Double integral with logarithms [on hold]
$begingroup$
How to solve this integral:
$$Jequiv int_{0}^{1}{int_{0}^{1}{frac{ln x-ln y}{x-y}}}dxdy$$
I've tried it for polylogarithmic transformations, but I can not get the result, which I think should be $$frac{{{pi }^{2}}}{3}.$$
Thanks!.
integration
New contributor
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put on hold as off-topic by YCor, user44191, Pace Nielsen, Gerald Edgar, Piotr Hajlasz 5 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "MathOverflow is for mathematicians to ask each other questions about their research. See Math.StackExchange to ask general questions in mathematics." – Pace Nielsen, Gerald Edgar, Piotr Hajlasz
If this question can be reworded to fit the rules in the help center, please edit the question.
|
show 2 more comments
$begingroup$
How to solve this integral:
$$Jequiv int_{0}^{1}{int_{0}^{1}{frac{ln x-ln y}{x-y}}}dxdy$$
I've tried it for polylogarithmic transformations, but I can not get the result, which I think should be $$frac{{{pi }^{2}}}{3}.$$
Thanks!.
integration
New contributor
$endgroup$
put on hold as off-topic by YCor, user44191, Pace Nielsen, Gerald Edgar, Piotr Hajlasz 5 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "MathOverflow is for mathematicians to ask each other questions about their research. See Math.StackExchange to ask general questions in mathematics." – Pace Nielsen, Gerald Edgar, Piotr Hajlasz
If this question can be reworded to fit the rules in the help center, please edit the question.
4
$begingroup$
MSE is a right place for such type questions. Both Maple and Mathematica confirm $ frac{pi ^2}{3}$.
$endgroup$
– user64494
11 hours ago
7
$begingroup$
I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
$endgroup$
– RP_
10 hours ago
3
$begingroup$
@user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
$endgroup$
– Fedor Petrov
8 hours ago
2
$begingroup$
@user64494 being the author of several papers devoted to exact closed-form integration, I feel so old now.
$endgroup$
– Fedor Petrov
5 hours ago
1
$begingroup$
Closing a question doesn't mean it's bad. Also doesn't mean it would be solved right away by any research mathematician.
$endgroup$
– YCor
3 hours ago
|
show 2 more comments
$begingroup$
How to solve this integral:
$$Jequiv int_{0}^{1}{int_{0}^{1}{frac{ln x-ln y}{x-y}}}dxdy$$
I've tried it for polylogarithmic transformations, but I can not get the result, which I think should be $$frac{{{pi }^{2}}}{3}.$$
Thanks!.
integration
New contributor
$endgroup$
How to solve this integral:
$$Jequiv int_{0}^{1}{int_{0}^{1}{frac{ln x-ln y}{x-y}}}dxdy$$
I've tried it for polylogarithmic transformations, but I can not get the result, which I think should be $$frac{{{pi }^{2}}}{3}.$$
Thanks!.
integration
integration
New contributor
New contributor
edited 3 hours ago
YCor
29.1k486140
29.1k486140
New contributor
asked 11 hours ago
Jesús Álvarez LoboJesús Álvarez Lobo
251
251
New contributor
New contributor
put on hold as off-topic by YCor, user44191, Pace Nielsen, Gerald Edgar, Piotr Hajlasz 5 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "MathOverflow is for mathematicians to ask each other questions about their research. See Math.StackExchange to ask general questions in mathematics." – Pace Nielsen, Gerald Edgar, Piotr Hajlasz
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by YCor, user44191, Pace Nielsen, Gerald Edgar, Piotr Hajlasz 5 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "MathOverflow is for mathematicians to ask each other questions about their research. See Math.StackExchange to ask general questions in mathematics." – Pace Nielsen, Gerald Edgar, Piotr Hajlasz
If this question can be reworded to fit the rules in the help center, please edit the question.
4
$begingroup$
MSE is a right place for such type questions. Both Maple and Mathematica confirm $ frac{pi ^2}{3}$.
$endgroup$
– user64494
11 hours ago
7
$begingroup$
I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
$endgroup$
– RP_
10 hours ago
3
$begingroup$
@user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
$endgroup$
– Fedor Petrov
8 hours ago
2
$begingroup$
@user64494 being the author of several papers devoted to exact closed-form integration, I feel so old now.
$endgroup$
– Fedor Petrov
5 hours ago
1
$begingroup$
Closing a question doesn't mean it's bad. Also doesn't mean it would be solved right away by any research mathematician.
$endgroup$
– YCor
3 hours ago
|
show 2 more comments
4
$begingroup$
MSE is a right place for such type questions. Both Maple and Mathematica confirm $ frac{pi ^2}{3}$.
$endgroup$
– user64494
11 hours ago
7
$begingroup$
I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
$endgroup$
– RP_
10 hours ago
3
$begingroup$
@user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
$endgroup$
– Fedor Petrov
8 hours ago
2
$begingroup$
@user64494 being the author of several papers devoted to exact closed-form integration, I feel so old now.
$endgroup$
– Fedor Petrov
5 hours ago
1
$begingroup$
Closing a question doesn't mean it's bad. Also doesn't mean it would be solved right away by any research mathematician.
$endgroup$
– YCor
3 hours ago
4
4
$begingroup$
MSE is a right place for such type questions. Both Maple and Mathematica confirm $ frac{pi ^2}{3}$.
$endgroup$
– user64494
11 hours ago
$begingroup$
MSE is a right place for such type questions. Both Maple and Mathematica confirm $ frac{pi ^2}{3}$.
$endgroup$
– user64494
11 hours ago
7
7
$begingroup$
I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
$endgroup$
– RP_
10 hours ago
$begingroup$
I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
$endgroup$
– RP_
10 hours ago
3
3
$begingroup$
@user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
$endgroup$
– Fedor Petrov
8 hours ago
$begingroup$
@user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
$endgroup$
– Fedor Petrov
8 hours ago
2
2
$begingroup$
@user64494 being the author of several papers devoted to exact closed-form integration, I feel so old now.
$endgroup$
– Fedor Petrov
5 hours ago
$begingroup$
@user64494 being the author of several papers devoted to exact closed-form integration, I feel so old now.
$endgroup$
– Fedor Petrov
5 hours ago
1
1
$begingroup$
Closing a question doesn't mean it's bad. Also doesn't mean it would be solved right away by any research mathematician.
$endgroup$
– YCor
3 hours ago
$begingroup$
Closing a question doesn't mean it's bad. Also doesn't mean it would be solved right away by any research mathematician.
$endgroup$
– YCor
3 hours ago
|
show 2 more comments
1 Answer
1
active
oldest
votes
$begingroup$
By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 frac{log t} {1-t}dt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac{1}{1 - t} =sum_{n>0 } t^{n-1}$ and integrate term-wise to get $sum 1/n^2$).
$endgroup$
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 frac{log t} {1-t}dt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac{1}{1 - t} =sum_{n>0 } t^{n-1}$ and integrate term-wise to get $sum 1/n^2$).
$endgroup$
add a comment |
$begingroup$
By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 frac{log t} {1-t}dt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac{1}{1 - t} =sum_{n>0 } t^{n-1}$ and integrate term-wise to get $sum 1/n^2$).
$endgroup$
add a comment |
$begingroup$
By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 frac{log t} {1-t}dt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac{1}{1 - t} =sum_{n>0 } t^{n-1}$ and integrate term-wise to get $sum 1/n^2$).
$endgroup$
By symmetry we have $J/2=int_0^1 dx int_0^x f(x, y) dy$ where $f(x, y) $ is your integrand. Integrating against $y$ for fixed $x$ we denote $y=tx$, $t$ varies from 0 to 1 and the integral against $y$ reads as $-int_0^1 frac{log t} {1-t}dt$. It does not depend on $x$ and is well known to be equal to $pi^2/6$ (you may use the geometric progression expansion $frac{1}{1 - t} =sum_{n>0 } t^{n-1}$ and integrate term-wise to get $sum 1/n^2$).
edited 10 hours ago
T. Amdeberhan
18.4k230132
18.4k230132
answered 11 hours ago
Fedor PetrovFedor Petrov
52.3k6122239
52.3k6122239
add a comment |
add a comment |
4
$begingroup$
MSE is a right place for such type questions. Both Maple and Mathematica confirm $ frac{pi ^2}{3}$.
$endgroup$
– user64494
11 hours ago
7
$begingroup$
I do not think this is such a bad question. I would not expect even every research mathematician to come up with the answer right away. So I vote not to close.
$endgroup$
– RP_
10 hours ago
3
$begingroup$
@user64494 what is a general strategy: when you have an integral which you do not know how to calculate, how should you decide between MSE and MO?
$endgroup$
– Fedor Petrov
8 hours ago
2
$begingroup$
@user64494 being the author of several papers devoted to exact closed-form integration, I feel so old now.
$endgroup$
– Fedor Petrov
5 hours ago
1
$begingroup$
Closing a question doesn't mean it's bad. Also doesn't mean it would be solved right away by any research mathematician.
$endgroup$
– YCor
3 hours ago