Get the max value from a slice of a JSON Array?












2















I would like to get the max value within a slice of a Json object (typicaly [1,2,3,5,6,7,9,10]) which is contained in a field named Data of the table raw.



The limits Start & End of the slice are contained in an other Json object named Features contained in a table named features



Here is the input:



CREATE TABLE raw (
id int PRIMARY KEY
GENERATED BY DEFAULT AS IDENTITY

data json
);

INSERT INTO raw (data) VALUES
('[1,2,3,5,6,7,9,10]');

CREATE TABLE features (
id int,
features json
);

INSERT INTO features (id, features) VALUES
(1, '{"Start" : 1, "End": 5}');


The output I would like is 7, i.e. the max value of the slice [2,3,5,6,7]



Here is what I came up with looking at other posts, but it does not work...



SELECT
R."ID",
F."Features"->>'Start' AS Start,
F."Features"->>'End' AS End,
sort_desc((array(select json_array_elements(R."Data")))[F."Features"->>'Start':F."Features"->>'End'])[1] as maxData
FROM
raw AS R
INNER JOIN
features AS F ON R."ID" = F."ID"


The approximate error message I get is concerning sort_desc :




No function corresponding to this name or this type of arguments. You
should convert the type of data











share|improve this question

























  • That's a horrible schema for this kind of query. At the very least, use jsonb, even better don't use json, use an int.

    – Evan Carroll
    7 hours ago


















2















I would like to get the max value within a slice of a Json object (typicaly [1,2,3,5,6,7,9,10]) which is contained in a field named Data of the table raw.



The limits Start & End of the slice are contained in an other Json object named Features contained in a table named features



Here is the input:



CREATE TABLE raw (
id int PRIMARY KEY
GENERATED BY DEFAULT AS IDENTITY

data json
);

INSERT INTO raw (data) VALUES
('[1,2,3,5,6,7,9,10]');

CREATE TABLE features (
id int,
features json
);

INSERT INTO features (id, features) VALUES
(1, '{"Start" : 1, "End": 5}');


The output I would like is 7, i.e. the max value of the slice [2,3,5,6,7]



Here is what I came up with looking at other posts, but it does not work...



SELECT
R."ID",
F."Features"->>'Start' AS Start,
F."Features"->>'End' AS End,
sort_desc((array(select json_array_elements(R."Data")))[F."Features"->>'Start':F."Features"->>'End'])[1] as maxData
FROM
raw AS R
INNER JOIN
features AS F ON R."ID" = F."ID"


The approximate error message I get is concerning sort_desc :




No function corresponding to this name or this type of arguments. You
should convert the type of data











share|improve this question

























  • That's a horrible schema for this kind of query. At the very least, use jsonb, even better don't use json, use an int.

    – Evan Carroll
    7 hours ago
















2












2








2








I would like to get the max value within a slice of a Json object (typicaly [1,2,3,5,6,7,9,10]) which is contained in a field named Data of the table raw.



The limits Start & End of the slice are contained in an other Json object named Features contained in a table named features



Here is the input:



CREATE TABLE raw (
id int PRIMARY KEY
GENERATED BY DEFAULT AS IDENTITY

data json
);

INSERT INTO raw (data) VALUES
('[1,2,3,5,6,7,9,10]');

CREATE TABLE features (
id int,
features json
);

INSERT INTO features (id, features) VALUES
(1, '{"Start" : 1, "End": 5}');


The output I would like is 7, i.e. the max value of the slice [2,3,5,6,7]



Here is what I came up with looking at other posts, but it does not work...



SELECT
R."ID",
F."Features"->>'Start' AS Start,
F."Features"->>'End' AS End,
sort_desc((array(select json_array_elements(R."Data")))[F."Features"->>'Start':F."Features"->>'End'])[1] as maxData
FROM
raw AS R
INNER JOIN
features AS F ON R."ID" = F."ID"


The approximate error message I get is concerning sort_desc :




No function corresponding to this name or this type of arguments. You
should convert the type of data











share|improve this question
















I would like to get the max value within a slice of a Json object (typicaly [1,2,3,5,6,7,9,10]) which is contained in a field named Data of the table raw.



The limits Start & End of the slice are contained in an other Json object named Features contained in a table named features



Here is the input:



CREATE TABLE raw (
id int PRIMARY KEY
GENERATED BY DEFAULT AS IDENTITY

data json
);

INSERT INTO raw (data) VALUES
('[1,2,3,5,6,7,9,10]');

CREATE TABLE features (
id int,
features json
);

INSERT INTO features (id, features) VALUES
(1, '{"Start" : 1, "End": 5}');


The output I would like is 7, i.e. the max value of the slice [2,3,5,6,7]



Here is what I came up with looking at other posts, but it does not work...



SELECT
R."ID",
F."Features"->>'Start' AS Start,
F."Features"->>'End' AS End,
sort_desc((array(select json_array_elements(R."Data")))[F."Features"->>'Start':F."Features"->>'End'])[1] as maxData
FROM
raw AS R
INNER JOIN
features AS F ON R."ID" = F."ID"


The approximate error message I get is concerning sort_desc :




No function corresponding to this name or this type of arguments. You
should convert the type of data








postgresql json array postgresql-11






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 6 hours ago









Evan Carroll

31.5k965213




31.5k965213










asked 10 hours ago









MaximeMaxime

153




153













  • That's a horrible schema for this kind of query. At the very least, use jsonb, even better don't use json, use an int.

    – Evan Carroll
    7 hours ago





















  • That's a horrible schema for this kind of query. At the very least, use jsonb, even better don't use json, use an int.

    – Evan Carroll
    7 hours ago



















That's a horrible schema for this kind of query. At the very least, use jsonb, even better don't use json, use an int.

– Evan Carroll
7 hours ago







That's a horrible schema for this kind of query. At the very least, use jsonb, even better don't use json, use an int.

– Evan Carroll
7 hours ago












2 Answers
2






active

oldest

votes


















2














You can unnest json array:



Postgres WITH ORDINALITY:




When a function in the FROM clause is suffixed by WITH ORDINALITY, a bigint column is appended to the output which starts from 1 and increments by 1 for each row of the function's output. This is most useful in the case of set returning functions such as unnest().




Have a look at this answer of Erwin Brandstetter:




  • PostgreSQL unnest() with element number


  SELECT
r."ID",
MAX(t.elem::int) MaxElem
FROM
raw r
JOIN
features f
ON f."ID" = r."ID"
JOIN LATERAL
json_array_elements_text(r."Data")
WITH ORDINALITY AS t(elem, n) ON TRUE
WHERE
n >= (f."Features"->>'Start')::int + 1
AND
n <= (f."Features"->>'End')::int + 1
GROUP BY
r."ID";




ID | maxelem
-: | ------:
1 | 7



db<>fiddle here



Or if you prefer to use intarray module:



SELECT
r."ID",
(sort_desc(((ARRAY(SELECT json_array_elements_text(r."Data")))::int)[(f."Features"->>'Start')::int + 1:(f."Features"->>'End')::int + 1]))[1]
FROM
raw r
JOIN
features f
ON f."ID" = r."ID";


rextester here






share|improve this answer





















  • 1





    I upvoted for doing what he wanted, but there is something to be said here for not doing this at all lol

    – Evan Carroll
    6 hours ago



















1














This is all around a horrible schema. You shouldn't be using json (as compared with jsonb) at all, ever (practically). If you're querying on the field, it should be jsonb. In your case, that's still a bad idea though, you likely want an sql array..



CREATE TABLE raw (
raw_id int PRIMARY KEY
GENERATED BY DEFAULT AS IDENTITY,
data int
);

INSERT INTO raw (data) VALUES ('{1,2,3,5,6,7,9,10}');

CREATE TABLE features (
feature_id int REFERENCES raw,
low smallint,
high smallint
);

INSERT INTO features ( feature_id, low, high ) VALUES ( 1, 1, 5 );


Now you can query it like this, note remember sql is 1-based,



SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(data[f.low:f.high]);




Also check out the intarray module, because it'll optimize the above,



CREATE EXTENSION intarray;

SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(subarray(data,f.low,f.high-f.low+1))


You can further optimize this if you know you just need the last element of the array.





Note if this is a GIS problem, you're still probably doing it wrong, but at least this method is sane.






share|improve this answer





















  • 1





    Now it is said. Nice answer. But I think subarray requires start, lenght. subarray(data,f.low,f.high-f.low+1)

    – McNets
    6 hours ago













  • Good catch! @McNets

    – Evan Carroll
    6 hours ago











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














You can unnest json array:



Postgres WITH ORDINALITY:




When a function in the FROM clause is suffixed by WITH ORDINALITY, a bigint column is appended to the output which starts from 1 and increments by 1 for each row of the function's output. This is most useful in the case of set returning functions such as unnest().




Have a look at this answer of Erwin Brandstetter:




  • PostgreSQL unnest() with element number


  SELECT
r."ID",
MAX(t.elem::int) MaxElem
FROM
raw r
JOIN
features f
ON f."ID" = r."ID"
JOIN LATERAL
json_array_elements_text(r."Data")
WITH ORDINALITY AS t(elem, n) ON TRUE
WHERE
n >= (f."Features"->>'Start')::int + 1
AND
n <= (f."Features"->>'End')::int + 1
GROUP BY
r."ID";




ID | maxelem
-: | ------:
1 | 7



db<>fiddle here



Or if you prefer to use intarray module:



SELECT
r."ID",
(sort_desc(((ARRAY(SELECT json_array_elements_text(r."Data")))::int)[(f."Features"->>'Start')::int + 1:(f."Features"->>'End')::int + 1]))[1]
FROM
raw r
JOIN
features f
ON f."ID" = r."ID";


rextester here






share|improve this answer





















  • 1





    I upvoted for doing what he wanted, but there is something to be said here for not doing this at all lol

    – Evan Carroll
    6 hours ago
















2














You can unnest json array:



Postgres WITH ORDINALITY:




When a function in the FROM clause is suffixed by WITH ORDINALITY, a bigint column is appended to the output which starts from 1 and increments by 1 for each row of the function's output. This is most useful in the case of set returning functions such as unnest().




Have a look at this answer of Erwin Brandstetter:




  • PostgreSQL unnest() with element number


  SELECT
r."ID",
MAX(t.elem::int) MaxElem
FROM
raw r
JOIN
features f
ON f."ID" = r."ID"
JOIN LATERAL
json_array_elements_text(r."Data")
WITH ORDINALITY AS t(elem, n) ON TRUE
WHERE
n >= (f."Features"->>'Start')::int + 1
AND
n <= (f."Features"->>'End')::int + 1
GROUP BY
r."ID";




ID | maxelem
-: | ------:
1 | 7



db<>fiddle here



Or if you prefer to use intarray module:



SELECT
r."ID",
(sort_desc(((ARRAY(SELECT json_array_elements_text(r."Data")))::int)[(f."Features"->>'Start')::int + 1:(f."Features"->>'End')::int + 1]))[1]
FROM
raw r
JOIN
features f
ON f."ID" = r."ID";


rextester here






share|improve this answer





















  • 1





    I upvoted for doing what he wanted, but there is something to be said here for not doing this at all lol

    – Evan Carroll
    6 hours ago














2












2








2







You can unnest json array:



Postgres WITH ORDINALITY:




When a function in the FROM clause is suffixed by WITH ORDINALITY, a bigint column is appended to the output which starts from 1 and increments by 1 for each row of the function's output. This is most useful in the case of set returning functions such as unnest().




Have a look at this answer of Erwin Brandstetter:




  • PostgreSQL unnest() with element number


  SELECT
r."ID",
MAX(t.elem::int) MaxElem
FROM
raw r
JOIN
features f
ON f."ID" = r."ID"
JOIN LATERAL
json_array_elements_text(r."Data")
WITH ORDINALITY AS t(elem, n) ON TRUE
WHERE
n >= (f."Features"->>'Start')::int + 1
AND
n <= (f."Features"->>'End')::int + 1
GROUP BY
r."ID";




ID | maxelem
-: | ------:
1 | 7



db<>fiddle here



Or if you prefer to use intarray module:



SELECT
r."ID",
(sort_desc(((ARRAY(SELECT json_array_elements_text(r."Data")))::int)[(f."Features"->>'Start')::int + 1:(f."Features"->>'End')::int + 1]))[1]
FROM
raw r
JOIN
features f
ON f."ID" = r."ID";


rextester here






share|improve this answer















You can unnest json array:



Postgres WITH ORDINALITY:




When a function in the FROM clause is suffixed by WITH ORDINALITY, a bigint column is appended to the output which starts from 1 and increments by 1 for each row of the function's output. This is most useful in the case of set returning functions such as unnest().




Have a look at this answer of Erwin Brandstetter:




  • PostgreSQL unnest() with element number


  SELECT
r."ID",
MAX(t.elem::int) MaxElem
FROM
raw r
JOIN
features f
ON f."ID" = r."ID"
JOIN LATERAL
json_array_elements_text(r."Data")
WITH ORDINALITY AS t(elem, n) ON TRUE
WHERE
n >= (f."Features"->>'Start')::int + 1
AND
n <= (f."Features"->>'End')::int + 1
GROUP BY
r."ID";




ID | maxelem
-: | ------:
1 | 7



db<>fiddle here



Or if you prefer to use intarray module:



SELECT
r."ID",
(sort_desc(((ARRAY(SELECT json_array_elements_text(r."Data")))::int)[(f."Features"->>'Start')::int + 1:(f."Features"->>'End')::int + 1]))[1]
FROM
raw r
JOIN
features f
ON f."ID" = r."ID";


rextester here







share|improve this answer














share|improve this answer



share|improve this answer








edited 7 hours ago

























answered 8 hours ago









McNetsMcNets

15.4k41858




15.4k41858








  • 1





    I upvoted for doing what he wanted, but there is something to be said here for not doing this at all lol

    – Evan Carroll
    6 hours ago














  • 1





    I upvoted for doing what he wanted, but there is something to be said here for not doing this at all lol

    – Evan Carroll
    6 hours ago








1




1





I upvoted for doing what he wanted, but there is something to be said here for not doing this at all lol

– Evan Carroll
6 hours ago





I upvoted for doing what he wanted, but there is something to be said here for not doing this at all lol

– Evan Carroll
6 hours ago













1














This is all around a horrible schema. You shouldn't be using json (as compared with jsonb) at all, ever (practically). If you're querying on the field, it should be jsonb. In your case, that's still a bad idea though, you likely want an sql array..



CREATE TABLE raw (
raw_id int PRIMARY KEY
GENERATED BY DEFAULT AS IDENTITY,
data int
);

INSERT INTO raw (data) VALUES ('{1,2,3,5,6,7,9,10}');

CREATE TABLE features (
feature_id int REFERENCES raw,
low smallint,
high smallint
);

INSERT INTO features ( feature_id, low, high ) VALUES ( 1, 1, 5 );


Now you can query it like this, note remember sql is 1-based,



SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(data[f.low:f.high]);




Also check out the intarray module, because it'll optimize the above,



CREATE EXTENSION intarray;

SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(subarray(data,f.low,f.high-f.low+1))


You can further optimize this if you know you just need the last element of the array.





Note if this is a GIS problem, you're still probably doing it wrong, but at least this method is sane.






share|improve this answer





















  • 1





    Now it is said. Nice answer. But I think subarray requires start, lenght. subarray(data,f.low,f.high-f.low+1)

    – McNets
    6 hours ago













  • Good catch! @McNets

    – Evan Carroll
    6 hours ago
















1














This is all around a horrible schema. You shouldn't be using json (as compared with jsonb) at all, ever (practically). If you're querying on the field, it should be jsonb. In your case, that's still a bad idea though, you likely want an sql array..



CREATE TABLE raw (
raw_id int PRIMARY KEY
GENERATED BY DEFAULT AS IDENTITY,
data int
);

INSERT INTO raw (data) VALUES ('{1,2,3,5,6,7,9,10}');

CREATE TABLE features (
feature_id int REFERENCES raw,
low smallint,
high smallint
);

INSERT INTO features ( feature_id, low, high ) VALUES ( 1, 1, 5 );


Now you can query it like this, note remember sql is 1-based,



SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(data[f.low:f.high]);




Also check out the intarray module, because it'll optimize the above,



CREATE EXTENSION intarray;

SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(subarray(data,f.low,f.high-f.low+1))


You can further optimize this if you know you just need the last element of the array.





Note if this is a GIS problem, you're still probably doing it wrong, but at least this method is sane.






share|improve this answer





















  • 1





    Now it is said. Nice answer. But I think subarray requires start, lenght. subarray(data,f.low,f.high-f.low+1)

    – McNets
    6 hours ago













  • Good catch! @McNets

    – Evan Carroll
    6 hours ago














1












1








1







This is all around a horrible schema. You shouldn't be using json (as compared with jsonb) at all, ever (practically). If you're querying on the field, it should be jsonb. In your case, that's still a bad idea though, you likely want an sql array..



CREATE TABLE raw (
raw_id int PRIMARY KEY
GENERATED BY DEFAULT AS IDENTITY,
data int
);

INSERT INTO raw (data) VALUES ('{1,2,3,5,6,7,9,10}');

CREATE TABLE features (
feature_id int REFERENCES raw,
low smallint,
high smallint
);

INSERT INTO features ( feature_id, low, high ) VALUES ( 1, 1, 5 );


Now you can query it like this, note remember sql is 1-based,



SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(data[f.low:f.high]);




Also check out the intarray module, because it'll optimize the above,



CREATE EXTENSION intarray;

SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(subarray(data,f.low,f.high-f.low+1))


You can further optimize this if you know you just need the last element of the array.





Note if this is a GIS problem, you're still probably doing it wrong, but at least this method is sane.






share|improve this answer















This is all around a horrible schema. You shouldn't be using json (as compared with jsonb) at all, ever (practically). If you're querying on the field, it should be jsonb. In your case, that's still a bad idea though, you likely want an sql array..



CREATE TABLE raw (
raw_id int PRIMARY KEY
GENERATED BY DEFAULT AS IDENTITY,
data int
);

INSERT INTO raw (data) VALUES ('{1,2,3,5,6,7,9,10}');

CREATE TABLE features (
feature_id int REFERENCES raw,
low smallint,
high smallint
);

INSERT INTO features ( feature_id, low, high ) VALUES ( 1, 1, 5 );


Now you can query it like this, note remember sql is 1-based,



SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(data[f.low:f.high]);




Also check out the intarray module, because it'll optimize the above,



CREATE EXTENSION intarray;

SELECT max(unnest)
FROM raw
CROSS JOIN features AS f
CROSS JOIN LATERAL unnest(subarray(data,f.low,f.high-f.low+1))


You can further optimize this if you know you just need the last element of the array.





Note if this is a GIS problem, you're still probably doing it wrong, but at least this method is sane.







share|improve this answer














share|improve this answer



share|improve this answer








edited 6 hours ago

























answered 7 hours ago









Evan CarrollEvan Carroll

31.5k965213




31.5k965213








  • 1





    Now it is said. Nice answer. But I think subarray requires start, lenght. subarray(data,f.low,f.high-f.low+1)

    – McNets
    6 hours ago













  • Good catch! @McNets

    – Evan Carroll
    6 hours ago














  • 1





    Now it is said. Nice answer. But I think subarray requires start, lenght. subarray(data,f.low,f.high-f.low+1)

    – McNets
    6 hours ago













  • Good catch! @McNets

    – Evan Carroll
    6 hours ago








1




1





Now it is said. Nice answer. But I think subarray requires start, lenght. subarray(data,f.low,f.high-f.low+1)

– McNets
6 hours ago







Now it is said. Nice answer. But I think subarray requires start, lenght. subarray(data,f.low,f.high-f.low+1)

– McNets
6 hours ago















Good catch! @McNets

– Evan Carroll
6 hours ago





Good catch! @McNets

– Evan Carroll
6 hours ago


















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