bash function without arguments












0















I am analyzing the following script (init script for ptpd2 deamon):



#!/bin/sh
#
# Start ptpd2
#

case "$1" in
start)
printf "Starting ptpd2: "
start-stop-daemon -S -q -x /usr/sbin/ptpd2 -- -g -i eth0 -s
if [ $? != 0 ]; then
echo "FAILED"
exit 1
else
echo "OK"
fi
;;
stop)
printf "Stopping ptpd2: "
start-stop-daemon -K -q -x /usr/sbin/ptpd2
echo "OK"
;;
restart|reload)
;;
*)
echo "Usage: $0 {start|stop|restart}"
exit 1
esac

exit $?


What does start), stop) mean? What kind of constraction is this? A function without arguments maybe?









share























  • part of the case structure, started with case and ending at the esac (case backwards) line. It controls execution by the "$1" ...

    – guiverc
    just now
















0















I am analyzing the following script (init script for ptpd2 deamon):



#!/bin/sh
#
# Start ptpd2
#

case "$1" in
start)
printf "Starting ptpd2: "
start-stop-daemon -S -q -x /usr/sbin/ptpd2 -- -g -i eth0 -s
if [ $? != 0 ]; then
echo "FAILED"
exit 1
else
echo "OK"
fi
;;
stop)
printf "Stopping ptpd2: "
start-stop-daemon -K -q -x /usr/sbin/ptpd2
echo "OK"
;;
restart|reload)
;;
*)
echo "Usage: $0 {start|stop|restart}"
exit 1
esac

exit $?


What does start), stop) mean? What kind of constraction is this? A function without arguments maybe?









share























  • part of the case structure, started with case and ending at the esac (case backwards) line. It controls execution by the "$1" ...

    – guiverc
    just now














0












0








0








I am analyzing the following script (init script for ptpd2 deamon):



#!/bin/sh
#
# Start ptpd2
#

case "$1" in
start)
printf "Starting ptpd2: "
start-stop-daemon -S -q -x /usr/sbin/ptpd2 -- -g -i eth0 -s
if [ $? != 0 ]; then
echo "FAILED"
exit 1
else
echo "OK"
fi
;;
stop)
printf "Stopping ptpd2: "
start-stop-daemon -K -q -x /usr/sbin/ptpd2
echo "OK"
;;
restart|reload)
;;
*)
echo "Usage: $0 {start|stop|restart}"
exit 1
esac

exit $?


What does start), stop) mean? What kind of constraction is this? A function without arguments maybe?









share














I am analyzing the following script (init script for ptpd2 deamon):



#!/bin/sh
#
# Start ptpd2
#

case "$1" in
start)
printf "Starting ptpd2: "
start-stop-daemon -S -q -x /usr/sbin/ptpd2 -- -g -i eth0 -s
if [ $? != 0 ]; then
echo "FAILED"
exit 1
else
echo "OK"
fi
;;
stop)
printf "Stopping ptpd2: "
start-stop-daemon -K -q -x /usr/sbin/ptpd2
echo "OK"
;;
restart|reload)
;;
*)
echo "Usage: $0 {start|stop|restart}"
exit 1
esac

exit $?


What does start), stop) mean? What kind of constraction is this? A function without arguments maybe?







bash





share












share










share



share










asked 2 mins ago









AndyAndy

11




11













  • part of the case structure, started with case and ending at the esac (case backwards) line. It controls execution by the "$1" ...

    – guiverc
    just now



















  • part of the case structure, started with case and ending at the esac (case backwards) line. It controls execution by the "$1" ...

    – guiverc
    just now

















part of the case structure, started with case and ending at the esac (case backwards) line. It controls execution by the "$1" ...

– guiverc
just now





part of the case structure, started with case and ending at the esac (case backwards) line. It controls execution by the "$1" ...

– guiverc
just now










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