What kind of transistor turns on with 0.2 volts?
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$begingroup$
I need a circuit to turn on a LED with 0.2 volts.
I want to do it with a transistor as a switch.
What kind of transistor will turn on at this voltage?
transistors mosfet bjt jfet
New contributor
$endgroup$
|
show 2 more comments
$begingroup$
I need a circuit to turn on a LED with 0.2 volts.
I want to do it with a transistor as a switch.
What kind of transistor will turn on at this voltage?
transistors mosfet bjt jfet
New contributor
$endgroup$
5
$begingroup$
Pretty much none of them. I would recommend amplifying the signal before trying to use it as a switch, perhaps with a comparator.
$endgroup$
– Hearth
2 days ago
6
$begingroup$
Instead of asking about a transistor which needs to turn on with only 0.2 V (there aren't any but please prove me wrong!) and assume that you can do this with only one transistor (you can't but I'd like to be proven wrong again), describe what your requirements are and ask what solutions exist. A LED will not light up with 0.2 V so there must be some other voltage present. Why 0.2 V? Do research on similar setups (switching LEDs) and learn how that's done.
$endgroup$
– Bimpelrekkie
2 days ago
2
$begingroup$
Highly related if not duplicate: electronics.stackexchange.com/questions/129183/…
$endgroup$
– winny
2 days ago
$begingroup$
0.2V isn't enough to run an LED; if you have a rail that'll drive an LED then you can use a comparator.
$endgroup$
– TimWescott
2 days ago
$begingroup$
What's the LED and what's the current and voltage it requires? What power supply rails do you have?
$endgroup$
– jonk
2 days ago
|
show 2 more comments
$begingroup$
I need a circuit to turn on a LED with 0.2 volts.
I want to do it with a transistor as a switch.
What kind of transistor will turn on at this voltage?
transistors mosfet bjt jfet
New contributor
$endgroup$
I need a circuit to turn on a LED with 0.2 volts.
I want to do it with a transistor as a switch.
What kind of transistor will turn on at this voltage?
transistors mosfet bjt jfet
transistors mosfet bjt jfet
New contributor
New contributor
New contributor
asked 2 days ago
seyyedali hosseiniseyyedali hosseini
173
173
New contributor
New contributor
5
$begingroup$
Pretty much none of them. I would recommend amplifying the signal before trying to use it as a switch, perhaps with a comparator.
$endgroup$
– Hearth
2 days ago
6
$begingroup$
Instead of asking about a transistor which needs to turn on with only 0.2 V (there aren't any but please prove me wrong!) and assume that you can do this with only one transistor (you can't but I'd like to be proven wrong again), describe what your requirements are and ask what solutions exist. A LED will not light up with 0.2 V so there must be some other voltage present. Why 0.2 V? Do research on similar setups (switching LEDs) and learn how that's done.
$endgroup$
– Bimpelrekkie
2 days ago
2
$begingroup$
Highly related if not duplicate: electronics.stackexchange.com/questions/129183/…
$endgroup$
– winny
2 days ago
$begingroup$
0.2V isn't enough to run an LED; if you have a rail that'll drive an LED then you can use a comparator.
$endgroup$
– TimWescott
2 days ago
$begingroup$
What's the LED and what's the current and voltage it requires? What power supply rails do you have?
$endgroup$
– jonk
2 days ago
|
show 2 more comments
5
$begingroup$
Pretty much none of them. I would recommend amplifying the signal before trying to use it as a switch, perhaps with a comparator.
$endgroup$
– Hearth
2 days ago
6
$begingroup$
Instead of asking about a transistor which needs to turn on with only 0.2 V (there aren't any but please prove me wrong!) and assume that you can do this with only one transistor (you can't but I'd like to be proven wrong again), describe what your requirements are and ask what solutions exist. A LED will not light up with 0.2 V so there must be some other voltage present. Why 0.2 V? Do research on similar setups (switching LEDs) and learn how that's done.
$endgroup$
– Bimpelrekkie
2 days ago
2
$begingroup$
Highly related if not duplicate: electronics.stackexchange.com/questions/129183/…
$endgroup$
– winny
2 days ago
$begingroup$
0.2V isn't enough to run an LED; if you have a rail that'll drive an LED then you can use a comparator.
$endgroup$
– TimWescott
2 days ago
$begingroup$
What's the LED and what's the current and voltage it requires? What power supply rails do you have?
$endgroup$
– jonk
2 days ago
5
5
$begingroup$
Pretty much none of them. I would recommend amplifying the signal before trying to use it as a switch, perhaps with a comparator.
$endgroup$
– Hearth
2 days ago
$begingroup$
Pretty much none of them. I would recommend amplifying the signal before trying to use it as a switch, perhaps with a comparator.
$endgroup$
– Hearth
2 days ago
6
6
$begingroup$
Instead of asking about a transistor which needs to turn on with only 0.2 V (there aren't any but please prove me wrong!) and assume that you can do this with only one transistor (you can't but I'd like to be proven wrong again), describe what your requirements are and ask what solutions exist. A LED will not light up with 0.2 V so there must be some other voltage present. Why 0.2 V? Do research on similar setups (switching LEDs) and learn how that's done.
$endgroup$
– Bimpelrekkie
2 days ago
$begingroup$
Instead of asking about a transistor which needs to turn on with only 0.2 V (there aren't any but please prove me wrong!) and assume that you can do this with only one transistor (you can't but I'd like to be proven wrong again), describe what your requirements are and ask what solutions exist. A LED will not light up with 0.2 V so there must be some other voltage present. Why 0.2 V? Do research on similar setups (switching LEDs) and learn how that's done.
$endgroup$
– Bimpelrekkie
2 days ago
2
2
$begingroup$
Highly related if not duplicate: electronics.stackexchange.com/questions/129183/…
$endgroup$
– winny
2 days ago
$begingroup$
Highly related if not duplicate: electronics.stackexchange.com/questions/129183/…
$endgroup$
– winny
2 days ago
$begingroup$
0.2V isn't enough to run an LED; if you have a rail that'll drive an LED then you can use a comparator.
$endgroup$
– TimWescott
2 days ago
$begingroup$
0.2V isn't enough to run an LED; if you have a rail that'll drive an LED then you can use a comparator.
$endgroup$
– TimWescott
2 days ago
$begingroup$
What's the LED and what's the current and voltage it requires? What power supply rails do you have?
$endgroup$
– jonk
2 days ago
$begingroup$
What's the LED and what's the current and voltage it requires? What power supply rails do you have?
$endgroup$
– jonk
2 days ago
|
show 2 more comments
4 Answers
4
active
oldest
votes
$begingroup$
Whilst I'm inclined to agree with @Bimpelrekkie that this is probably an X-Y problem, for those who might actually need such a device there are some options. Most MOSFETs are sold as enhancement or depletion mode (less commonly) devices, however it's possible to tune the threshold voltage to approximately zero +/- tens of mV.
For example, the Advanced Linear Devices ALD110800A and similar devices in that series have a nominal zero gate threshold (1uA Ids). The subthreshold behavior is fairly well documented as well.
For your actual situation, use CrossRoads circuit with just about any single supply op-amp or single-supply comparator. LM358 or LM393 will work fine from a 5V supply.
$endgroup$
add a comment |
$begingroup$
No single transistor can do what you want. Instead, you need to use multiple transistors. A simple voltage comparator will do what you want:
simulate this circuit – Schematic created using CircuitLab
R2 and R3 set the reference voltage for the base of Q2. As long as the voltage at the base of Q1 is less than Vref, all of the current through R1 will flow through Q2. As soon as the input voltage rises above 0.2V, Q2 will cut off and all of the current will flow through Q1 and the LED instead.
Note that since the emitters of the transistors need to be at a negative voltage, this circuit requires a negative supply. An alternative would be to use an IC comparator — you can find single-supply units that can work with input voltages close to ground.
$endgroup$
1
$begingroup$
You can approach the lower rail by using PNPs 'upside down' and a single supply.
$endgroup$
– Russell McMahon
2 days ago
$begingroup$
@RussellMcMahon: But then there's no overhead left for the load (LED), at least, not without adding additional transistors. At that point, just get the IC comparator, which is essentially the same thing.
$endgroup$
– Dave Tweed♦
2 days ago
$begingroup$
This circuit really needs some positive feedback to achieve a clean switch.
$endgroup$
– EinarA
yesterday
add a comment |
$begingroup$
simulate this circuit – Schematic created using CircuitLab
You could also use an Op Amp, or a Comparator. Set one input to 0.2V, when the other input exceeds that, the output will switch.
Here's one example
https://datasheets.maximintegrated.com/en/ds/MAX9107-MAX9109.pdf
$endgroup$
add a comment |
$begingroup$
A well chosen germanium transistor can do this. I have some that switch at .15V. Finding one might be a problem ; I am not offering any of mine, but they still exist. If you need accurateness use one of the other answers, The simplest solution is to prebias a transistor so the base receives enough voltage to turn on when the input is .2V. I have used this trick in non-critical situations.
$endgroup$
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Whilst I'm inclined to agree with @Bimpelrekkie that this is probably an X-Y problem, for those who might actually need such a device there are some options. Most MOSFETs are sold as enhancement or depletion mode (less commonly) devices, however it's possible to tune the threshold voltage to approximately zero +/- tens of mV.
For example, the Advanced Linear Devices ALD110800A and similar devices in that series have a nominal zero gate threshold (1uA Ids). The subthreshold behavior is fairly well documented as well.
For your actual situation, use CrossRoads circuit with just about any single supply op-amp or single-supply comparator. LM358 or LM393 will work fine from a 5V supply.
$endgroup$
add a comment |
$begingroup$
Whilst I'm inclined to agree with @Bimpelrekkie that this is probably an X-Y problem, for those who might actually need such a device there are some options. Most MOSFETs are sold as enhancement or depletion mode (less commonly) devices, however it's possible to tune the threshold voltage to approximately zero +/- tens of mV.
For example, the Advanced Linear Devices ALD110800A and similar devices in that series have a nominal zero gate threshold (1uA Ids). The subthreshold behavior is fairly well documented as well.
For your actual situation, use CrossRoads circuit with just about any single supply op-amp or single-supply comparator. LM358 or LM393 will work fine from a 5V supply.
$endgroup$
add a comment |
$begingroup$
Whilst I'm inclined to agree with @Bimpelrekkie that this is probably an X-Y problem, for those who might actually need such a device there are some options. Most MOSFETs are sold as enhancement or depletion mode (less commonly) devices, however it's possible to tune the threshold voltage to approximately zero +/- tens of mV.
For example, the Advanced Linear Devices ALD110800A and similar devices in that series have a nominal zero gate threshold (1uA Ids). The subthreshold behavior is fairly well documented as well.
For your actual situation, use CrossRoads circuit with just about any single supply op-amp or single-supply comparator. LM358 or LM393 will work fine from a 5V supply.
$endgroup$
Whilst I'm inclined to agree with @Bimpelrekkie that this is probably an X-Y problem, for those who might actually need such a device there are some options. Most MOSFETs are sold as enhancement or depletion mode (less commonly) devices, however it's possible to tune the threshold voltage to approximately zero +/- tens of mV.
For example, the Advanced Linear Devices ALD110800A and similar devices in that series have a nominal zero gate threshold (1uA Ids). The subthreshold behavior is fairly well documented as well.
For your actual situation, use CrossRoads circuit with just about any single supply op-amp or single-supply comparator. LM358 or LM393 will work fine from a 5V supply.
edited 2 days ago
answered 2 days ago
Spehro PefhanySpehro Pefhany
213k5162432
213k5162432
add a comment |
add a comment |
$begingroup$
No single transistor can do what you want. Instead, you need to use multiple transistors. A simple voltage comparator will do what you want:
simulate this circuit – Schematic created using CircuitLab
R2 and R3 set the reference voltage for the base of Q2. As long as the voltage at the base of Q1 is less than Vref, all of the current through R1 will flow through Q2. As soon as the input voltage rises above 0.2V, Q2 will cut off and all of the current will flow through Q1 and the LED instead.
Note that since the emitters of the transistors need to be at a negative voltage, this circuit requires a negative supply. An alternative would be to use an IC comparator — you can find single-supply units that can work with input voltages close to ground.
$endgroup$
1
$begingroup$
You can approach the lower rail by using PNPs 'upside down' and a single supply.
$endgroup$
– Russell McMahon
2 days ago
$begingroup$
@RussellMcMahon: But then there's no overhead left for the load (LED), at least, not without adding additional transistors. At that point, just get the IC comparator, which is essentially the same thing.
$endgroup$
– Dave Tweed♦
2 days ago
$begingroup$
This circuit really needs some positive feedback to achieve a clean switch.
$endgroup$
– EinarA
yesterday
add a comment |
$begingroup$
No single transistor can do what you want. Instead, you need to use multiple transistors. A simple voltage comparator will do what you want:
simulate this circuit – Schematic created using CircuitLab
R2 and R3 set the reference voltage for the base of Q2. As long as the voltage at the base of Q1 is less than Vref, all of the current through R1 will flow through Q2. As soon as the input voltage rises above 0.2V, Q2 will cut off and all of the current will flow through Q1 and the LED instead.
Note that since the emitters of the transistors need to be at a negative voltage, this circuit requires a negative supply. An alternative would be to use an IC comparator — you can find single-supply units that can work with input voltages close to ground.
$endgroup$
1
$begingroup$
You can approach the lower rail by using PNPs 'upside down' and a single supply.
$endgroup$
– Russell McMahon
2 days ago
$begingroup$
@RussellMcMahon: But then there's no overhead left for the load (LED), at least, not without adding additional transistors. At that point, just get the IC comparator, which is essentially the same thing.
$endgroup$
– Dave Tweed♦
2 days ago
$begingroup$
This circuit really needs some positive feedback to achieve a clean switch.
$endgroup$
– EinarA
yesterday
add a comment |
$begingroup$
No single transistor can do what you want. Instead, you need to use multiple transistors. A simple voltage comparator will do what you want:
simulate this circuit – Schematic created using CircuitLab
R2 and R3 set the reference voltage for the base of Q2. As long as the voltage at the base of Q1 is less than Vref, all of the current through R1 will flow through Q2. As soon as the input voltage rises above 0.2V, Q2 will cut off and all of the current will flow through Q1 and the LED instead.
Note that since the emitters of the transistors need to be at a negative voltage, this circuit requires a negative supply. An alternative would be to use an IC comparator — you can find single-supply units that can work with input voltages close to ground.
$endgroup$
No single transistor can do what you want. Instead, you need to use multiple transistors. A simple voltage comparator will do what you want:
simulate this circuit – Schematic created using CircuitLab
R2 and R3 set the reference voltage for the base of Q2. As long as the voltage at the base of Q1 is less than Vref, all of the current through R1 will flow through Q2. As soon as the input voltage rises above 0.2V, Q2 will cut off and all of the current will flow through Q1 and the LED instead.
Note that since the emitters of the transistors need to be at a negative voltage, this circuit requires a negative supply. An alternative would be to use an IC comparator — you can find single-supply units that can work with input voltages close to ground.
answered 2 days ago
Dave Tweed♦Dave Tweed
124k10153268
124k10153268
1
$begingroup$
You can approach the lower rail by using PNPs 'upside down' and a single supply.
$endgroup$
– Russell McMahon
2 days ago
$begingroup$
@RussellMcMahon: But then there's no overhead left for the load (LED), at least, not without adding additional transistors. At that point, just get the IC comparator, which is essentially the same thing.
$endgroup$
– Dave Tweed♦
2 days ago
$begingroup$
This circuit really needs some positive feedback to achieve a clean switch.
$endgroup$
– EinarA
yesterday
add a comment |
1
$begingroup$
You can approach the lower rail by using PNPs 'upside down' and a single supply.
$endgroup$
– Russell McMahon
2 days ago
$begingroup$
@RussellMcMahon: But then there's no overhead left for the load (LED), at least, not without adding additional transistors. At that point, just get the IC comparator, which is essentially the same thing.
$endgroup$
– Dave Tweed♦
2 days ago
$begingroup$
This circuit really needs some positive feedback to achieve a clean switch.
$endgroup$
– EinarA
yesterday
1
1
$begingroup$
You can approach the lower rail by using PNPs 'upside down' and a single supply.
$endgroup$
– Russell McMahon
2 days ago
$begingroup$
You can approach the lower rail by using PNPs 'upside down' and a single supply.
$endgroup$
– Russell McMahon
2 days ago
$begingroup$
@RussellMcMahon: But then there's no overhead left for the load (LED), at least, not without adding additional transistors. At that point, just get the IC comparator, which is essentially the same thing.
$endgroup$
– Dave Tweed♦
2 days ago
$begingroup$
@RussellMcMahon: But then there's no overhead left for the load (LED), at least, not without adding additional transistors. At that point, just get the IC comparator, which is essentially the same thing.
$endgroup$
– Dave Tweed♦
2 days ago
$begingroup$
This circuit really needs some positive feedback to achieve a clean switch.
$endgroup$
– EinarA
yesterday
$begingroup$
This circuit really needs some positive feedback to achieve a clean switch.
$endgroup$
– EinarA
yesterday
add a comment |
$begingroup$
simulate this circuit – Schematic created using CircuitLab
You could also use an Op Amp, or a Comparator. Set one input to 0.2V, when the other input exceeds that, the output will switch.
Here's one example
https://datasheets.maximintegrated.com/en/ds/MAX9107-MAX9109.pdf
$endgroup$
add a comment |
$begingroup$
simulate this circuit – Schematic created using CircuitLab
You could also use an Op Amp, or a Comparator. Set one input to 0.2V, when the other input exceeds that, the output will switch.
Here's one example
https://datasheets.maximintegrated.com/en/ds/MAX9107-MAX9109.pdf
$endgroup$
add a comment |
$begingroup$
simulate this circuit – Schematic created using CircuitLab
You could also use an Op Amp, or a Comparator. Set one input to 0.2V, when the other input exceeds that, the output will switch.
Here's one example
https://datasheets.maximintegrated.com/en/ds/MAX9107-MAX9109.pdf
$endgroup$
simulate this circuit – Schematic created using CircuitLab
You could also use an Op Amp, or a Comparator. Set one input to 0.2V, when the other input exceeds that, the output will switch.
Here's one example
https://datasheets.maximintegrated.com/en/ds/MAX9107-MAX9109.pdf
edited 2 days ago
Dave Tweed♦
124k10153268
124k10153268
answered 2 days ago
CrossRoadsCrossRoads
2,12728
2,12728
add a comment |
add a comment |
$begingroup$
A well chosen germanium transistor can do this. I have some that switch at .15V. Finding one might be a problem ; I am not offering any of mine, but they still exist. If you need accurateness use one of the other answers, The simplest solution is to prebias a transistor so the base receives enough voltage to turn on when the input is .2V. I have used this trick in non-critical situations.
$endgroup$
add a comment |
$begingroup$
A well chosen germanium transistor can do this. I have some that switch at .15V. Finding one might be a problem ; I am not offering any of mine, but they still exist. If you need accurateness use one of the other answers, The simplest solution is to prebias a transistor so the base receives enough voltage to turn on when the input is .2V. I have used this trick in non-critical situations.
$endgroup$
add a comment |
$begingroup$
A well chosen germanium transistor can do this. I have some that switch at .15V. Finding one might be a problem ; I am not offering any of mine, but they still exist. If you need accurateness use one of the other answers, The simplest solution is to prebias a transistor so the base receives enough voltage to turn on when the input is .2V. I have used this trick in non-critical situations.
$endgroup$
A well chosen germanium transistor can do this. I have some that switch at .15V. Finding one might be a problem ; I am not offering any of mine, but they still exist. If you need accurateness use one of the other answers, The simplest solution is to prebias a transistor so the base receives enough voltage to turn on when the input is .2V. I have used this trick in non-critical situations.
answered 2 days ago
EinarAEinarA
1485
1485
add a comment |
add a comment |
seyyedali hosseini is a new contributor. Be nice, and check out our Code of Conduct.
seyyedali hosseini is a new contributor. Be nice, and check out our Code of Conduct.
seyyedali hosseini is a new contributor. Be nice, and check out our Code of Conduct.
seyyedali hosseini is a new contributor. Be nice, and check out our Code of Conduct.
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5
$begingroup$
Pretty much none of them. I would recommend amplifying the signal before trying to use it as a switch, perhaps with a comparator.
$endgroup$
– Hearth
2 days ago
6
$begingroup$
Instead of asking about a transistor which needs to turn on with only 0.2 V (there aren't any but please prove me wrong!) and assume that you can do this with only one transistor (you can't but I'd like to be proven wrong again), describe what your requirements are and ask what solutions exist. A LED will not light up with 0.2 V so there must be some other voltage present. Why 0.2 V? Do research on similar setups (switching LEDs) and learn how that's done.
$endgroup$
– Bimpelrekkie
2 days ago
2
$begingroup$
Highly related if not duplicate: electronics.stackexchange.com/questions/129183/…
$endgroup$
– winny
2 days ago
$begingroup$
0.2V isn't enough to run an LED; if you have a rail that'll drive an LED then you can use a comparator.
$endgroup$
– TimWescott
2 days ago
$begingroup$
What's the LED and what's the current and voltage it requires? What power supply rails do you have?
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– jonk
2 days ago