Draw functions on Plot3D












2












$begingroup$


I have a 2D function $f(x,z)$ which I render with Plot3D. In the plot, on top of the surface, I want to plot 1D functions at $f(0, z)$, $f(100, z)$ and $f(200, z)$.



So far I only have this:



um = 1;

Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]

mfx =
Function[{x, y, z}, Evaluate[D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z], x]]];

Plot3D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z],
{x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
PlotRange -> Full,
AxesLabel -> {x, z},
PlotPoints -> 50,
MeshFunctions -> {mfx},
Mesh -> {{0}},
MeshStyle -> {{Red}},
Boxed -> False,
Axes -> {True, False, False},
PlotStyle -> Cyan]


And I get this:



enter image description here



This only works for the $x = 0$ bit though.. how can I also add lines at $x = 100, 200$?










share|improve this question











$endgroup$

















    2












    $begingroup$


    I have a 2D function $f(x,z)$ which I render with Plot3D. In the plot, on top of the surface, I want to plot 1D functions at $f(0, z)$, $f(100, z)$ and $f(200, z)$.



    So far I only have this:



    um = 1;

    Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]

    mfx =
    Function[{x, y, z}, Evaluate[D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z], x]]];

    Plot3D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z],
    {x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
    PlotRange -> Full,
    AxesLabel -> {x, z},
    PlotPoints -> 50,
    MeshFunctions -> {mfx},
    Mesh -> {{0}},
    MeshStyle -> {{Red}},
    Boxed -> False,
    Axes -> {True, False, False},
    PlotStyle -> Cyan]


    And I get this:



    enter image description here



    This only works for the $x = 0$ bit though.. how can I also add lines at $x = 100, 200$?










    share|improve this question











    $endgroup$















      2












      2








      2





      $begingroup$


      I have a 2D function $f(x,z)$ which I render with Plot3D. In the plot, on top of the surface, I want to plot 1D functions at $f(0, z)$, $f(100, z)$ and $f(200, z)$.



      So far I only have this:



      um = 1;

      Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]

      mfx =
      Function[{x, y, z}, Evaluate[D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z], x]]];

      Plot3D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z],
      {x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
      PlotRange -> Full,
      AxesLabel -> {x, z},
      PlotPoints -> 50,
      MeshFunctions -> {mfx},
      Mesh -> {{0}},
      MeshStyle -> {{Red}},
      Boxed -> False,
      Axes -> {True, False, False},
      PlotStyle -> Cyan]


      And I get this:



      enter image description here



      This only works for the $x = 0$ bit though.. how can I also add lines at $x = 100, 200$?










      share|improve this question











      $endgroup$




      I have a 2D function $f(x,z)$ which I render with Plot3D. In the plot, on top of the surface, I want to plot 1D functions at $f(0, z)$, $f(100, z)$ and $f(200, z)$.



      So far I only have this:



      um = 1;

      Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]

      mfx =
      Function[{x, y, z}, Evaluate[D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z], x]]];

      Plot3D[Potential[1, (2 π)/(0.725 um ), 200 um, x, z],
      {x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
      PlotRange -> Full,
      AxesLabel -> {x, z},
      PlotPoints -> 50,
      MeshFunctions -> {mfx},
      Mesh -> {{0}},
      MeshStyle -> {{Red}},
      Boxed -> False,
      Axes -> {True, False, False},
      PlotStyle -> Cyan]


      And I get this:



      enter image description here



      This only works for the $x = 0$ bit though.. how can I also add lines at $x = 100, 200$?







      plotting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 3 hours ago









      m_goldberg

      85k872196




      85k872196










      asked 4 hours ago









      SuperCiociaSuperCiocia

      575312




      575312






















          1 Answer
          1






          active

          oldest

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          3












          $begingroup$

          You have to indicate the Mesh as a List



          um = 1;
          Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
          Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
          {x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
          PlotRange -> Full,
          AxesLabel -> {x, z}, PlotPoints -> 50,
          Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
          Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]





          share|improve this answer











          $endgroup$













          • $begingroup$
            I have removed the definition of mfxsince it is not relevant to your solution.
            $endgroup$
            – m_goldberg
            3 hours ago










          • $begingroup$
            I suggest MeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
            $endgroup$
            – m_goldberg
            3 hours ago











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          1 Answer
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          active

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          active

          oldest

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          active

          oldest

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          3












          $begingroup$

          You have to indicate the Mesh as a List



          um = 1;
          Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
          Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
          {x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
          PlotRange -> Full,
          AxesLabel -> {x, z}, PlotPoints -> 50,
          Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
          Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]





          share|improve this answer











          $endgroup$













          • $begingroup$
            I have removed the definition of mfxsince it is not relevant to your solution.
            $endgroup$
            – m_goldberg
            3 hours ago










          • $begingroup$
            I suggest MeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
            $endgroup$
            – m_goldberg
            3 hours ago
















          3












          $begingroup$

          You have to indicate the Mesh as a List



          um = 1;
          Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
          Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
          {x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
          PlotRange -> Full,
          AxesLabel -> {x, z}, PlotPoints -> 50,
          Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
          Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]





          share|improve this answer











          $endgroup$













          • $begingroup$
            I have removed the definition of mfxsince it is not relevant to your solution.
            $endgroup$
            – m_goldberg
            3 hours ago










          • $begingroup$
            I suggest MeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
            $endgroup$
            – m_goldberg
            3 hours ago














          3












          3








          3





          $begingroup$

          You have to indicate the Mesh as a List



          um = 1;
          Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
          Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
          {x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
          PlotRange -> Full,
          AxesLabel -> {x, z}, PlotPoints -> 50,
          Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
          Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]





          share|improve this answer











          $endgroup$



          You have to indicate the Mesh as a List



          um = 1;
          Potential[V0_, k_, w_, x_, z_] := V0*(Sin[k z]^2)*Exp[(-2 x^2)/w^2]
          Plot3D[Potential[1, (2 π)/(0.725 um), 200 um, x, z],
          {x, -500 um, 500 um}, {z, -1.1 um, 1.1 um},
          PlotRange -> Full,
          AxesLabel -> {x, z}, PlotPoints -> 50,
          Mesh -> {{0, 100, 200}, {30}, {30}}, MeshStyle -> {{Red}},
          Boxed -> False, Axes -> {True, False, False}, PlotStyle -> Cyan]






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 3 hours ago









          m_goldberg

          85k872196




          85k872196










          answered 4 hours ago









          M. VerueteM. Veruete

          713




          713












          • $begingroup$
            I have removed the definition of mfxsince it is not relevant to your solution.
            $endgroup$
            – m_goldberg
            3 hours ago










          • $begingroup$
            I suggest MeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
            $endgroup$
            – m_goldberg
            3 hours ago


















          • $begingroup$
            I have removed the definition of mfxsince it is not relevant to your solution.
            $endgroup$
            – m_goldberg
            3 hours ago










          • $begingroup$
            I suggest MeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
            $endgroup$
            – m_goldberg
            3 hours ago
















          $begingroup$
          I have removed the definition of mfxsince it is not relevant to your solution.
          $endgroup$
          – m_goldberg
          3 hours ago




          $begingroup$
          I have removed the definition of mfxsince it is not relevant to your solution.
          $endgroup$
          – m_goldberg
          3 hours ago












          $begingroup$
          I suggest MeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
          $endgroup$
          – m_goldberg
          3 hours ago




          $begingroup$
          I suggest MeshStyle -> {Directive[Red, AbsoluteThickness[4]]}. I think it make for a better looking plot.
          $endgroup$
          – m_goldberg
          3 hours ago


















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