line or exclude it from being copied ? Also, what happens if you have multiple lines matching xyz ?– don_crissti
1 hour ago
Do you want to include that
xyz line or exclude it from being copied ? Also, what happens if you have multiple lines matching xyz ?– don_crissti
1 hour ago
2
2
Possible duplicate of How to print all lines after a match up to the end of the file?
– Kusalananda
1 hour ago
Possible duplicate of How to print all lines after a match up to the end of the file?
– Kusalananda
1 hour ago
add a comment |
4 Answers
4
active
oldest
votes
Using GNU sed
To copy all lines after xyz, try:
sed '0,/xyz/d' file1.txt >file2.txt
1,/xyz/ specifies a range of lines starting with the first and ending with the first occurrence of a line matching xyz. d tells sed to delete those lines.
Note: For BSD/MacOS sed, one can use sed '1,/xyz/d' file1.txt >file2.txt but this only works if the first appearance of xyz is in the second line or later. (Hat tip: kusalananda.)
Another approach, as suggested by don_crissti, should work for all sed:
{ printf %s\n; cat file1.txt; } | sed '1,/xyz/d' >file2.txt
Example
Consider this test file:
$ cat file1.txt
a
b
xyz
c
d
Run our command:
$ sed '1,/xyz/d' file1.txt >file2.txt
$ cat file2.txt
c
d
Using awk
The same logic can used with awk:
awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt
NR==1,/xyz/{next} tells awk to skip over all lines from the first (NR==1) to the first line matching the regex xyz. 1 tells awk to print any remaining lines.
answered 1 hour ago
John1024John1024
47.5k5110125
@don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
– John1024
1 hour ago
@John1024 Whatsedare you using there?
– Kusalananda
32 mins ago
@Kusalanandased --versionreturns(GNU sed) 4.4.
– John1024
30 mins ago
@don_crissti Very good. Thanks! I added theprintfsolution to the answer.
– John1024
17 mins ago
add a comment |
With ed:
ed -s file.txt <<< $'/xyz/+1,$w file2.txt'
This sends one (ranged) command to ed: from the line after (+1) the one containing xyz until the end of the file ($), write those lines to file2.txt.
answered 57 mins ago
Jeff SchallerJeff Schaller
43.2k1159138
add a comment |
$ sed -n '/xyz/,$p' file.txt > file2.txt
With -n we prevent sed to print every line. With $ means end of file end p stands for print line. So /xyz/$p means: If a line matches xyz print it until the end of the file.
answered 1 hour ago
finswimmerfinswimmer
72917
This would also print the line matchingxyz, not from the line after.
– Kusalananda
1 hour ago
add a comment |
There is also csplit :
csplit -s file1.txt %xyz%1
answered 1 hour ago
ctac_ctac_
1,4221210
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Using GNU sed
To copy all lines after xyz, try:
sed '0,/xyz/d' file1.txt >file2.txt
1,/xyz/ specifies a range of lines starting with the first and ending with the first occurrence of a line matching xyz. d tells sed to delete those lines.
Note: For BSD/MacOS sed, one can use sed '1,/xyz/d' file1.txt >file2.txt but this only works if the first appearance of xyz is in the second line or later. (Hat tip: kusalananda.)
Another approach, as suggested by don_crissti, should work for all sed:
{ printf %s\n; cat file1.txt; } | sed '1,/xyz/d' >file2.txt
Example
Consider this test file:
$ cat file1.txt
a
b
xyz
c
d
Run our command:
$ sed '1,/xyz/d' file1.txt >file2.txt
$ cat file2.txt
c
d
Using awk
The same logic can used with awk:
awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt
NR==1,/xyz/{next} tells awk to skip over all lines from the first (NR==1) to the first line matching the regex xyz. 1 tells awk to print any remaining lines.
answered 1 hour ago
John1024John1024
47.5k5110125
@don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
– John1024
1 hour ago
@John1024 Whatsedare you using there?
– Kusalananda
32 mins ago
@Kusalanandased --versionreturns(GNU sed) 4.4.
– John1024
30 mins ago
@don_crissti Very good. Thanks! I added theprintfsolution to the answer.
– John1024
17 mins ago
add a comment |
Using GNU sed
To copy all lines after xyz, try:
sed '0,/xyz/d' file1.txt >file2.txt
1,/xyz/ specifies a range of lines starting with the first and ending with the first occurrence of a line matching xyz. d tells sed to delete those lines.
Note: For BSD/MacOS sed, one can use sed '1,/xyz/d' file1.txt >file2.txt but this only works if the first appearance of xyz is in the second line or later. (Hat tip: kusalananda.)
Another approach, as suggested by don_crissti, should work for all sed:
{ printf %s\n; cat file1.txt; } | sed '1,/xyz/d' >file2.txt
Example
Consider this test file:
$ cat file1.txt
a
b
xyz
c
d
Run our command:
$ sed '1,/xyz/d' file1.txt >file2.txt
$ cat file2.txt
c
d
Using awk
The same logic can used with awk:
awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt
NR==1,/xyz/{next} tells awk to skip over all lines from the first (NR==1) to the first line matching the regex xyz. 1 tells awk to print any remaining lines.
answered 1 hour ago
John1024John1024
47.5k5110125
@don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
– John1024
1 hour ago
@John1024 Whatsedare you using there?
– Kusalananda
32 mins ago
@Kusalanandased --versionreturns(GNU sed) 4.4.
– John1024
30 mins ago
@don_crissti Very good. Thanks! I added theprintfsolution to the answer.
– John1024
17 mins ago
add a comment |
Using GNU sed
To copy all lines after xyz, try:
sed '0,/xyz/d' file1.txt >file2.txt
1,/xyz/ specifies a range of lines starting with the first and ending with the first occurrence of a line matching xyz. d tells sed to delete those lines.
Note: For BSD/MacOS sed, one can use sed '1,/xyz/d' file1.txt >file2.txt but this only works if the first appearance of xyz is in the second line or later. (Hat tip: kusalananda.)
Another approach, as suggested by don_crissti, should work for all sed:
{ printf %s\n; cat file1.txt; } | sed '1,/xyz/d' >file2.txt
Example
Consider this test file:
$ cat file1.txt
a
b
xyz
c
d
Run our command:
$ sed '1,/xyz/d' file1.txt >file2.txt
$ cat file2.txt
c
d
Using awk
The same logic can used with awk:
awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt
NR==1,/xyz/{next} tells awk to skip over all lines from the first (NR==1) to the first line matching the regex xyz. 1 tells awk to print any remaining lines.
answered 1 hour ago
John1024John1024
47.5k5110125
Using GNU sed
To copy all lines after xyz, try:
sed '0,/xyz/d' file1.txt >file2.txt
1,/xyz/ specifies a range of lines starting with the first and ending with the first occurrence of a line matching xyz. d tells sed to delete those lines.
Note: For BSD/MacOS sed, one can use sed '1,/xyz/d' file1.txt >file2.txt but this only works if the first appearance of xyz is in the second line or later. (Hat tip: kusalananda.)
Another approach, as suggested by don_crissti, should work for all sed:
{ printf %s\n; cat file1.txt; } | sed '1,/xyz/d' >file2.txt
Example
Consider this test file:
$ cat file1.txt
a
b
xyz
c
d
Run our command:
$ sed '1,/xyz/d' file1.txt >file2.txt
$ cat file2.txt
c
d
Using awk
The same logic can used with awk:
awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt
NR==1,/xyz/{next} tells awk to skip over all lines from the first (NR==1) to the first line matching the regex xyz. 1 tells awk to print any remaining lines.
answered 1 hour ago
John1024John1024
47.5k5110125
edited 17 mins ago
answered 1 hour ago
John1024John1024
47.5k5110125
answered 1 hour ago
John1024John1024
47.5k5110125
answered 1 hour ago
John1024John1024
47.5k5110125
47.5k5110125
@don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
– John1024
1 hour ago
@John1024 Whatsedare you using there?
– Kusalananda
32 mins ago
@Kusalanandased --versionreturns(GNU sed) 4.4.
– John1024
30 mins ago
@don_crissti Very good. Thanks! I added theprintfsolution to the answer.
– John1024
17 mins ago
add a comment |
@don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
– John1024
1 hour ago
@John1024 Whatsedare you using there?
– Kusalananda
32 mins ago
@Kusalanandased --versionreturns(GNU sed) 4.4.
– John1024
30 mins ago
@don_crissti Very good. Thanks! I added theprintfsolution to the answer.
– John1024
17 mins ago
@don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
– John1024
1 hour ago
@don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
– John1024
1 hour ago
@John1024 What
sed are you using there?– Kusalananda
32 mins ago
@John1024 What
sed are you using there?– Kusalananda
32 mins ago
@Kusalananda
sed --version returns (GNU sed) 4.4.– John1024
30 mins ago
@Kusalananda
sed --version returns (GNU sed) 4.4.– John1024
30 mins ago
@don_crissti Very good. Thanks! I added the
printf solution to the answer.– John1024
17 mins ago
@don_crissti Very good. Thanks! I added the
printf solution to the answer.– John1024
17 mins ago
add a comment |
With ed:
ed -s file.txt <<< $'/xyz/+1,$w file2.txt'
This sends one (ranged) command to ed: from the line after (+1) the one containing xyz until the end of the file ($), write those lines to file2.txt.
answered 57 mins ago
Jeff SchallerJeff Schaller
43.2k1159138
add a comment |
With ed:
ed -s file.txt <<< $'/xyz/+1,$w file2.txt'
This sends one (ranged) command to ed: from the line after (+1) the one containing xyz until the end of the file ($), write those lines to file2.txt.
answered 57 mins ago
Jeff SchallerJeff Schaller
43.2k1159138
add a comment |
With ed:
ed -s file.txt <<< $'/xyz/+1,$w file2.txt'
This sends one (ranged) command to ed: from the line after (+1) the one containing xyz until the end of the file ($), write those lines to file2.txt.
answered 57 mins ago
Jeff SchallerJeff Schaller
43.2k1159138
With ed:
ed -s file.txt <<< $'/xyz/+1,$w file2.txt'
This sends one (ranged) command to ed: from the line after (+1) the one containing xyz until the end of the file ($), write those lines to file2.txt.
answered 57 mins ago
Jeff SchallerJeff Schaller
43.2k1159138
answered 57 mins ago
Jeff SchallerJeff Schaller
43.2k1159138
answered 57 mins ago
Jeff SchallerJeff Schaller
43.2k1159138
answered 57 mins ago
Jeff SchallerJeff Schaller
43.2k1159138
43.2k1159138
add a comment |
add a comment |
$ sed -n '/xyz/,$p' file.txt > file2.txt
With -n we prevent sed to print every line. With $ means end of file end p stands for print line. So /xyz/$p means: If a line matches xyz print it until the end of the file.
answered 1 hour ago
finswimmerfinswimmer
72917
This would also print the line matchingxyz, not from the line after.
– Kusalananda
1 hour ago
add a comment |
$ sed -n '/xyz/,$p' file.txt > file2.txt
With -n we prevent sed to print every line. With $ means end of file end p stands for print line. So /xyz/$p means: If a line matches xyz print it until the end of the file.
answered 1 hour ago
finswimmerfinswimmer
72917
This would also print the line matchingxyz, not from the line after.
– Kusalananda
1 hour ago
add a comment |
$ sed -n '/xyz/,$p' file.txt > file2.txt
With -n we prevent sed to print every line. With $ means end of file end p stands for print line. So /xyz/$p means: If a line matches xyz print it until the end of the file.
answered 1 hour ago
finswimmerfinswimmer
72917
$ sed -n '/xyz/,$p' file.txt > file2.txt
With -n we prevent sed to print every line. With $ means end of file end p stands for print line. So /xyz/$p means: If a line matches xyz print it until the end of the file.
answered 1 hour ago
finswimmerfinswimmer
72917
answered 1 hour ago
finswimmerfinswimmer
72917
answered 1 hour ago
finswimmerfinswimmer
72917
answered 1 hour ago
finswimmerfinswimmer
72917
72917
This would also print the line matchingxyz, not from the line after.
– Kusalananda
1 hour ago
add a comment |
This would also print the line matchingxyz, not from the line after.
– Kusalananda
1 hour ago
This would also print the line matching
xyz, not from the line after.– Kusalananda
1 hour ago
This would also print the line matching
xyz, not from the line after.– Kusalananda
1 hour ago
add a comment |
There is also csplit :
csplit -s file1.txt %xyz%1
answered 1 hour ago
ctac_ctac_
1,4221210
add a comment |
There is also csplit :
csplit -s file1.txt %xyz%1
answered 1 hour ago
ctac_ctac_
1,4221210
add a comment |
There is also csplit :
csplit -s file1.txt %xyz%1
answered 1 hour ago
ctac_ctac_
1,4221210
There is also csplit :
csplit -s file1.txt %xyz%1
answered 1 hour ago
ctac_ctac_
1,4221210
answered 1 hour ago
ctac_ctac_
1,4221210
answered 1 hour ago
ctac_ctac_
1,4221210
answered 1 hour ago
ctac_ctac_
1,4221210
1,4221210
add a comment |
add a comment |
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2
Do you want to include that
xyzline or exclude it from being copied ? Also, what happens if you have multiple lines matchingxyz?– don_crissti
1 hour ago
2
Possible duplicate of How to print all lines after a match up to the end of the file?
– Kusalananda
1 hour ago