Trying to use an LCD 1602 to display, but I don't have a 10 KOhm potentiometer
I'm following this tutorial page and I don't have a 10k ohm potentiometer on hand. Could I replace it with resistors to simulate a manual setting and replace the resistors to adjust to a new settings.
From what I was reading this pin is for contrast and I'm sure I could manually set the contrast once and be happy with it for quick prototyping. I'll be ordering a 10k ohm potentiometer on Monday.
potentiometer
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I'm following this tutorial page and I don't have a 10k ohm potentiometer on hand. Could I replace it with resistors to simulate a manual setting and replace the resistors to adjust to a new settings.
From what I was reading this pin is for contrast and I'm sure I could manually set the contrast once and be happy with it for quick prototyping. I'll be ordering a 10k ohm potentiometer on Monday.
potentiometer
New contributor
add a comment |
I'm following this tutorial page and I don't have a 10k ohm potentiometer on hand. Could I replace it with resistors to simulate a manual setting and replace the resistors to adjust to a new settings.
From what I was reading this pin is for contrast and I'm sure I could manually set the contrast once and be happy with it for quick prototyping. I'll be ordering a 10k ohm potentiometer on Monday.
potentiometer
New contributor
I'm following this tutorial page and I don't have a 10k ohm potentiometer on hand. Could I replace it with resistors to simulate a manual setting and replace the resistors to adjust to a new settings.
From what I was reading this pin is for contrast and I'm sure I could manually set the contrast once and be happy with it for quick prototyping. I'll be ordering a 10k ohm potentiometer on Monday.
potentiometer
potentiometer
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New contributor
edited 5 hours ago
Michel Keijzers
6,69441938
6,69441938
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asked 5 hours ago
TolureTolure
1083
1083
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4 Answers
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Yes. All a potentiometer is, is two resistors end to end. The "wiper" is the join between the two resistors.
It doesn't matter too much what value potentiometer (and hence what value resistors) you use, as long as it's "around" the 10kΩ mark (100kΩ should be fine, 50kΩ, 1kΩ etc - anything below 1kΩ may not work) - what matters is the ratio of the values of the resistor.
Would this work + ---[10K]--[connection to wiper]--[100K]--- -
– Tolure
5 hours ago
It may. It depends if that is the resistor ratio that you need. You will have to try it and see. If it's not right then change the resistors. But that arrangement of resistors is the right idea, yes.
– Majenko♦
3 hours ago
add a comment |
Yes, you always can do that, depending on the resistors you have at hand, you can combine them to make e.g. 1 KOhm, 2 KOhm etc resistors.
Probably you need a linear potentiometer (which means halfway is 5 KOhm).
In a linear potentiometer, you can use the following resistance (made up by a single or a combination of resistors in series or parallel):
add a comment |
Yes, but you need only one resistor to GND. The display has already one resistor inside the display. I forgot what the value should be and I don't have a display at hand right now, so you have to try which value is best.
In most examples with a LCD display, a potentiometer is used for the contrast. Not many people know that only a (variable) resistor to GND is needed.
With a fixed resistor, you are not able to quickly adjust the display when the temperature changes.
add a comment |
Disregard. My reply didn't add anything useful. I'm glad to see this forum is so watchful regarding the quality of answers and help.
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4 Answers
4
active
oldest
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4 Answers
4
active
oldest
votes
active
oldest
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active
oldest
votes
Yes. All a potentiometer is, is two resistors end to end. The "wiper" is the join between the two resistors.
It doesn't matter too much what value potentiometer (and hence what value resistors) you use, as long as it's "around" the 10kΩ mark (100kΩ should be fine, 50kΩ, 1kΩ etc - anything below 1kΩ may not work) - what matters is the ratio of the values of the resistor.
Would this work + ---[10K]--[connection to wiper]--[100K]--- -
– Tolure
5 hours ago
It may. It depends if that is the resistor ratio that you need. You will have to try it and see. If it's not right then change the resistors. But that arrangement of resistors is the right idea, yes.
– Majenko♦
3 hours ago
add a comment |
Yes. All a potentiometer is, is two resistors end to end. The "wiper" is the join between the two resistors.
It doesn't matter too much what value potentiometer (and hence what value resistors) you use, as long as it's "around" the 10kΩ mark (100kΩ should be fine, 50kΩ, 1kΩ etc - anything below 1kΩ may not work) - what matters is the ratio of the values of the resistor.
Would this work + ---[10K]--[connection to wiper]--[100K]--- -
– Tolure
5 hours ago
It may. It depends if that is the resistor ratio that you need. You will have to try it and see. If it's not right then change the resistors. But that arrangement of resistors is the right idea, yes.
– Majenko♦
3 hours ago
add a comment |
Yes. All a potentiometer is, is two resistors end to end. The "wiper" is the join between the two resistors.
It doesn't matter too much what value potentiometer (and hence what value resistors) you use, as long as it's "around" the 10kΩ mark (100kΩ should be fine, 50kΩ, 1kΩ etc - anything below 1kΩ may not work) - what matters is the ratio of the values of the resistor.
Yes. All a potentiometer is, is two resistors end to end. The "wiper" is the join between the two resistors.
It doesn't matter too much what value potentiometer (and hence what value resistors) you use, as long as it's "around" the 10kΩ mark (100kΩ should be fine, 50kΩ, 1kΩ etc - anything below 1kΩ may not work) - what matters is the ratio of the values of the resistor.
answered 5 hours ago
Majenko♦Majenko
68.1k43277
68.1k43277
Would this work + ---[10K]--[connection to wiper]--[100K]--- -
– Tolure
5 hours ago
It may. It depends if that is the resistor ratio that you need. You will have to try it and see. If it's not right then change the resistors. But that arrangement of resistors is the right idea, yes.
– Majenko♦
3 hours ago
add a comment |
Would this work + ---[10K]--[connection to wiper]--[100K]--- -
– Tolure
5 hours ago
It may. It depends if that is the resistor ratio that you need. You will have to try it and see. If it's not right then change the resistors. But that arrangement of resistors is the right idea, yes.
– Majenko♦
3 hours ago
Would this work + ---[10K]--[connection to wiper]--[100K]--- -
– Tolure
5 hours ago
Would this work + ---[10K]--[connection to wiper]--[100K]--- -
– Tolure
5 hours ago
It may. It depends if that is the resistor ratio that you need. You will have to try it and see. If it's not right then change the resistors. But that arrangement of resistors is the right idea, yes.
– Majenko♦
3 hours ago
It may. It depends if that is the resistor ratio that you need. You will have to try it and see. If it's not right then change the resistors. But that arrangement of resistors is the right idea, yes.
– Majenko♦
3 hours ago
add a comment |
Yes, you always can do that, depending on the resistors you have at hand, you can combine them to make e.g. 1 KOhm, 2 KOhm etc resistors.
Probably you need a linear potentiometer (which means halfway is 5 KOhm).
In a linear potentiometer, you can use the following resistance (made up by a single or a combination of resistors in series or parallel):
add a comment |
Yes, you always can do that, depending on the resistors you have at hand, you can combine them to make e.g. 1 KOhm, 2 KOhm etc resistors.
Probably you need a linear potentiometer (which means halfway is 5 KOhm).
In a linear potentiometer, you can use the following resistance (made up by a single or a combination of resistors in series or parallel):
add a comment |
Yes, you always can do that, depending on the resistors you have at hand, you can combine them to make e.g. 1 KOhm, 2 KOhm etc resistors.
Probably you need a linear potentiometer (which means halfway is 5 KOhm).
In a linear potentiometer, you can use the following resistance (made up by a single or a combination of resistors in series or parallel):
Yes, you always can do that, depending on the resistors you have at hand, you can combine them to make e.g. 1 KOhm, 2 KOhm etc resistors.
Probably you need a linear potentiometer (which means halfway is 5 KOhm).
In a linear potentiometer, you can use the following resistance (made up by a single or a combination of resistors in series or parallel):
answered 5 hours ago
Michel KeijzersMichel Keijzers
6,69441938
6,69441938
add a comment |
add a comment |
Yes, but you need only one resistor to GND. The display has already one resistor inside the display. I forgot what the value should be and I don't have a display at hand right now, so you have to try which value is best.
In most examples with a LCD display, a potentiometer is used for the contrast. Not many people know that only a (variable) resistor to GND is needed.
With a fixed resistor, you are not able to quickly adjust the display when the temperature changes.
add a comment |
Yes, but you need only one resistor to GND. The display has already one resistor inside the display. I forgot what the value should be and I don't have a display at hand right now, so you have to try which value is best.
In most examples with a LCD display, a potentiometer is used for the contrast. Not many people know that only a (variable) resistor to GND is needed.
With a fixed resistor, you are not able to quickly adjust the display when the temperature changes.
add a comment |
Yes, but you need only one resistor to GND. The display has already one resistor inside the display. I forgot what the value should be and I don't have a display at hand right now, so you have to try which value is best.
In most examples with a LCD display, a potentiometer is used for the contrast. Not many people know that only a (variable) resistor to GND is needed.
With a fixed resistor, you are not able to quickly adjust the display when the temperature changes.
Yes, but you need only one resistor to GND. The display has already one resistor inside the display. I forgot what the value should be and I don't have a display at hand right now, so you have to try which value is best.
In most examples with a LCD display, a potentiometer is used for the contrast. Not many people know that only a (variable) resistor to GND is needed.
With a fixed resistor, you are not able to quickly adjust the display when the temperature changes.
answered 1 hour ago
JotJot
2,6081618
2,6081618
add a comment |
add a comment |
Disregard. My reply didn't add anything useful. I'm glad to see this forum is so watchful regarding the quality of answers and help.
New contributor
add a comment |
Disregard. My reply didn't add anything useful. I'm glad to see this forum is so watchful regarding the quality of answers and help.
New contributor
add a comment |
Disregard. My reply didn't add anything useful. I'm glad to see this forum is so watchful regarding the quality of answers and help.
New contributor
Disregard. My reply didn't add anything useful. I'm glad to see this forum is so watchful regarding the quality of answers and help.
New contributor
edited 1 hour ago
New contributor
answered 4 hours ago
John P.John P.
81
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Tolure is a new contributor. Be nice, and check out our Code of Conduct.
Tolure is a new contributor. Be nice, and check out our Code of Conduct.
Tolure is a new contributor. Be nice, and check out our Code of Conduct.
Tolure is a new contributor. Be nice, and check out our Code of Conduct.
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