Regexp replace to to match a string, but not superstring
Let's say I want to replace the string "Vector" by "VectorBase", but there are existing instances of "VectorBase". So I would like to omit "VectorBase". What is an elegant way to achieve this?
An easy way is to do ignore the condition and do the replacement and at the end replace all instances of BaseBase by Base. I'm looking for a better way to achieve this.
regular-expressions replace query-replace
add a comment |
Let's say I want to replace the string "Vector" by "VectorBase", but there are existing instances of "VectorBase". So I would like to omit "VectorBase". What is an elegant way to achieve this?
An easy way is to do ignore the condition and do the replacement and at the end replace all instances of BaseBase by Base. I'm looking for a better way to achieve this.
regular-expressions replace query-replace
add a comment |
Let's say I want to replace the string "Vector" by "VectorBase", but there are existing instances of "VectorBase". So I would like to omit "VectorBase". What is an elegant way to achieve this?
An easy way is to do ignore the condition and do the replacement and at the end replace all instances of BaseBase by Base. I'm looking for a better way to achieve this.
regular-expressions replace query-replace
Let's say I want to replace the string "Vector" by "VectorBase", but there are existing instances of "VectorBase". So I would like to omit "VectorBase". What is an elegant way to achieve this?
An easy way is to do ignore the condition and do the replacement and at the end replace all instances of BaseBase by Base. I'm looking for a better way to achieve this.
regular-expressions replace query-replace
regular-expressions replace query-replace
edited 9 hours ago
Drew
47.4k462104
47.4k462104
asked 10 hours ago
fermesommefermesomme
200110
200110
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Try bVectorb
. The b
construct matches the empty string, but only at the beginning and end of a word (what is a "word" depends on the buffer's syntax table however: it should work in most cases, but there might be corner cases that are problematic.)
See Backslash Constructs in Regular Expressions for more information.
add a comment |
Another simple trick you can use is to match both Vector
and VectorBase
, and replace them both with VectorBase
.
Vector(Base)? → VectorBase
More complicated cases can be handled by using elisp in the replacement. For example, the following replaces "Vector" with "Array" unless it was "VectorBase", in which case it 'keeps' it as "VectorBase" (i.e. replaces it with the matched string).
Vector(Base)? → ,(if 1 & "Array")
Which is similar (in terms of the end result) to what can be done with arbitrary look-around assertions (in regexp languages which support those).
add a comment |
One simple, very old-school way is to do multiple replacement passes:
Replace
VectorBase
by, sayAAAA
(some string that you're sure doesn't already occur somewhere).Replace
Vector
byVectorBase
.Replace
AAAA
byVectorBase
.
This works for replace-all and query-replace. It's pretty fail-safe and doesn't require any complex matching or fancy replacement regexp.
However: It's important that you first check that there are not already some occurrences of any chars of the string you're thinking of using as the temporary replacement (e.g. AAAA
). If there are already such occurrences then choose a different string. ;-) (I typically use a string such as ^G
(a Control-G character), input in the minibuffer using C-q C-g
- after making sure there is no C-g
char in the buffer.)
1
Even if 'AAAA' doesn't appear in the text, that approach may fail. If the text containsAAVectorBase
, the sequence of events described above will result in the text containingVectorBaseAA
.
– Abigail
4 hours ago
@Abigail: Yes, of course. Use a string that has no chars used anywhere. Updated to make that clear. Thx.
– Drew
3 hours ago
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try bVectorb
. The b
construct matches the empty string, but only at the beginning and end of a word (what is a "word" depends on the buffer's syntax table however: it should work in most cases, but there might be corner cases that are problematic.)
See Backslash Constructs in Regular Expressions for more information.
add a comment |
Try bVectorb
. The b
construct matches the empty string, but only at the beginning and end of a word (what is a "word" depends on the buffer's syntax table however: it should work in most cases, but there might be corner cases that are problematic.)
See Backslash Constructs in Regular Expressions for more information.
add a comment |
Try bVectorb
. The b
construct matches the empty string, but only at the beginning and end of a word (what is a "word" depends on the buffer's syntax table however: it should work in most cases, but there might be corner cases that are problematic.)
See Backslash Constructs in Regular Expressions for more information.
Try bVectorb
. The b
construct matches the empty string, but only at the beginning and end of a word (what is a "word" depends on the buffer's syntax table however: it should work in most cases, but there might be corner cases that are problematic.)
See Backslash Constructs in Regular Expressions for more information.
edited 8 hours ago
answered 10 hours ago
NickDNickD
2,4511312
2,4511312
add a comment |
add a comment |
Another simple trick you can use is to match both Vector
and VectorBase
, and replace them both with VectorBase
.
Vector(Base)? → VectorBase
More complicated cases can be handled by using elisp in the replacement. For example, the following replaces "Vector" with "Array" unless it was "VectorBase", in which case it 'keeps' it as "VectorBase" (i.e. replaces it with the matched string).
Vector(Base)? → ,(if 1 & "Array")
Which is similar (in terms of the end result) to what can be done with arbitrary look-around assertions (in regexp languages which support those).
add a comment |
Another simple trick you can use is to match both Vector
and VectorBase
, and replace them both with VectorBase
.
Vector(Base)? → VectorBase
More complicated cases can be handled by using elisp in the replacement. For example, the following replaces "Vector" with "Array" unless it was "VectorBase", in which case it 'keeps' it as "VectorBase" (i.e. replaces it with the matched string).
Vector(Base)? → ,(if 1 & "Array")
Which is similar (in terms of the end result) to what can be done with arbitrary look-around assertions (in regexp languages which support those).
add a comment |
Another simple trick you can use is to match both Vector
and VectorBase
, and replace them both with VectorBase
.
Vector(Base)? → VectorBase
More complicated cases can be handled by using elisp in the replacement. For example, the following replaces "Vector" with "Array" unless it was "VectorBase", in which case it 'keeps' it as "VectorBase" (i.e. replaces it with the matched string).
Vector(Base)? → ,(if 1 & "Array")
Which is similar (in terms of the end result) to what can be done with arbitrary look-around assertions (in regexp languages which support those).
Another simple trick you can use is to match both Vector
and VectorBase
, and replace them both with VectorBase
.
Vector(Base)? → VectorBase
More complicated cases can be handled by using elisp in the replacement. For example, the following replaces "Vector" with "Array" unless it was "VectorBase", in which case it 'keeps' it as "VectorBase" (i.e. replaces it with the matched string).
Vector(Base)? → ,(if 1 & "Array")
Which is similar (in terms of the end result) to what can be done with arbitrary look-around assertions (in regexp languages which support those).
edited 5 hours ago
answered 6 hours ago
philsphils
26.3k23567
26.3k23567
add a comment |
add a comment |
One simple, very old-school way is to do multiple replacement passes:
Replace
VectorBase
by, sayAAAA
(some string that you're sure doesn't already occur somewhere).Replace
Vector
byVectorBase
.Replace
AAAA
byVectorBase
.
This works for replace-all and query-replace. It's pretty fail-safe and doesn't require any complex matching or fancy replacement regexp.
However: It's important that you first check that there are not already some occurrences of any chars of the string you're thinking of using as the temporary replacement (e.g. AAAA
). If there are already such occurrences then choose a different string. ;-) (I typically use a string such as ^G
(a Control-G character), input in the minibuffer using C-q C-g
- after making sure there is no C-g
char in the buffer.)
1
Even if 'AAAA' doesn't appear in the text, that approach may fail. If the text containsAAVectorBase
, the sequence of events described above will result in the text containingVectorBaseAA
.
– Abigail
4 hours ago
@Abigail: Yes, of course. Use a string that has no chars used anywhere. Updated to make that clear. Thx.
– Drew
3 hours ago
add a comment |
One simple, very old-school way is to do multiple replacement passes:
Replace
VectorBase
by, sayAAAA
(some string that you're sure doesn't already occur somewhere).Replace
Vector
byVectorBase
.Replace
AAAA
byVectorBase
.
This works for replace-all and query-replace. It's pretty fail-safe and doesn't require any complex matching or fancy replacement regexp.
However: It's important that you first check that there are not already some occurrences of any chars of the string you're thinking of using as the temporary replacement (e.g. AAAA
). If there are already such occurrences then choose a different string. ;-) (I typically use a string such as ^G
(a Control-G character), input in the minibuffer using C-q C-g
- after making sure there is no C-g
char in the buffer.)
1
Even if 'AAAA' doesn't appear in the text, that approach may fail. If the text containsAAVectorBase
, the sequence of events described above will result in the text containingVectorBaseAA
.
– Abigail
4 hours ago
@Abigail: Yes, of course. Use a string that has no chars used anywhere. Updated to make that clear. Thx.
– Drew
3 hours ago
add a comment |
One simple, very old-school way is to do multiple replacement passes:
Replace
VectorBase
by, sayAAAA
(some string that you're sure doesn't already occur somewhere).Replace
Vector
byVectorBase
.Replace
AAAA
byVectorBase
.
This works for replace-all and query-replace. It's pretty fail-safe and doesn't require any complex matching or fancy replacement regexp.
However: It's important that you first check that there are not already some occurrences of any chars of the string you're thinking of using as the temporary replacement (e.g. AAAA
). If there are already such occurrences then choose a different string. ;-) (I typically use a string such as ^G
(a Control-G character), input in the minibuffer using C-q C-g
- after making sure there is no C-g
char in the buffer.)
One simple, very old-school way is to do multiple replacement passes:
Replace
VectorBase
by, sayAAAA
(some string that you're sure doesn't already occur somewhere).Replace
Vector
byVectorBase
.Replace
AAAA
byVectorBase
.
This works for replace-all and query-replace. It's pretty fail-safe and doesn't require any complex matching or fancy replacement regexp.
However: It's important that you first check that there are not already some occurrences of any chars of the string you're thinking of using as the temporary replacement (e.g. AAAA
). If there are already such occurrences then choose a different string. ;-) (I typically use a string such as ^G
(a Control-G character), input in the minibuffer using C-q C-g
- after making sure there is no C-g
char in the buffer.)
edited 3 hours ago
answered 9 hours ago
DrewDrew
47.4k462104
47.4k462104
1
Even if 'AAAA' doesn't appear in the text, that approach may fail. If the text containsAAVectorBase
, the sequence of events described above will result in the text containingVectorBaseAA
.
– Abigail
4 hours ago
@Abigail: Yes, of course. Use a string that has no chars used anywhere. Updated to make that clear. Thx.
– Drew
3 hours ago
add a comment |
1
Even if 'AAAA' doesn't appear in the text, that approach may fail. If the text containsAAVectorBase
, the sequence of events described above will result in the text containingVectorBaseAA
.
– Abigail
4 hours ago
@Abigail: Yes, of course. Use a string that has no chars used anywhere. Updated to make that clear. Thx.
– Drew
3 hours ago
1
1
Even if 'AAAA' doesn't appear in the text, that approach may fail. If the text contains
AAVectorBase
, the sequence of events described above will result in the text containing VectorBaseAA
.– Abigail
4 hours ago
Even if 'AAAA' doesn't appear in the text, that approach may fail. If the text contains
AAVectorBase
, the sequence of events described above will result in the text containing VectorBaseAA
.– Abigail
4 hours ago
@Abigail: Yes, of course. Use a string that has no chars used anywhere. Updated to make that clear. Thx.
– Drew
3 hours ago
@Abigail: Yes, of course. Use a string that has no chars used anywhere. Updated to make that clear. Thx.
– Drew
3 hours ago
add a comment |
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