Why does ls color two supposedly similar files differently?












1















So, here's the peculiar situation:



$ ls -l foo.sqlite foo.ssqlite
-rw-r--r-- 1 xie xie 8192 Jan 22 19:25 foo.sqlite
-rw-r--r-- 1 xie xie 8192 Jan 23 11:48 foo.ssqlite


In the output, foo.sqlite is colored blue by ls while foo.ssqlite is colored red/pink. Permissions are the same, types are the same:



$ file foo.sqlite foo.ssqlite
foo.sqlite: SQLite 3.x database, last written using SQLite version 3026000
foo.ssqlite: SQLite 3.x database, last written using SQLite version 3023001


The only obvious difference is that foo.sqlite was created by a Perl script, while the other - by a Python script, however that does not explain the different coloring, as if ls recognizes these as two different file types. Well, the question then is why does ls report these in different colors despite the type being the same?










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    1















    So, here's the peculiar situation:



    $ ls -l foo.sqlite foo.ssqlite
    -rw-r--r-- 1 xie xie 8192 Jan 22 19:25 foo.sqlite
    -rw-r--r-- 1 xie xie 8192 Jan 23 11:48 foo.ssqlite


    In the output, foo.sqlite is colored blue by ls while foo.ssqlite is colored red/pink. Permissions are the same, types are the same:



    $ file foo.sqlite foo.ssqlite
    foo.sqlite: SQLite 3.x database, last written using SQLite version 3026000
    foo.ssqlite: SQLite 3.x database, last written using SQLite version 3023001


    The only obvious difference is that foo.sqlite was created by a Perl script, while the other - by a Python script, however that does not explain the different coloring, as if ls recognizes these as two different file types. Well, the question then is why does ls report these in different colors despite the type being the same?










    share|improve this question



























      1












      1








      1








      So, here's the peculiar situation:



      $ ls -l foo.sqlite foo.ssqlite
      -rw-r--r-- 1 xie xie 8192 Jan 22 19:25 foo.sqlite
      -rw-r--r-- 1 xie xie 8192 Jan 23 11:48 foo.ssqlite


      In the output, foo.sqlite is colored blue by ls while foo.ssqlite is colored red/pink. Permissions are the same, types are the same:



      $ file foo.sqlite foo.ssqlite
      foo.sqlite: SQLite 3.x database, last written using SQLite version 3026000
      foo.ssqlite: SQLite 3.x database, last written using SQLite version 3023001


      The only obvious difference is that foo.sqlite was created by a Perl script, while the other - by a Python script, however that does not explain the different coloring, as if ls recognizes these as two different file types. Well, the question then is why does ls report these in different colors despite the type being the same?










      share|improve this question
















      So, here's the peculiar situation:



      $ ls -l foo.sqlite foo.ssqlite
      -rw-r--r-- 1 xie xie 8192 Jan 22 19:25 foo.sqlite
      -rw-r--r-- 1 xie xie 8192 Jan 23 11:48 foo.ssqlite


      In the output, foo.sqlite is colored blue by ls while foo.ssqlite is colored red/pink. Permissions are the same, types are the same:



      $ file foo.sqlite foo.ssqlite
      foo.sqlite: SQLite 3.x database, last written using SQLite version 3026000
      foo.ssqlite: SQLite 3.x database, last written using SQLite version 3023001


      The only obvious difference is that foo.sqlite was created by a Perl script, while the other - by a Python script, however that does not explain the different coloring, as if ls recognizes these as two different file types. Well, the question then is why does ls report these in different colors despite the type being the same?







      command-line environment-variables ls






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      edited 6 mins ago









      dessert

      22.4k56198




      22.4k56198










      asked 3 hours ago









      Sergiy KolodyazhnyySergiy Kolodyazhnyy

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          Apparently, ls relies on environment variable $LS_COLORS. Doing echo "$LS_COLORS" | grep --color sqlite revealed an entry with value *.sqlite=38;5;147, which apparently is the 256-color ANSI escape color code in form ESC[38;5;#m for foreground color.






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            Apparently, ls relies on environment variable $LS_COLORS. Doing echo "$LS_COLORS" | grep --color sqlite revealed an entry with value *.sqlite=38;5;147, which apparently is the 256-color ANSI escape color code in form ESC[38;5;#m for foreground color.






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              1














              Apparently, ls relies on environment variable $LS_COLORS. Doing echo "$LS_COLORS" | grep --color sqlite revealed an entry with value *.sqlite=38;5;147, which apparently is the 256-color ANSI escape color code in form ESC[38;5;#m for foreground color.






              share|improve this answer


























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                1







                Apparently, ls relies on environment variable $LS_COLORS. Doing echo "$LS_COLORS" | grep --color sqlite revealed an entry with value *.sqlite=38;5;147, which apparently is the 256-color ANSI escape color code in form ESC[38;5;#m for foreground color.






                share|improve this answer













                Apparently, ls relies on environment variable $LS_COLORS. Doing echo "$LS_COLORS" | grep --color sqlite revealed an entry with value *.sqlite=38;5;147, which apparently is the 256-color ANSI escape color code in form ESC[38;5;#m for foreground color.







                share|improve this answer












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                share|improve this answer










                answered 3 hours ago









                Sergiy KolodyazhnyySergiy Kolodyazhnyy

                71.4k9147313




                71.4k9147313






























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