Cohomology of tangent sheaf of a hypersurface












3












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Let $Xsubsetmathbb{P}^n$ be an irreducible and reduced hypersurface of degree $d$. How can one explicitly compute the dimension of the vector spaces $H^0(X,T_X),H^1(X,T_X),H^2(X,T_X)$? Here $T_X$ is the tangent sheaf of $X$.
For instance $h^0(X,T_X)$ gives the dimension of the automorphism group of $X$.










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    $begingroup$


    Let $Xsubsetmathbb{P}^n$ be an irreducible and reduced hypersurface of degree $d$. How can one explicitly compute the dimension of the vector spaces $H^0(X,T_X),H^1(X,T_X),H^2(X,T_X)$? Here $T_X$ is the tangent sheaf of $X$.
    For instance $h^0(X,T_X)$ gives the dimension of the automorphism group of $X$.










    share|cite|improve this question







    New contributor




    user125056 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      3





      $begingroup$


      Let $Xsubsetmathbb{P}^n$ be an irreducible and reduced hypersurface of degree $d$. How can one explicitly compute the dimension of the vector spaces $H^0(X,T_X),H^1(X,T_X),H^2(X,T_X)$? Here $T_X$ is the tangent sheaf of $X$.
      For instance $h^0(X,T_X)$ gives the dimension of the automorphism group of $X$.










      share|cite|improve this question







      New contributor




      user125056 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      Let $Xsubsetmathbb{P}^n$ be an irreducible and reduced hypersurface of degree $d$. How can one explicitly compute the dimension of the vector spaces $H^0(X,T_X),H^1(X,T_X),H^2(X,T_X)$? Here $T_X$ is the tangent sheaf of $X$.
      For instance $h^0(X,T_X)$ gives the dimension of the automorphism group of $X$.







      ag.algebraic-geometry sheaf-theory projective-geometry birational-geometry sheaf-cohomology






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      asked 11 hours ago









      user125056user125056

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          1 Answer
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          4












          $begingroup$

          Use the normal sequence
          $$
          0 to T_X to T_{mathbb{P}^n}vert_X to N_{X/mathbb{P}^n} to 0,
          $$

          exact sequences
          $$
          0 to mathcal{O}_{mathbb{P}^n} to mathcal{O}_{mathbb{P}^n}(d) to i_*N_{X/mathbb{P}^n} to 0
          $$

          (we identify here $N_{X/mathbb{P}^n}$ with $mathcal{O}_X(d)$ and denote by $i$ the embedding $X to mathbb{P}^n$) and
          $$
          0 to T_{mathbb{P}^n}(-d) to T_{mathbb{P}^n} to i_*(T_{mathbb{P}^n}vert_X) to 0,
          $$

          and Borel-Bott-Weil Theorem to compute cohomology on $mathbb{P}^n$.






          share|cite|improve this answer









          $endgroup$









          • 1




            $begingroup$
            I think that the first exact sequence you wrote holds only if $X$ is smooth. What if $X$ is singular?
            $endgroup$
            – user125056
            10 hours ago






          • 2




            $begingroup$
            This is right (I missed the absence of the smoothness assumption in the question). In the singular case the first sequence is not exact in the right term, but its cokernel is not so hard to control. It is isomorphic to $mathcal{O}_Z(d)$, where $Z subset mathbb{P}^n$ is the subscheme defined by ${ partial F/partial x_0 = partial F/partial x_1 = dots partial F/partial x_n = 0 }$, where $F$ is the equation of $X$.
            $endgroup$
            – Sasha
            9 hours ago










          • $begingroup$
            An addendum: this nice paper by Sernesi (arxiv.org/pdf/1306.3736.pdf) gives informations on how to control the deformations of a singular reduced hypersurface in terms of the local cohomology of the cokernel that Sasha was mentioning.
            $endgroup$
            – Enrico
            6 hours ago











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          1 Answer
          1






          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          4












          $begingroup$

          Use the normal sequence
          $$
          0 to T_X to T_{mathbb{P}^n}vert_X to N_{X/mathbb{P}^n} to 0,
          $$

          exact sequences
          $$
          0 to mathcal{O}_{mathbb{P}^n} to mathcal{O}_{mathbb{P}^n}(d) to i_*N_{X/mathbb{P}^n} to 0
          $$

          (we identify here $N_{X/mathbb{P}^n}$ with $mathcal{O}_X(d)$ and denote by $i$ the embedding $X to mathbb{P}^n$) and
          $$
          0 to T_{mathbb{P}^n}(-d) to T_{mathbb{P}^n} to i_*(T_{mathbb{P}^n}vert_X) to 0,
          $$

          and Borel-Bott-Weil Theorem to compute cohomology on $mathbb{P}^n$.






          share|cite|improve this answer









          $endgroup$









          • 1




            $begingroup$
            I think that the first exact sequence you wrote holds only if $X$ is smooth. What if $X$ is singular?
            $endgroup$
            – user125056
            10 hours ago






          • 2




            $begingroup$
            This is right (I missed the absence of the smoothness assumption in the question). In the singular case the first sequence is not exact in the right term, but its cokernel is not so hard to control. It is isomorphic to $mathcal{O}_Z(d)$, where $Z subset mathbb{P}^n$ is the subscheme defined by ${ partial F/partial x_0 = partial F/partial x_1 = dots partial F/partial x_n = 0 }$, where $F$ is the equation of $X$.
            $endgroup$
            – Sasha
            9 hours ago










          • $begingroup$
            An addendum: this nice paper by Sernesi (arxiv.org/pdf/1306.3736.pdf) gives informations on how to control the deformations of a singular reduced hypersurface in terms of the local cohomology of the cokernel that Sasha was mentioning.
            $endgroup$
            – Enrico
            6 hours ago
















          4












          $begingroup$

          Use the normal sequence
          $$
          0 to T_X to T_{mathbb{P}^n}vert_X to N_{X/mathbb{P}^n} to 0,
          $$

          exact sequences
          $$
          0 to mathcal{O}_{mathbb{P}^n} to mathcal{O}_{mathbb{P}^n}(d) to i_*N_{X/mathbb{P}^n} to 0
          $$

          (we identify here $N_{X/mathbb{P}^n}$ with $mathcal{O}_X(d)$ and denote by $i$ the embedding $X to mathbb{P}^n$) and
          $$
          0 to T_{mathbb{P}^n}(-d) to T_{mathbb{P}^n} to i_*(T_{mathbb{P}^n}vert_X) to 0,
          $$

          and Borel-Bott-Weil Theorem to compute cohomology on $mathbb{P}^n$.






          share|cite|improve this answer









          $endgroup$









          • 1




            $begingroup$
            I think that the first exact sequence you wrote holds only if $X$ is smooth. What if $X$ is singular?
            $endgroup$
            – user125056
            10 hours ago






          • 2




            $begingroup$
            This is right (I missed the absence of the smoothness assumption in the question). In the singular case the first sequence is not exact in the right term, but its cokernel is not so hard to control. It is isomorphic to $mathcal{O}_Z(d)$, where $Z subset mathbb{P}^n$ is the subscheme defined by ${ partial F/partial x_0 = partial F/partial x_1 = dots partial F/partial x_n = 0 }$, where $F$ is the equation of $X$.
            $endgroup$
            – Sasha
            9 hours ago










          • $begingroup$
            An addendum: this nice paper by Sernesi (arxiv.org/pdf/1306.3736.pdf) gives informations on how to control the deformations of a singular reduced hypersurface in terms of the local cohomology of the cokernel that Sasha was mentioning.
            $endgroup$
            – Enrico
            6 hours ago














          4












          4








          4





          $begingroup$

          Use the normal sequence
          $$
          0 to T_X to T_{mathbb{P}^n}vert_X to N_{X/mathbb{P}^n} to 0,
          $$

          exact sequences
          $$
          0 to mathcal{O}_{mathbb{P}^n} to mathcal{O}_{mathbb{P}^n}(d) to i_*N_{X/mathbb{P}^n} to 0
          $$

          (we identify here $N_{X/mathbb{P}^n}$ with $mathcal{O}_X(d)$ and denote by $i$ the embedding $X to mathbb{P}^n$) and
          $$
          0 to T_{mathbb{P}^n}(-d) to T_{mathbb{P}^n} to i_*(T_{mathbb{P}^n}vert_X) to 0,
          $$

          and Borel-Bott-Weil Theorem to compute cohomology on $mathbb{P}^n$.






          share|cite|improve this answer









          $endgroup$



          Use the normal sequence
          $$
          0 to T_X to T_{mathbb{P}^n}vert_X to N_{X/mathbb{P}^n} to 0,
          $$

          exact sequences
          $$
          0 to mathcal{O}_{mathbb{P}^n} to mathcal{O}_{mathbb{P}^n}(d) to i_*N_{X/mathbb{P}^n} to 0
          $$

          (we identify here $N_{X/mathbb{P}^n}$ with $mathcal{O}_X(d)$ and denote by $i$ the embedding $X to mathbb{P}^n$) and
          $$
          0 to T_{mathbb{P}^n}(-d) to T_{mathbb{P}^n} to i_*(T_{mathbb{P}^n}vert_X) to 0,
          $$

          and Borel-Bott-Weil Theorem to compute cohomology on $mathbb{P}^n$.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered 11 hours ago









          SashaSasha

          20.8k22655




          20.8k22655








          • 1




            $begingroup$
            I think that the first exact sequence you wrote holds only if $X$ is smooth. What if $X$ is singular?
            $endgroup$
            – user125056
            10 hours ago






          • 2




            $begingroup$
            This is right (I missed the absence of the smoothness assumption in the question). In the singular case the first sequence is not exact in the right term, but its cokernel is not so hard to control. It is isomorphic to $mathcal{O}_Z(d)$, where $Z subset mathbb{P}^n$ is the subscheme defined by ${ partial F/partial x_0 = partial F/partial x_1 = dots partial F/partial x_n = 0 }$, where $F$ is the equation of $X$.
            $endgroup$
            – Sasha
            9 hours ago










          • $begingroup$
            An addendum: this nice paper by Sernesi (arxiv.org/pdf/1306.3736.pdf) gives informations on how to control the deformations of a singular reduced hypersurface in terms of the local cohomology of the cokernel that Sasha was mentioning.
            $endgroup$
            – Enrico
            6 hours ago














          • 1




            $begingroup$
            I think that the first exact sequence you wrote holds only if $X$ is smooth. What if $X$ is singular?
            $endgroup$
            – user125056
            10 hours ago






          • 2




            $begingroup$
            This is right (I missed the absence of the smoothness assumption in the question). In the singular case the first sequence is not exact in the right term, but its cokernel is not so hard to control. It is isomorphic to $mathcal{O}_Z(d)$, where $Z subset mathbb{P}^n$ is the subscheme defined by ${ partial F/partial x_0 = partial F/partial x_1 = dots partial F/partial x_n = 0 }$, where $F$ is the equation of $X$.
            $endgroup$
            – Sasha
            9 hours ago










          • $begingroup$
            An addendum: this nice paper by Sernesi (arxiv.org/pdf/1306.3736.pdf) gives informations on how to control the deformations of a singular reduced hypersurface in terms of the local cohomology of the cokernel that Sasha was mentioning.
            $endgroup$
            – Enrico
            6 hours ago








          1




          1




          $begingroup$
          I think that the first exact sequence you wrote holds only if $X$ is smooth. What if $X$ is singular?
          $endgroup$
          – user125056
          10 hours ago




          $begingroup$
          I think that the first exact sequence you wrote holds only if $X$ is smooth. What if $X$ is singular?
          $endgroup$
          – user125056
          10 hours ago




          2




          2




          $begingroup$
          This is right (I missed the absence of the smoothness assumption in the question). In the singular case the first sequence is not exact in the right term, but its cokernel is not so hard to control. It is isomorphic to $mathcal{O}_Z(d)$, where $Z subset mathbb{P}^n$ is the subscheme defined by ${ partial F/partial x_0 = partial F/partial x_1 = dots partial F/partial x_n = 0 }$, where $F$ is the equation of $X$.
          $endgroup$
          – Sasha
          9 hours ago




          $begingroup$
          This is right (I missed the absence of the smoothness assumption in the question). In the singular case the first sequence is not exact in the right term, but its cokernel is not so hard to control. It is isomorphic to $mathcal{O}_Z(d)$, where $Z subset mathbb{P}^n$ is the subscheme defined by ${ partial F/partial x_0 = partial F/partial x_1 = dots partial F/partial x_n = 0 }$, where $F$ is the equation of $X$.
          $endgroup$
          – Sasha
          9 hours ago












          $begingroup$
          An addendum: this nice paper by Sernesi (arxiv.org/pdf/1306.3736.pdf) gives informations on how to control the deformations of a singular reduced hypersurface in terms of the local cohomology of the cokernel that Sasha was mentioning.
          $endgroup$
          – Enrico
          6 hours ago




          $begingroup$
          An addendum: this nice paper by Sernesi (arxiv.org/pdf/1306.3736.pdf) gives informations on how to control the deformations of a singular reduced hypersurface in terms of the local cohomology of the cokernel that Sasha was mentioning.
          $endgroup$
          – Enrico
          6 hours ago










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