Output the Arecibo Message












33












$begingroup$



The Arecibo message is a 1974 interstellar radio message carrying basic information about humanity and Earth sent to globular star cluster M13 in the hope that extraterrestrial intelligence might receive and decipher it... The message consisted of 1,679 binary digits, approximately 210 bytes...



The number 1,679 was chosen because it is a semiprime (the product of two prime numbers), to be arranged rectangularly as 73 rows by 23 columns. The alternative arrangement, 23 rows by 73 columns, produces an unintelligible set of characters (as do all other X/Y formats).



The Arecibo Message



This is the message with color added to highlight its separate parts. The actual binary transmission carried no color information.




Source: Wikipedia





Your task is to output the Arecibo Message in the exact 23x73 arrangement shown in the image. Any of these output formats is acceptable:




  • Text, using one character for ones and another for zeros (using the usual rules for row separation)

  • A 2D array of two distinct values

  • A 23x73 image with two distinct colors

  • Aan uninterrupted stream of 1679 items of two distinct values (i.e. any of the above formats, but flat.)

  • A 1679-bit integer. Indicate bit and byte order (endianness) in your solution.


For your convenience, here is a copy-pastable version (also an example output in text format):



00000010101010000000000
00101000001010000000100
10001000100010010110010
10101010101010100100100
00000000000000000000000
00000000000011000000000
00000000001101000000000
00000000001101000000000
00000000010101000000000
00000000011111000000000
00000000000000000000000
11000011100011000011000
10000000000000110010000
11010001100011000011010
11111011111011111011111
00000000000000000000000
00010000000000000000010
00000000000000000000000
00001000000000000000001
11111000000000000011111
00000000000000000000000
11000011000011100011000
10000000100000000010000
11010000110001110011010
11111011111011111011111
00000000000000000000000
00010000001100000000010
00000000001100000000000
00001000001100000000001
11111000001100000011111
00000000001100000000000
00100000000100000000100
00010000001100000001000
00001100001100000010000
00000011000100001100000
00000000001100110000000
00000011000100001100000
00001100001100000010000
00010000001000000001000
00100000001100000000100
01000000001100000000100
01000000000100000001000
00100000001000000010000
00010000000000001100000
00001100000000110000000
00100011101011000000000
00100000001000000000000
00100000111110000000000
00100001011101001011011
00000010011100100111111
10111000011100000110111
00000000010100000111011
00100000010100000111111
00100000010100000110000
00100000110110000000000
00000000000000000000000
00111000001000000000000
00111010100010101010101
00111000000000101010100
00000000000000101000000
00000000111110000000000
00000011111111100000000
00001110000000111000000
00011000000000001100000
00110100000000010110000
01100110000000110011000
01000101000001010001000
01000100100010010001000
00000100010100010000000
00000100001000010000000
00000100000000010000000
00000001001010000000000
01111001111101001111000


If your language, for some reason, has a builtin for the Arecibo Message, you may not use that builtin.



Good Luck!



UPDATE: I accepted the 05AB1E answer since it was the first one to be shorter than the original message. Don't let that dissuade you from new solutions.










share|improve this question











$endgroup$








  • 8




    $begingroup$
    If a language has a built in for Arecibo message, I can tell, with all certainty, that I've seen everything in this world c:
    $endgroup$
    – Luis felipe De jesus Munoz
    2 days ago








  • 5




    $begingroup$
    Mathematica (IIRC) has an image builtin for Lena, so it wouldn't surprise me if it also has an Aricebo message as well.
    $endgroup$
    – Beefster
    2 days ago










  • $begingroup$
    @RobertS. no because there are other valid formats besides text.
    $endgroup$
    – Beefster
    2 days ago






  • 3




    $begingroup$
    In the spirit of the original format, a flat result/output should be allowed. The whole point of 1679 bits is exactly that the proper number of rows and columns can be inferred from the signal length.
    $endgroup$
    – Adám
    2 days ago






  • 4




    $begingroup$
    @LuisfelipeDejesusMunoz Mathematica has a builtin to determine goats in a picture, so an Arecibo message builtin wouldn't really surprise me either.. That language is built on builtins of the universe.. >.>
    $endgroup$
    – Kevin Cruijssen
    yesterday
















33












$begingroup$



The Arecibo message is a 1974 interstellar radio message carrying basic information about humanity and Earth sent to globular star cluster M13 in the hope that extraterrestrial intelligence might receive and decipher it... The message consisted of 1,679 binary digits, approximately 210 bytes...



The number 1,679 was chosen because it is a semiprime (the product of two prime numbers), to be arranged rectangularly as 73 rows by 23 columns. The alternative arrangement, 23 rows by 73 columns, produces an unintelligible set of characters (as do all other X/Y formats).



The Arecibo Message



This is the message with color added to highlight its separate parts. The actual binary transmission carried no color information.




Source: Wikipedia





Your task is to output the Arecibo Message in the exact 23x73 arrangement shown in the image. Any of these output formats is acceptable:




  • Text, using one character for ones and another for zeros (using the usual rules for row separation)

  • A 2D array of two distinct values

  • A 23x73 image with two distinct colors

  • Aan uninterrupted stream of 1679 items of two distinct values (i.e. any of the above formats, but flat.)

  • A 1679-bit integer. Indicate bit and byte order (endianness) in your solution.


For your convenience, here is a copy-pastable version (also an example output in text format):



00000010101010000000000
00101000001010000000100
10001000100010010110010
10101010101010100100100
00000000000000000000000
00000000000011000000000
00000000001101000000000
00000000001101000000000
00000000010101000000000
00000000011111000000000
00000000000000000000000
11000011100011000011000
10000000000000110010000
11010001100011000011010
11111011111011111011111
00000000000000000000000
00010000000000000000010
00000000000000000000000
00001000000000000000001
11111000000000000011111
00000000000000000000000
11000011000011100011000
10000000100000000010000
11010000110001110011010
11111011111011111011111
00000000000000000000000
00010000001100000000010
00000000001100000000000
00001000001100000000001
11111000001100000011111
00000000001100000000000
00100000000100000000100
00010000001100000001000
00001100001100000010000
00000011000100001100000
00000000001100110000000
00000011000100001100000
00001100001100000010000
00010000001000000001000
00100000001100000000100
01000000001100000000100
01000000000100000001000
00100000001000000010000
00010000000000001100000
00001100000000110000000
00100011101011000000000
00100000001000000000000
00100000111110000000000
00100001011101001011011
00000010011100100111111
10111000011100000110111
00000000010100000111011
00100000010100000111111
00100000010100000110000
00100000110110000000000
00000000000000000000000
00111000001000000000000
00111010100010101010101
00111000000000101010100
00000000000000101000000
00000000111110000000000
00000011111111100000000
00001110000000111000000
00011000000000001100000
00110100000000010110000
01100110000000110011000
01000101000001010001000
01000100100010010001000
00000100010100010000000
00000100001000010000000
00000100000000010000000
00000001001010000000000
01111001111101001111000


If your language, for some reason, has a builtin for the Arecibo Message, you may not use that builtin.



Good Luck!



UPDATE: I accepted the 05AB1E answer since it was the first one to be shorter than the original message. Don't let that dissuade you from new solutions.










share|improve this question











$endgroup$








  • 8




    $begingroup$
    If a language has a built in for Arecibo message, I can tell, with all certainty, that I've seen everything in this world c:
    $endgroup$
    – Luis felipe De jesus Munoz
    2 days ago








  • 5




    $begingroup$
    Mathematica (IIRC) has an image builtin for Lena, so it wouldn't surprise me if it also has an Aricebo message as well.
    $endgroup$
    – Beefster
    2 days ago










  • $begingroup$
    @RobertS. no because there are other valid formats besides text.
    $endgroup$
    – Beefster
    2 days ago






  • 3




    $begingroup$
    In the spirit of the original format, a flat result/output should be allowed. The whole point of 1679 bits is exactly that the proper number of rows and columns can be inferred from the signal length.
    $endgroup$
    – Adám
    2 days ago






  • 4




    $begingroup$
    @LuisfelipeDejesusMunoz Mathematica has a builtin to determine goats in a picture, so an Arecibo message builtin wouldn't really surprise me either.. That language is built on builtins of the universe.. >.>
    $endgroup$
    – Kevin Cruijssen
    yesterday














33












33








33


6



$begingroup$



The Arecibo message is a 1974 interstellar radio message carrying basic information about humanity and Earth sent to globular star cluster M13 in the hope that extraterrestrial intelligence might receive and decipher it... The message consisted of 1,679 binary digits, approximately 210 bytes...



The number 1,679 was chosen because it is a semiprime (the product of two prime numbers), to be arranged rectangularly as 73 rows by 23 columns. The alternative arrangement, 23 rows by 73 columns, produces an unintelligible set of characters (as do all other X/Y formats).



The Arecibo Message



This is the message with color added to highlight its separate parts. The actual binary transmission carried no color information.




Source: Wikipedia





Your task is to output the Arecibo Message in the exact 23x73 arrangement shown in the image. Any of these output formats is acceptable:




  • Text, using one character for ones and another for zeros (using the usual rules for row separation)

  • A 2D array of two distinct values

  • A 23x73 image with two distinct colors

  • Aan uninterrupted stream of 1679 items of two distinct values (i.e. any of the above formats, but flat.)

  • A 1679-bit integer. Indicate bit and byte order (endianness) in your solution.


For your convenience, here is a copy-pastable version (also an example output in text format):



00000010101010000000000
00101000001010000000100
10001000100010010110010
10101010101010100100100
00000000000000000000000
00000000000011000000000
00000000001101000000000
00000000001101000000000
00000000010101000000000
00000000011111000000000
00000000000000000000000
11000011100011000011000
10000000000000110010000
11010001100011000011010
11111011111011111011111
00000000000000000000000
00010000000000000000010
00000000000000000000000
00001000000000000000001
11111000000000000011111
00000000000000000000000
11000011000011100011000
10000000100000000010000
11010000110001110011010
11111011111011111011111
00000000000000000000000
00010000001100000000010
00000000001100000000000
00001000001100000000001
11111000001100000011111
00000000001100000000000
00100000000100000000100
00010000001100000001000
00001100001100000010000
00000011000100001100000
00000000001100110000000
00000011000100001100000
00001100001100000010000
00010000001000000001000
00100000001100000000100
01000000001100000000100
01000000000100000001000
00100000001000000010000
00010000000000001100000
00001100000000110000000
00100011101011000000000
00100000001000000000000
00100000111110000000000
00100001011101001011011
00000010011100100111111
10111000011100000110111
00000000010100000111011
00100000010100000111111
00100000010100000110000
00100000110110000000000
00000000000000000000000
00111000001000000000000
00111010100010101010101
00111000000000101010100
00000000000000101000000
00000000111110000000000
00000011111111100000000
00001110000000111000000
00011000000000001100000
00110100000000010110000
01100110000000110011000
01000101000001010001000
01000100100010010001000
00000100010100010000000
00000100001000010000000
00000100000000010000000
00000001001010000000000
01111001111101001111000


If your language, for some reason, has a builtin for the Arecibo Message, you may not use that builtin.



Good Luck!



UPDATE: I accepted the 05AB1E answer since it was the first one to be shorter than the original message. Don't let that dissuade you from new solutions.










share|improve this question











$endgroup$





The Arecibo message is a 1974 interstellar radio message carrying basic information about humanity and Earth sent to globular star cluster M13 in the hope that extraterrestrial intelligence might receive and decipher it... The message consisted of 1,679 binary digits, approximately 210 bytes...



The number 1,679 was chosen because it is a semiprime (the product of two prime numbers), to be arranged rectangularly as 73 rows by 23 columns. The alternative arrangement, 23 rows by 73 columns, produces an unintelligible set of characters (as do all other X/Y formats).



The Arecibo Message



This is the message with color added to highlight its separate parts. The actual binary transmission carried no color information.




Source: Wikipedia





Your task is to output the Arecibo Message in the exact 23x73 arrangement shown in the image. Any of these output formats is acceptable:




  • Text, using one character for ones and another for zeros (using the usual rules for row separation)

  • A 2D array of two distinct values

  • A 23x73 image with two distinct colors

  • Aan uninterrupted stream of 1679 items of two distinct values (i.e. any of the above formats, but flat.)

  • A 1679-bit integer. Indicate bit and byte order (endianness) in your solution.


For your convenience, here is a copy-pastable version (also an example output in text format):



00000010101010000000000
00101000001010000000100
10001000100010010110010
10101010101010100100100
00000000000000000000000
00000000000011000000000
00000000001101000000000
00000000001101000000000
00000000010101000000000
00000000011111000000000
00000000000000000000000
11000011100011000011000
10000000000000110010000
11010001100011000011010
11111011111011111011111
00000000000000000000000
00010000000000000000010
00000000000000000000000
00001000000000000000001
11111000000000000011111
00000000000000000000000
11000011000011100011000
10000000100000000010000
11010000110001110011010
11111011111011111011111
00000000000000000000000
00010000001100000000010
00000000001100000000000
00001000001100000000001
11111000001100000011111
00000000001100000000000
00100000000100000000100
00010000001100000001000
00001100001100000010000
00000011000100001100000
00000000001100110000000
00000011000100001100000
00001100001100000010000
00010000001000000001000
00100000001100000000100
01000000001100000000100
01000000000100000001000
00100000001000000010000
00010000000000001100000
00001100000000110000000
00100011101011000000000
00100000001000000000000
00100000111110000000000
00100001011101001011011
00000010011100100111111
10111000011100000110111
00000000010100000111011
00100000010100000111111
00100000010100000110000
00100000110110000000000
00000000000000000000000
00111000001000000000000
00111010100010101010101
00111000000000101010100
00000000000000101000000
00000000111110000000000
00000011111111100000000
00001110000000111000000
00011000000000001100000
00110100000000010110000
01100110000000110011000
01000101000001010001000
01000100100010010001000
00000100010100010000000
00000100001000010000000
00000100000000010000000
00000001001010000000000
01111001111101001111000


If your language, for some reason, has a builtin for the Arecibo Message, you may not use that builtin.



Good Luck!



UPDATE: I accepted the 05AB1E answer since it was the first one to be shorter than the original message. Don't let that dissuade you from new solutions.







code-golf kolmogorov-complexity






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 8 hours ago







Beefster

















asked 2 days ago









BeefsterBeefster

2,6771344




2,6771344








  • 8




    $begingroup$
    If a language has a built in for Arecibo message, I can tell, with all certainty, that I've seen everything in this world c:
    $endgroup$
    – Luis felipe De jesus Munoz
    2 days ago








  • 5




    $begingroup$
    Mathematica (IIRC) has an image builtin for Lena, so it wouldn't surprise me if it also has an Aricebo message as well.
    $endgroup$
    – Beefster
    2 days ago










  • $begingroup$
    @RobertS. no because there are other valid formats besides text.
    $endgroup$
    – Beefster
    2 days ago






  • 3




    $begingroup$
    In the spirit of the original format, a flat result/output should be allowed. The whole point of 1679 bits is exactly that the proper number of rows and columns can be inferred from the signal length.
    $endgroup$
    – Adám
    2 days ago






  • 4




    $begingroup$
    @LuisfelipeDejesusMunoz Mathematica has a builtin to determine goats in a picture, so an Arecibo message builtin wouldn't really surprise me either.. That language is built on builtins of the universe.. >.>
    $endgroup$
    – Kevin Cruijssen
    yesterday














  • 8




    $begingroup$
    If a language has a built in for Arecibo message, I can tell, with all certainty, that I've seen everything in this world c:
    $endgroup$
    – Luis felipe De jesus Munoz
    2 days ago








  • 5




    $begingroup$
    Mathematica (IIRC) has an image builtin for Lena, so it wouldn't surprise me if it also has an Aricebo message as well.
    $endgroup$
    – Beefster
    2 days ago










  • $begingroup$
    @RobertS. no because there are other valid formats besides text.
    $endgroup$
    – Beefster
    2 days ago






  • 3




    $begingroup$
    In the spirit of the original format, a flat result/output should be allowed. The whole point of 1679 bits is exactly that the proper number of rows and columns can be inferred from the signal length.
    $endgroup$
    – Adám
    2 days ago






  • 4




    $begingroup$
    @LuisfelipeDejesusMunoz Mathematica has a builtin to determine goats in a picture, so an Arecibo message builtin wouldn't really surprise me either.. That language is built on builtins of the universe.. >.>
    $endgroup$
    – Kevin Cruijssen
    yesterday








8




8




$begingroup$
If a language has a built in for Arecibo message, I can tell, with all certainty, that I've seen everything in this world c:
$endgroup$
– Luis felipe De jesus Munoz
2 days ago






$begingroup$
If a language has a built in for Arecibo message, I can tell, with all certainty, that I've seen everything in this world c:
$endgroup$
– Luis felipe De jesus Munoz
2 days ago






5




5




$begingroup$
Mathematica (IIRC) has an image builtin for Lena, so it wouldn't surprise me if it also has an Aricebo message as well.
$endgroup$
– Beefster
2 days ago




$begingroup$
Mathematica (IIRC) has an image builtin for Lena, so it wouldn't surprise me if it also has an Aricebo message as well.
$endgroup$
– Beefster
2 days ago












$begingroup$
@RobertS. no because there are other valid formats besides text.
$endgroup$
– Beefster
2 days ago




$begingroup$
@RobertS. no because there are other valid formats besides text.
$endgroup$
– Beefster
2 days ago




3




3




$begingroup$
In the spirit of the original format, a flat result/output should be allowed. The whole point of 1679 bits is exactly that the proper number of rows and columns can be inferred from the signal length.
$endgroup$
– Adám
2 days ago




$begingroup$
In the spirit of the original format, a flat result/output should be allowed. The whole point of 1679 bits is exactly that the proper number of rows and columns can be inferred from the signal length.
$endgroup$
– Adám
2 days ago




4




4




$begingroup$
@LuisfelipeDejesusMunoz Mathematica has a builtin to determine goats in a picture, so an Arecibo message builtin wouldn't really surprise me either.. That language is built on builtins of the universe.. >.>
$endgroup$
– Kevin Cruijssen
yesterday




$begingroup$
@LuisfelipeDejesusMunoz Mathematica has a builtin to determine goats in a picture, so an Arecibo message builtin wouldn't really surprise me either.. That language is built on builtins of the universe.. >.>
$endgroup$
– Kevin Cruijssen
yesterday










19 Answers
19






active

oldest

votes


















11












$begingroup$


05AB1E, 215 210 200 bytes



Saved 15 bytes thanks to Magic Octopus Urn



•cOž¤4é57ñΛÖ₃BαöĀíL½₅üBdoÙRθLγ¨G×Tćú$G(˜ƒ¦!€R»SDrµCnJ†d∊ζ·<8‡T@|‹ï=BζćósxGÙÎ$¿o₁5/ÔŸÇBûXé-”a::Ž]°∊y;ζ]MÜβ‘иL”β{üÃÇíäc€÷›ÎU=}¨иaŸdY`»¾ÚUβ:ô©¦β†₅DGŠβ3Jêθ,äá!ícqšVÖ›lÈΣ¯pε €êʃDpÙ/¬Žλ8:ãÿ3=€.Þć•3BY¾4×:


Try it online!
or with Additional formatting



Base-255 encoded trinary string with occurrences of 0000 replaced by 2.






share|improve this answer











$endgroup$













  • $begingroup$
    @MagicOctopusUrn: Thanks! That makes it 210 even :)
    $endgroup$
    – Emigna
    yesterday










  • $begingroup$
    It's actually even better if you replace 0000 with 2 by 9 more bytes. - pastebin.com/aZ6tHxjx for 201
    $endgroup$
    – Magic Octopus Urn
    yesterday












  • $begingroup$
    @MagicOctopusUrn: Yes, I found that as well and was just about to post it :)
    $endgroup$
    – Emigna
    yesterday






  • 1




    $begingroup$
    Cool! Since the Arecibo messages is 210 bytes (23 * 73 / 8 = 209.875), your solution (currently at 200 bytes) is shorter than the message itself!
    $endgroup$
    – J-L
    9 hours ago










  • $begingroup$
    I went ahead and made this the accepted answer since it was the first one to be shorter than the message itself.
    $endgroup$
    – Beefster
    8 hours ago



















9












$begingroup$

Java, 688 678 590 379 361 bytes



Returns a string.



n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replace("2","0000")


-10 bytes by returning the raw stream (old answer)

-88 bytes by using base 10 numerics (thanks @ceilingcat!)

-211 bytes (I knew it could be golfed!) by using a base-36 encoded BigInteger (thanks @JollyJoker!)

-18 bytes by using a different encoded integer (thanks again @JollyJoker)


Try it online!



Explanation:



n->new java.math.BigInteger("base36 string",36)              // Decode the base-36 integer.
.toString(3) // Re-encode as ternary
.replace("2","0000") // Replace 2 with "0000"
// Implicit return





share|improve this answer











$endgroup$













  • $begingroup$
    Comments are not for extended discussion; this conversation has been moved to chat.
    $endgroup$
    – Adam Lear
    3 hours ago



















8












$begingroup$


Jelly, 213 bytes



“H²ɓ¶Ṡḷ€ẹ]ƒf*ḳḢ&ƁṇOḥ{ḄṫwỊ+oLạʋߢH9¢¹÷ỴɗÇ⁶ƲƙæḊẋ3³=1!VƇƁ'D⁺3Ỵɱ©⁵%fȯez#ƈjƒżṆo.ZF⁶ċṢ⁶ọṛb9Ȯƒd?ƁUĠt4ẇ,ḞġƒµƭfʠƁP§÷øȤŻPɲẋ(¢ß¢(⁽3¶ṙėɗy@ṁYȮL~e⁷ƤĊ§nỊṅµṠ°@7ẠB>Ġ⁻İ}uy¡½:esOpḢt}qS©HÞṬĖṛṇḣ9÷;ESḢ,Ẉ^ṙpƲ©tṃwçnẒṆ¡⁻Jıƒị£-&Ɱ*ẋʂżoȯÑḢɼ’


Try it online!



I played around with Huffman coding, but the improvements in data size were outweighed by the extra code. As such, this is simply a base-250 encoded version of the desired output. Output consists of an integer that when decoded as bijective base 2 will yield the 1D list of 1s and 2s. Thanks @Emigna for pointing out the change in rules.



Try it online - with further decoding to demonstrate output!



If a more conventional binary encoding is preferred, here is one that encodes an integer representation of the inverted binary message. The most significant bit of the integer represents the beginning of the message.






share|improve this answer











$endgroup$





















    6












    $begingroup$

    Brainfuck, 2360 2008 1938 bytes



    -[>+<-----]>---......+.-.+.-.+.-.+.-............+.-.+.-.....+.-.+.-.......+.-.<++++[->.+.-..<]>+.-.+..-.<+++++++++[->.+.-<]>..+.-..+.-<++++++[->......<]>.+.<++[->.-...................+..-.+<]>.-..................+.-.+.-.+.-..................+.....-<++++++++[->....<]>+..-....+...-...+..-....+..-...+.-.............+..-..+.-....+..-.+.-...+..-...+..-....+..-.+<++++[->.-.+....<]>.-<+++++[->.....<]>.+.-.................+.-............................+.-.................+......-.............+.....-.......................+..-....+..-....+...-...+..-...+.-.......+.-.........+.-....+..-.+.-....+..-...+...-..+..-.+.-.+.....-.+.....-.+.....-.+.....-..........................+.-......+..-.........+.-...........+..-...............+.-.....+..-..........+......-.....+..-......+.....-..........+..-.....<+++[->........+.-<]>.....+.-......+..-.......+.-.......+..-....+..-......+.-..........+..-...+.-....+..-...............+..-..+..-.............+..-...+.-....+..-.........+..-....+..-......+.-.......+.-......+.-........+.-.....+.-<++[->.......+..-........+.-...+.-.<]>........+.-.......+.-<++++[->.....+.-..<]>..........+..-.........+..-........+..-.........+.-...+...-.+.-.+..-...........+.-.......+.-..............+.-.....+.....-............+.-....+.-.+...-.+.-..+.-.+..-.+..-......+.-..+...-..+.-..+.......-.+...-....+...-.....+..-.+...-.........+.-.+.-.....+...-.+..-..+.-......+.-.+.-.....+......-..+.-......+.-.+.-.....+..-......+.-.....+..-.+..-<+++++++[->.....<]>+...-.....+.-..............+...-.+.-.+.-..<++++++[->.+.-<]>..+...-.........+.-.+.-.+.-.+.-................+.-.+.-..............+.....-................+.........-............+...-.......+...-.<++[->........+..-...<]>....+..-.+.-.........+.-.+..-<++[->.....+..-..+..-..<]>..+.-...+.-.+.-.....+.-.+.-...+.-..<+++[->..+.-...+.-<]>........+.-...+.-.+.-...+.-............+.-....+.-.<++[->...+.-.........<]>+.-..............+.-..+.-.+.-...........+....-..+.....-.+.-..+....-...


    Try it online!



    I will probably golf this even further soon.






    share|improve this answer











    $endgroup$





















      3












      $begingroup$


      C# (Visual C# Interactive Compiler), 366 332 329 319 bytes





      int i;foreach(var g in"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ")Write(Convert.ToString(g,2).PadLeft(12-i++%2,'0'));


      Replace all instances of with to test.



      Try it online!




      C# (Visual C# Interactive Compiler), 305 bytes, 210 chars





      _=>"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ".Select((g,i)=>Convert.ToString(g,2).PadLeft(12-i%2,'0'))


      Same with above, replace with with to test. Output as IEnumerable<string>.



      Try it online!(Courtesy of Jo King)






      share|improve this answer











      $endgroup$













      • $begingroup$
        TIO link with NUL bytes
        $endgroup$
        – Jo King
        yesterday










      • $begingroup$
        I believe the ++ in 12-i++%2 is a nop (at least, it worked for me when I removed it)
        $endgroup$
        – someone
        yesterday










      • $begingroup$
        @someone They are a copy-paste from the old answer I forgot to remove
        $endgroup$
        – Embodiment of Ignorance
        yesterday



















      2












      $begingroup$


      Deadfish~, 1115 bytes



      ooooooiodoiodoiodoiod{o}{i}c{d}ooiodoiodoooooiodoiodoooooooiodoo{i}c{d}iodoooiodoooiodoooiodooiodoioodooiodo{i}c{d}iodoiodoiodoiodoiodoiodoiodoiodooiodooiodoo{i}c{d}{oo}ooo{i}c{d}{o}ooioodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}oooooooooiodoiodoiodooooooooo{i}c{d}oooooooooiooooodooooooooo{i}c{d}{oo}ooo{i}c{d}ioodooooiooodoooioodooooioodooo{i}c{d}iod{o}oooioodooiodoooo{i}c{d}ioodoiodoooioodoooioodooooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiod{o}oooooooiodo{i}c{d}{oo}ooo{i}c{d}ooooiod{o}oooooooiod{i}c{d}ioooood{o}oooioooood{i}c{d}{oo}ooo{i}c{d}ioodooooioodooooiooodoooioodooo{i}c{d}iodoooooooiodoooooooooiodoooo{i}c{d}ioodoiodooooioodoooiooodooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiodooooooioodoooooooooiodo{i}c{d}{o}iood{o}o{i}c{d}ooooiodoooooiood{o}iod{i}c{d}iooooodoooooioodooooooioooood{i}c{d}{o}iood{o}o{i}c{d}ooiodooooooooiodooooooooiodoo{i}c{d}oooiodooooooioodoooooooiodooo{i}c{d}ooooioodooooioodooooooiodoooo{i}c{d}ooooooioodoooiodooooioodooooo{i}c{d}{o}ioodooioodooooooo{i}c{d}ooooooioodoooiodooooioodooooo


      Try it online!



      If someone has the patience to golf this further, I salute you ahead of time. :P






      share|improve this answer









      $endgroup$





















        2












        $begingroup$


        Perl 6, 368 bytes



        .say for :36('FJXOE0PDDNF5Y5EHGB8M9SWMXQOXIKIT9F6ZKWWDEACHCBGXL1N2H60CN0CJ4EMKF7D6MODSKYJVNR4SFTDR6NSM421LQ67B6MWF0G5BQATFOJJJBQ0UFQM64T0MWSQN41C4S5D1QR5KJM2L9UTYMMKUBBQWY45YCMRGO8ZRGTQH7LXMZBUASLCTKX30IH0AYKYEPHO8HFHX8GAY5WM38YOSUX0HABYSH2PPBLRDRZIN5ANAQ3V8PLOZ6EHC0UI95EVJVYD1820T6J14HGX85NWFQET2NWOMSNUT0JW4LHMY90X094TEE9KXJXSNN6YPERFQW').base(2).substr(1).comb(23)


        Try it online!



        The long string is the message as a single base-36 number (with a single prefixed 1 bit to preserve the leading zeroes) which is then converted back to binary and printed 23 bits at a time.






        share|improve this answer









        $endgroup$













        • $begingroup$
          You can use >>.say and &{S/.//} to save bytes. Have you thought about using a different base instead?
          $endgroup$
          – Jo King
          2 days ago












        • $begingroup$
          Yes, I tried using base 65536/Unicode, but the message runs into some forbidden surrogate codepoints. I was able to avoid that by adding a fixed offset to each codepoint, but astonishingly, some of the generated strings crashed Emacs a few times. Resolving the issues started taking more time than I could afford to commit. I'll probably revisit the problem later.
          $endgroup$
          – Sean
          2 days ago










        • $begingroup$
          There's no point going into multiple byte characters, since that increases your byte count. 289 bytes by implementing my tips from above and using base 122 (to avoid carriage returns)
          $endgroup$
          – Jo King
          2 days ago





















        2












        $begingroup$


        Wolfram Language (Mathematica), 383 bytes



        StringPartition[Uncompress@"1:eJylVNsRwjAM44s92KBaBTZgAUZhZXqtHUuOWrgjfSRRHFlO4tyer/vjfb1clq0gHirZLRjby986hppcT5p+L3BmgJ3t4Ul4GsNyG++7YbaXLh0ZTPhXa4Sn+X/s9Qfk3Hx2cOaSIuNYaVu5laschvgzSqAjHeZBhilKgKBDEhw0upJRg+HOK4MyNC29sfbc3RV0VPDqeLiRTsG1ulExq1IitpunOa7asnYM9siDZ6eidUCkEzBOUbCkGIig4aTyUGBYWAX6W6aXIWGGI/HlhmsqzSU0QTZjkMVpaX5sBsm1OGKVg1qdjKP0EdyqZBRLhukn8DLBQav6kccgz8OKfgBzjj6Z",23]


        Try it online!






        share|improve this answer









        $endgroup$





















          2












          $begingroup$


          Node.js, 333 bytes



          Returns a binary string of 1,679 characters.





          _=>Buffer(")SI)=.);1K?>>>2333A3,93/I3>3)g33)AEAAI)5JQZJTddda3)*3*33+3,e)*e3)//0/1+)1C/7Cgggg3395)9)A3IY)h*IH),39+)995*)AA-)59Y)*O3Z,)//*)91**)A*-)Y+1)I11+)I1)/)5)Y*0?)+)I)-0Y)1@;_*7<gaE/a)Q7[*9HM+IY16I33)a1)*^.><I+S3.38I)*hY)7)a)Y)A,9*A5Y/A:9=9K:1I-=9)19I)9*329)GH<").map(x=>s+=(x-51&&x-41).toString(2).padStart(x-51?6:12,0),s='')&&s


          Try it online! (with formatted output)





          JavaScript (ES8), 413 bytes



          Returns a binary string of 1,679 characters.





          _=>atob('AsKoAFBQEiIlwpVVUk!!ABwo!DQ!Gg!V!Aw7g!!GHGHCi!yGjHChsK+w7vDr8K!!Q!Q!!g!/DgAHDs!AGGHDhiAgCGhjwprDu8Ovwr4!ABAw4AQAcK!MKDAD8GB8OAD!QCAQQMBAYYEAMQwABwpgAMQwBwoYEBAgEEBgEQDAIwoAgIMKAwoDCgMKABgDDgDAEdcKACAgAEHwAIXTCtgTDpMO+w6HDgcK4AsKDwrIFB8OkCgwINg!!A4IAB1FVTDoArCo!U!/CgAB/w4ADwoDDoAwAYDQBYMOMBmEUFEIkSMKARR!woQgAQB!MKUAHnDtA'.split`!`.join`AA`).replace(/[sS]/g,c=>c.charCodeAt().toString(2).padStart(8,0))


          Try it online! (with formatted output)






          share|improve this answer











          $endgroup$





















            2












            $begingroup$

            Bubblegum, 275 236 bytes



            00000000: e006 8e00 e45d 0018 6988 6507 a228 f86f  .....]..i.e..(.o
            00000010: f042 c62f d4d7 b99e 38bc 56c4 52e8 2630 .B./....8.V.R.&0
            00000020: 8aaa 7252 d47d 5ef4 c96a 511f 6842 423f ..rR.}^..jQ.hBB?
            00000030: 4532 ca9f 22d3 1633 e0c4 665a d5dc 4e68 E2.."..3..fZ..Nh
            00000040: 7b09 76ae 3c7e f9d4 fa4a 05e0 4163 c580 {.v.<~...J..Ac..
            00000050: c585 a383 2396 4ca9 1f48 a4b9 744e 37c8 ....#.L..H..tN7.
            00000060: 68c5 af23 645d 59a7 542a e6d1 23b9 3aba h..#d]Y.T*..#.:.
            00000070: f0e6 2738 dfd5 b0a3 c6a3 60bf c5b6 5ae6 ..'8......`...Z.
            00000080: 7893 30a8 ae04 edf9 298b b777 4d56 285b x.0.....)..wMV([
            00000090: cb74 07cc 7a7b a399 3dc7 c6e7 b693 e715 .t..z{..=.......
            000000a0: d908 876e 001f 7408 3c6a 5fcd 37cb 02c4 ...n..t.<j_.7...
            000000b0: 93de 33c2 a11e 5bac cd12 d99a fac3 e0fa ..3...[.........
            000000c0: 5268 94f7 d640 0f73 cede f79d 821f 39d1 Rh...@.s......9.
            000000d0: dc49 ff06 6962 6c31 dc29 a077 01c3 7690 .I..ibl1.).w..v.
            000000e0: 85ef bbec 31d7 5c7f f9fc 8c00 ....1......


            Try it online!






            share|improve this answer











            $endgroup$





















              1












              $begingroup$


              Perl 5, 460 bytes





              printf"%023b",oct"0x$_"for qw/15400 141404 4444b2 555524 0 600 1a00 1a00 2a00 3e00 0 61c618 400190 68c61a 7df7df 0 80002 0 40001 7c001f 0 618718 404010 68639a 7df7df 0 81802 1800 41801 7c181f 1800 100804 81808 61810 18860 1980 18860 61810 81008 101804 201804 200808 101010 80060 60180 11d600 101000 107c00 10ba5b 1393f 5c3837 283b 10283f 102830 106c00 0 1c1000 1d4555 1c0154 140 7c00 1ff00 701c0 c0060 1a00b0 330198 228288 224488 22880 21080 20080 9400 3cfa78/


              Try it online!






              share|improve this answer









              $endgroup$





















                1












                $begingroup$

                bash + GNU tools, 351 bytes



                base64 -d<<<H4sIAPnNrVwCA6WUCRLDIAwDv8T+/3NNG4wvkTBTcisGSyA8xrcxj9Ds02F+Z7yuf3hnPyz0vYEGz+FG3IKBs+x3oL2PSh0TM/PnaGamft9nPUCew3uCp5RBWdRKGz+qNJn8qRKkkNaTBgeVIFXWOdi8VCaIeUnsfHo6TXpaFa3H5olf6J5MuIHLoEi0uKcRFCvEXG4xseglKzZg7kpYJSLMA3M7wXKR+/L2WiK0kvg+TDASLp6Co1KEVIlVmFzhCktRhBBDdSZYU1xKHrmDUllcWpNR/YNW2QNcHtF0rSySb0MXk/SDUgEwG5gfLvQDxuEdDo8GAAA=|gunzip


                TIO






                share|improve this answer











                $endgroup$













                • $begingroup$
                  didn't see your bash post before I posted mine - so much smaller!
                  $endgroup$
                  – Noodle9
                  yesterday



















                1












                $begingroup$


                Java (OpenJDK 8), 364 bytes





                n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replaceAll("2","0000")


                Try it online!



                Explanation: First had n->new java.math.BigInteger(str,36).toString(2), just converting a radix 36 number to binary, but that needed nine extra chars for leading zeroes. Then, I got the idea of run-length encoding some zeroes as twos. A length of four zeroes seems to minimize the radix 36 length, so n->new java.math.BigInteger(str,36).toString(3).replaceAll("2","0000")



                See the discussion under this answer for the leading zeroes bug fix by @KevinCruijssen






                share|improve this answer









                $endgroup$













                • $begingroup$
                  Nice. It's impressively short for Java!
                  $endgroup$
                  – Eric Duminil
                  18 hours ago



















                1












                $begingroup$

                [Python 2], 346 bytes





                s='';
                for c in '''%pG+K$K&j h!kk ppjGDI2S2S1[1e?v~vw,x"z wgqcde e9G0G;G0eG,e6vv~w&G(gn wy uuuuG9G%I(G*I.G$I)eG$I%e)I,G'G'G$G%I&G&vI%G)w#I.y,w#I(vI%G&G%G'G$G&I'W'I'W(G&G$G&G&G&G+I(I'I(iq*G&G-G$e+g c!sG%m!md~ M$}(K$cO%K$eO%K$I%G$aBM$G-c hpoI(pG/K-e/eU+M&M(I*I&S(Q$y&y#hG$ng"j j G'hW+g#G+G(G-k*''':c=ord(c)-31;s+=c<39and'0'*c or bin(c-39)[2:]
                print s


                I encoded the length of strings of 0s as a byte starting at chr(31). Then I encoded the remaining 10101 as binary numbers starting at chr(70) up to chr(126). Binary strings that didn't fit were split up into smaller chunks.



                Edit: Reduced to 326 bytes. Thanks Jo King
                Edit: Fixed a bug in the code generator program






                share|improve this answer










                New contributor




                Benjamin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$













                • $begingroup$
                  Actually, a list comprehension is even shorter. [bin(c-39)[2:],'0'*c][c<39]. You're also missing the link part of your answer
                  $endgroup$
                  – Jo King
                  1 hour ago












                • $begingroup$
                  You don't need to save the big string in o to a variable.
                  $endgroup$
                  – xnor
                  1 hour ago



















                0












                $begingroup$


                Python 2, 336 bytes





                print bin(int('gVQAKCgJERLKqqkgAAAAAMAABoAADQAAKgAAfAAAAAMOMMQAGQ0Yw19998AAAAgAAgAAABAAB+AA+AAADDDjEBAENDHNffffAAAAIGAIAMAAQYAfgwPgBgAIBAIIGAgMMCAGIYAAzAAYhgDDAgIEAggMAiAYBEAQEEBAQEADAGAYAjrABAQACD4AELpbAnJ/cODcAUHZAoPyBQYEGwAAAAAcEAA6iqpwBVAACgAHwAA/4AHAcAYAMBoAsGYDMIoKIRIkQCKIAEIQAIAgAEoAPPp4'.decode('base64').encode('hex'),16))[3:]


                Try it online!



                Prints a string of bytes






                share|improve this answer









                $endgroup$





















                  0












                  $begingroup$


                  Bash, 702 697 bytes





                  xxd -r -p<<X|xz -dc
                  fd377a585a000004e6d6b4460200210116000000742fe5a3e006d7010c5d
                  0018698865079cf6752c9e9a501a87a798b4844f9fcfdaaf87733b9d8239
                  48c816d860a938767f6cb81299f3e8a638effe3068c0e096a8949c81d706
                  7dff3ec44e5df185b3a48e5b5857724386e8c37cfbd5c856b12614ee78ec
                  c41df4db3aea71fd3a8fa474905609f78eb3fd66e246557965e4ab6dfd67
                  efbd9202f542ded9cf98a6401ee2d23afb2f544bd2442c6f428fd612397c
                  f2c6ec50847ddccc5832185e487712e5a7676b97058d7e485d5a3536166a
                  44ab3c689c93073cdda73b5306a83c4cd268e79db238bfa2d08ac912a578
                  75020bc7828342d5a62ce367aff7fd89290336128d119fa4272da2b2a79f
                  5973c71935af054f2d91c1bd3ea4847a3502d6dc8c975114dacf8a4de600
                  622d80986dbb0cd00001a802d80d00001b16e2a7b1c467fb020000000004
                  595a
                  X


                  Try it online!






                  share|improve this answer











                  $endgroup$





















                    0












                    $begingroup$


                    Ruby, 362 bytes





                    puts"5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0".to_i(36).to_s(2).rjust(1679,?0)


                    Integer written in base 36. There's surely a more efficient way to compress the integer, e.g. with zlib or base64.



                    Try it online!






                    share|improve this answer











                    $endgroup$





















                      0












                      $begingroup$

                      [C++ (VC++)(but tested with gcc as well)], 585 bytes





                      #define l(x,y)for(int x=0;x<y;x++)
                      void f(){const char*a="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";int x=1679;l(i,365){int d=a[i],c=0;d-=(d>47&d<58)?48:((d>64&d<71)?55:0);if(d>70&d<91)c=91-d,d=a[i-1];for(c;c>=0;c--)l(j,4){if(x--)cout<<(int)((d&(8>>j))>0);}}}



                      Try it online!



                      ungolfed Version (lacks the break after the 1679th element though and goes until the 1680th):



                      #include <stdio.h>
                      #include <iostream>
                      using namespace std;
                      int main()
                      {
                      const char arecibo="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";
                      int i = 0,j;
                      while (i<sizeof(arecibo)-1)
                      {
                      char digit = arecibo[i];
                      int count=0;
                      if (digit >= '0' & digit <= '9')
                      {
                      digit -= '0';
                      }
                      else if (digit>='A'& digit<='F')
                      {
                      digit -= 'A'-10;
                      }
                      else if (digit > 'F'&digit<='Z')
                      {
                      //digit does not contain any valid hex digit in this case
                      count = 'Z' - digit+1; //digit = Z means repeat 2 more times...
                      digit = arecibo[i - 1];
                      }
                      for (count; count >= 0; count--)
                      {
                      for (j = 0; j<4; j++)
                      {
                      cout << (int)(((digit)&(8 >> j))>0);
                      }
                      }
                      i++;
                      }
                      return 0;
                      }


                      as an Explanation: i concatenated the 73 lines of sample output given to one long line.
                      i encoded them in hexadecimal where the bit order is msbfirst (using this program https://github.com/Marc-Bender/longBinaryStreamToHex/releases/download/addedErrorCode-4/longBinaryStreamToHex.exe)
                      i shortened the Output of that by about 70 hexadecimal Digits by using the letters 'G'-'Z' as a sign to repeat the last Digit for a certain amount of times (Z = 2more times, Y = 3more times …)
                      the rest should be relatively self explainatory for Code-Golfers. abusing the preprocessor to shorten loops, abusing the , Operator and the like.



                      Output Format is uninterrupted stream of 1679 0/1-values.






                      share|improve this answer









                      $endgroup$













                      • $begingroup$
                        before anybody asks the const is for compatibility with VC++ (what the main development work was done with)
                        $endgroup$
                        – der bender
                        yesterday



















                      0












                      $begingroup$


                      Perl 6, 348 bytes





                      {"000000"~:36<5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0>.base(2)}


                      Based on Benjamin Urquhart's Java solution.



                      Uses a straight stream of 0 and 1 characters. The link below has some code to prettify the output.



                      Try it online!






                      share|improve this answer









                      $endgroup$














                        Your Answer





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                        19 Answers
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                        oldest

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                        11












                        $begingroup$


                        05AB1E, 215 210 200 bytes



                        Saved 15 bytes thanks to Magic Octopus Urn



                        •cOž¤4é57ñΛÖ₃BαöĀíL½₅üBdoÙRθLγ¨G×Tćú$G(˜ƒ¦!€R»SDrµCnJ†d∊ζ·<8‡T@|‹ï=BζćósxGÙÎ$¿o₁5/ÔŸÇBûXé-”a::Ž]°∊y;ζ]MÜβ‘иL”β{üÃÇíäc€÷›ÎU=}¨иaŸdY`»¾ÚUβ:ô©¦β†₅DGŠβ3Jêθ,äá!ícqšVÖ›lÈΣ¯pε €êʃDpÙ/¬Žλ8:ãÿ3=€.Þć•3BY¾4×:


                        Try it online!
                        or with Additional formatting



                        Base-255 encoded trinary string with occurrences of 0000 replaced by 2.






                        share|improve this answer











                        $endgroup$













                        • $begingroup$
                          @MagicOctopusUrn: Thanks! That makes it 210 even :)
                          $endgroup$
                          – Emigna
                          yesterday










                        • $begingroup$
                          It's actually even better if you replace 0000 with 2 by 9 more bytes. - pastebin.com/aZ6tHxjx for 201
                          $endgroup$
                          – Magic Octopus Urn
                          yesterday












                        • $begingroup$
                          @MagicOctopusUrn: Yes, I found that as well and was just about to post it :)
                          $endgroup$
                          – Emigna
                          yesterday






                        • 1




                          $begingroup$
                          Cool! Since the Arecibo messages is 210 bytes (23 * 73 / 8 = 209.875), your solution (currently at 200 bytes) is shorter than the message itself!
                          $endgroup$
                          – J-L
                          9 hours ago










                        • $begingroup$
                          I went ahead and made this the accepted answer since it was the first one to be shorter than the message itself.
                          $endgroup$
                          – Beefster
                          8 hours ago
















                        11












                        $begingroup$


                        05AB1E, 215 210 200 bytes



                        Saved 15 bytes thanks to Magic Octopus Urn



                        •cOž¤4é57ñΛÖ₃BαöĀíL½₅üBdoÙRθLγ¨G×Tćú$G(˜ƒ¦!€R»SDrµCnJ†d∊ζ·<8‡T@|‹ï=BζćósxGÙÎ$¿o₁5/ÔŸÇBûXé-”a::Ž]°∊y;ζ]MÜβ‘иL”β{üÃÇíäc€÷›ÎU=}¨иaŸdY`»¾ÚUβ:ô©¦β†₅DGŠβ3Jêθ,äá!ícqšVÖ›lÈΣ¯pε €êʃDpÙ/¬Žλ8:ãÿ3=€.Þć•3BY¾4×:


                        Try it online!
                        or with Additional formatting



                        Base-255 encoded trinary string with occurrences of 0000 replaced by 2.






                        share|improve this answer











                        $endgroup$













                        • $begingroup$
                          @MagicOctopusUrn: Thanks! That makes it 210 even :)
                          $endgroup$
                          – Emigna
                          yesterday










                        • $begingroup$
                          It's actually even better if you replace 0000 with 2 by 9 more bytes. - pastebin.com/aZ6tHxjx for 201
                          $endgroup$
                          – Magic Octopus Urn
                          yesterday












                        • $begingroup$
                          @MagicOctopusUrn: Yes, I found that as well and was just about to post it :)
                          $endgroup$
                          – Emigna
                          yesterday






                        • 1




                          $begingroup$
                          Cool! Since the Arecibo messages is 210 bytes (23 * 73 / 8 = 209.875), your solution (currently at 200 bytes) is shorter than the message itself!
                          $endgroup$
                          – J-L
                          9 hours ago










                        • $begingroup$
                          I went ahead and made this the accepted answer since it was the first one to be shorter than the message itself.
                          $endgroup$
                          – Beefster
                          8 hours ago














                        11












                        11








                        11





                        $begingroup$


                        05AB1E, 215 210 200 bytes



                        Saved 15 bytes thanks to Magic Octopus Urn



                        •cOž¤4é57ñΛÖ₃BαöĀíL½₅üBdoÙRθLγ¨G×Tćú$G(˜ƒ¦!€R»SDrµCnJ†d∊ζ·<8‡T@|‹ï=BζćósxGÙÎ$¿o₁5/ÔŸÇBûXé-”a::Ž]°∊y;ζ]MÜβ‘иL”β{üÃÇíäc€÷›ÎU=}¨иaŸdY`»¾ÚUβ:ô©¦β†₅DGŠβ3Jêθ,äá!ícqšVÖ›lÈΣ¯pε €êʃDpÙ/¬Žλ8:ãÿ3=€.Þć•3BY¾4×:


                        Try it online!
                        or with Additional formatting



                        Base-255 encoded trinary string with occurrences of 0000 replaced by 2.






                        share|improve this answer











                        $endgroup$




                        05AB1E, 215 210 200 bytes



                        Saved 15 bytes thanks to Magic Octopus Urn



                        •cOž¤4é57ñΛÖ₃BαöĀíL½₅üBdoÙRθLγ¨G×Tćú$G(˜ƒ¦!€R»SDrµCnJ†d∊ζ·<8‡T@|‹ï=BζćósxGÙÎ$¿o₁5/ÔŸÇBûXé-”a::Ž]°∊y;ζ]MÜβ‘иL”β{üÃÇíäc€÷›ÎU=}¨иaŸdY`»¾ÚUβ:ô©¦β†₅DGŠβ3Jêθ,äá!ícqšVÖ›lÈΣ¯pε €êʃDpÙ/¬Žλ8:ãÿ3=€.Þć•3BY¾4×:


                        Try it online!
                        or with Additional formatting



                        Base-255 encoded trinary string with occurrences of 0000 replaced by 2.







                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited yesterday

























                        answered 2 days ago









                        EmignaEmigna

                        47.9k434146




                        47.9k434146












                        • $begingroup$
                          @MagicOctopusUrn: Thanks! That makes it 210 even :)
                          $endgroup$
                          – Emigna
                          yesterday










                        • $begingroup$
                          It's actually even better if you replace 0000 with 2 by 9 more bytes. - pastebin.com/aZ6tHxjx for 201
                          $endgroup$
                          – Magic Octopus Urn
                          yesterday












                        • $begingroup$
                          @MagicOctopusUrn: Yes, I found that as well and was just about to post it :)
                          $endgroup$
                          – Emigna
                          yesterday






                        • 1




                          $begingroup$
                          Cool! Since the Arecibo messages is 210 bytes (23 * 73 / 8 = 209.875), your solution (currently at 200 bytes) is shorter than the message itself!
                          $endgroup$
                          – J-L
                          9 hours ago










                        • $begingroup$
                          I went ahead and made this the accepted answer since it was the first one to be shorter than the message itself.
                          $endgroup$
                          – Beefster
                          8 hours ago


















                        • $begingroup$
                          @MagicOctopusUrn: Thanks! That makes it 210 even :)
                          $endgroup$
                          – Emigna
                          yesterday










                        • $begingroup$
                          It's actually even better if you replace 0000 with 2 by 9 more bytes. - pastebin.com/aZ6tHxjx for 201
                          $endgroup$
                          – Magic Octopus Urn
                          yesterday












                        • $begingroup$
                          @MagicOctopusUrn: Yes, I found that as well and was just about to post it :)
                          $endgroup$
                          – Emigna
                          yesterday






                        • 1




                          $begingroup$
                          Cool! Since the Arecibo messages is 210 bytes (23 * 73 / 8 = 209.875), your solution (currently at 200 bytes) is shorter than the message itself!
                          $endgroup$
                          – J-L
                          9 hours ago










                        • $begingroup$
                          I went ahead and made this the accepted answer since it was the first one to be shorter than the message itself.
                          $endgroup$
                          – Beefster
                          8 hours ago
















                        $begingroup$
                        @MagicOctopusUrn: Thanks! That makes it 210 even :)
                        $endgroup$
                        – Emigna
                        yesterday




                        $begingroup$
                        @MagicOctopusUrn: Thanks! That makes it 210 even :)
                        $endgroup$
                        – Emigna
                        yesterday












                        $begingroup$
                        It's actually even better if you replace 0000 with 2 by 9 more bytes. - pastebin.com/aZ6tHxjx for 201
                        $endgroup$
                        – Magic Octopus Urn
                        yesterday






                        $begingroup$
                        It's actually even better if you replace 0000 with 2 by 9 more bytes. - pastebin.com/aZ6tHxjx for 201
                        $endgroup$
                        – Magic Octopus Urn
                        yesterday














                        $begingroup$
                        @MagicOctopusUrn: Yes, I found that as well and was just about to post it :)
                        $endgroup$
                        – Emigna
                        yesterday




                        $begingroup$
                        @MagicOctopusUrn: Yes, I found that as well and was just about to post it :)
                        $endgroup$
                        – Emigna
                        yesterday




                        1




                        1




                        $begingroup$
                        Cool! Since the Arecibo messages is 210 bytes (23 * 73 / 8 = 209.875), your solution (currently at 200 bytes) is shorter than the message itself!
                        $endgroup$
                        – J-L
                        9 hours ago




                        $begingroup$
                        Cool! Since the Arecibo messages is 210 bytes (23 * 73 / 8 = 209.875), your solution (currently at 200 bytes) is shorter than the message itself!
                        $endgroup$
                        – J-L
                        9 hours ago












                        $begingroup$
                        I went ahead and made this the accepted answer since it was the first one to be shorter than the message itself.
                        $endgroup$
                        – Beefster
                        8 hours ago




                        $begingroup$
                        I went ahead and made this the accepted answer since it was the first one to be shorter than the message itself.
                        $endgroup$
                        – Beefster
                        8 hours ago











                        9












                        $begingroup$

                        Java, 688 678 590 379 361 bytes



                        Returns a string.



                        n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replace("2","0000")


                        -10 bytes by returning the raw stream (old answer)

                        -88 bytes by using base 10 numerics (thanks @ceilingcat!)

                        -211 bytes (I knew it could be golfed!) by using a base-36 encoded BigInteger (thanks @JollyJoker!)

                        -18 bytes by using a different encoded integer (thanks again @JollyJoker)


                        Try it online!



                        Explanation:



                        n->new java.math.BigInteger("base36 string",36)              // Decode the base-36 integer.
                        .toString(3) // Re-encode as ternary
                        .replace("2","0000") // Replace 2 with "0000"
                        // Implicit return





                        share|improve this answer











                        $endgroup$













                        • $begingroup$
                          Comments are not for extended discussion; this conversation has been moved to chat.
                          $endgroup$
                          – Adam Lear
                          3 hours ago
















                        9












                        $begingroup$

                        Java, 688 678 590 379 361 bytes



                        Returns a string.



                        n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replace("2","0000")


                        -10 bytes by returning the raw stream (old answer)

                        -88 bytes by using base 10 numerics (thanks @ceilingcat!)

                        -211 bytes (I knew it could be golfed!) by using a base-36 encoded BigInteger (thanks @JollyJoker!)

                        -18 bytes by using a different encoded integer (thanks again @JollyJoker)


                        Try it online!



                        Explanation:



                        n->new java.math.BigInteger("base36 string",36)              // Decode the base-36 integer.
                        .toString(3) // Re-encode as ternary
                        .replace("2","0000") // Replace 2 with "0000"
                        // Implicit return





                        share|improve this answer











                        $endgroup$













                        • $begingroup$
                          Comments are not for extended discussion; this conversation has been moved to chat.
                          $endgroup$
                          – Adam Lear
                          3 hours ago














                        9












                        9








                        9





                        $begingroup$

                        Java, 688 678 590 379 361 bytes



                        Returns a string.



                        n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replace("2","0000")


                        -10 bytes by returning the raw stream (old answer)

                        -88 bytes by using base 10 numerics (thanks @ceilingcat!)

                        -211 bytes (I knew it could be golfed!) by using a base-36 encoded BigInteger (thanks @JollyJoker!)

                        -18 bytes by using a different encoded integer (thanks again @JollyJoker)


                        Try it online!



                        Explanation:



                        n->new java.math.BigInteger("base36 string",36)              // Decode the base-36 integer.
                        .toString(3) // Re-encode as ternary
                        .replace("2","0000") // Replace 2 with "0000"
                        // Implicit return





                        share|improve this answer











                        $endgroup$



                        Java, 688 678 590 379 361 bytes



                        Returns a string.



                        n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replace("2","0000")


                        -10 bytes by returning the raw stream (old answer)

                        -88 bytes by using base 10 numerics (thanks @ceilingcat!)

                        -211 bytes (I knew it could be golfed!) by using a base-36 encoded BigInteger (thanks @JollyJoker!)

                        -18 bytes by using a different encoded integer (thanks again @JollyJoker)


                        Try it online!



                        Explanation:



                        n->new java.math.BigInteger("base36 string",36)              // Decode the base-36 integer.
                        .toString(3) // Re-encode as ternary
                        .replace("2","0000") // Replace 2 with "0000"
                        // Implicit return






                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited 8 hours ago

























                        answered 2 days ago









                        Benjamin UrquhartBenjamin Urquhart

                        47017




                        47017












                        • $begingroup$
                          Comments are not for extended discussion; this conversation has been moved to chat.
                          $endgroup$
                          – Adam Lear
                          3 hours ago


















                        • $begingroup$
                          Comments are not for extended discussion; this conversation has been moved to chat.
                          $endgroup$
                          – Adam Lear
                          3 hours ago
















                        $begingroup$
                        Comments are not for extended discussion; this conversation has been moved to chat.
                        $endgroup$
                        – Adam Lear
                        3 hours ago




                        $begingroup$
                        Comments are not for extended discussion; this conversation has been moved to chat.
                        $endgroup$
                        – Adam Lear
                        3 hours ago











                        8












                        $begingroup$


                        Jelly, 213 bytes



                        “H²ɓ¶Ṡḷ€ẹ]ƒf*ḳḢ&ƁṇOḥ{ḄṫwỊ+oLạʋߢH9¢¹÷ỴɗÇ⁶ƲƙæḊẋ3³=1!VƇƁ'D⁺3Ỵɱ©⁵%fȯez#ƈjƒżṆo.ZF⁶ċṢ⁶ọṛb9Ȯƒd?ƁUĠt4ẇ,ḞġƒµƭfʠƁP§÷øȤŻPɲẋ(¢ß¢(⁽3¶ṙėɗy@ṁYȮL~e⁷ƤĊ§nỊṅµṠ°@7ẠB>Ġ⁻İ}uy¡½:esOpḢt}qS©HÞṬĖṛṇḣ9÷;ESḢ,Ẉ^ṙpƲ©tṃwçnẒṆ¡⁻Jıƒị£-&Ɱ*ẋʂżoȯÑḢɼ’


                        Try it online!



                        I played around with Huffman coding, but the improvements in data size were outweighed by the extra code. As such, this is simply a base-250 encoded version of the desired output. Output consists of an integer that when decoded as bijective base 2 will yield the 1D list of 1s and 2s. Thanks @Emigna for pointing out the change in rules.



                        Try it online - with further decoding to demonstrate output!



                        If a more conventional binary encoding is preferred, here is one that encodes an integer representation of the inverted binary message. The most significant bit of the integer represents the beginning of the message.






                        share|improve this answer











                        $endgroup$


















                          8












                          $begingroup$


                          Jelly, 213 bytes



                          “H²ɓ¶Ṡḷ€ẹ]ƒf*ḳḢ&ƁṇOḥ{ḄṫwỊ+oLạʋߢH9¢¹÷ỴɗÇ⁶ƲƙæḊẋ3³=1!VƇƁ'D⁺3Ỵɱ©⁵%fȯez#ƈjƒżṆo.ZF⁶ċṢ⁶ọṛb9Ȯƒd?ƁUĠt4ẇ,ḞġƒµƭfʠƁP§÷øȤŻPɲẋ(¢ß¢(⁽3¶ṙėɗy@ṁYȮL~e⁷ƤĊ§nỊṅµṠ°@7ẠB>Ġ⁻İ}uy¡½:esOpḢt}qS©HÞṬĖṛṇḣ9÷;ESḢ,Ẉ^ṙpƲ©tṃwçnẒṆ¡⁻Jıƒị£-&Ɱ*ẋʂżoȯÑḢɼ’


                          Try it online!



                          I played around with Huffman coding, but the improvements in data size were outweighed by the extra code. As such, this is simply a base-250 encoded version of the desired output. Output consists of an integer that when decoded as bijective base 2 will yield the 1D list of 1s and 2s. Thanks @Emigna for pointing out the change in rules.



                          Try it online - with further decoding to demonstrate output!



                          If a more conventional binary encoding is preferred, here is one that encodes an integer representation of the inverted binary message. The most significant bit of the integer represents the beginning of the message.






                          share|improve this answer











                          $endgroup$
















                            8












                            8








                            8





                            $begingroup$


                            Jelly, 213 bytes



                            “H²ɓ¶Ṡḷ€ẹ]ƒf*ḳḢ&ƁṇOḥ{ḄṫwỊ+oLạʋߢH9¢¹÷ỴɗÇ⁶ƲƙæḊẋ3³=1!VƇƁ'D⁺3Ỵɱ©⁵%fȯez#ƈjƒżṆo.ZF⁶ċṢ⁶ọṛb9Ȯƒd?ƁUĠt4ẇ,ḞġƒµƭfʠƁP§÷øȤŻPɲẋ(¢ß¢(⁽3¶ṙėɗy@ṁYȮL~e⁷ƤĊ§nỊṅµṠ°@7ẠB>Ġ⁻İ}uy¡½:esOpḢt}qS©HÞṬĖṛṇḣ9÷;ESḢ,Ẉ^ṙpƲ©tṃwçnẒṆ¡⁻Jıƒị£-&Ɱ*ẋʂżoȯÑḢɼ’


                            Try it online!



                            I played around with Huffman coding, but the improvements in data size were outweighed by the extra code. As such, this is simply a base-250 encoded version of the desired output. Output consists of an integer that when decoded as bijective base 2 will yield the 1D list of 1s and 2s. Thanks @Emigna for pointing out the change in rules.



                            Try it online - with further decoding to demonstrate output!



                            If a more conventional binary encoding is preferred, here is one that encodes an integer representation of the inverted binary message. The most significant bit of the integer represents the beginning of the message.






                            share|improve this answer











                            $endgroup$




                            Jelly, 213 bytes



                            “H²ɓ¶Ṡḷ€ẹ]ƒf*ḳḢ&ƁṇOḥ{ḄṫwỊ+oLạʋߢH9¢¹÷ỴɗÇ⁶ƲƙæḊẋ3³=1!VƇƁ'D⁺3Ỵɱ©⁵%fȯez#ƈjƒżṆo.ZF⁶ċṢ⁶ọṛb9Ȯƒd?ƁUĠt4ẇ,ḞġƒµƭfʠƁP§÷øȤŻPɲẋ(¢ß¢(⁽3¶ṙėɗy@ṁYȮL~e⁷ƤĊ§nỊṅµṠ°@7ẠB>Ġ⁻İ}uy¡½:esOpḢt}qS©HÞṬĖṛṇḣ9÷;ESḢ,Ẉ^ṙpƲ©tṃwçnẒṆ¡⁻Jıƒị£-&Ɱ*ẋʂżoȯÑḢɼ’


                            Try it online!



                            I played around with Huffman coding, but the improvements in data size were outweighed by the extra code. As such, this is simply a base-250 encoded version of the desired output. Output consists of an integer that when decoded as bijective base 2 will yield the 1D list of 1s and 2s. Thanks @Emigna for pointing out the change in rules.



                            Try it online - with further decoding to demonstrate output!



                            If a more conventional binary encoding is preferred, here is one that encodes an integer representation of the inverted binary message. The most significant bit of the integer represents the beginning of the message.







                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited 2 days ago

























                            answered 2 days ago









                            Nick KennedyNick Kennedy

                            1,51649




                            1,51649























                                6












                                $begingroup$

                                Brainfuck, 2360 2008 1938 bytes



                                -[>+<-----]>---......+.-.+.-.+.-.+.-............+.-.+.-.....+.-.+.-.......+.-.<++++[->.+.-..<]>+.-.+..-.<+++++++++[->.+.-<]>..+.-..+.-<++++++[->......<]>.+.<++[->.-...................+..-.+<]>.-..................+.-.+.-.+.-..................+.....-<++++++++[->....<]>+..-....+...-...+..-....+..-...+.-.............+..-..+.-....+..-.+.-...+..-...+..-....+..-.+<++++[->.-.+....<]>.-<+++++[->.....<]>.+.-.................+.-............................+.-.................+......-.............+.....-.......................+..-....+..-....+...-...+..-...+.-.......+.-.........+.-....+..-.+.-....+..-...+...-..+..-.+.-.+.....-.+.....-.+.....-.+.....-..........................+.-......+..-.........+.-...........+..-...............+.-.....+..-..........+......-.....+..-......+.....-..........+..-.....<+++[->........+.-<]>.....+.-......+..-.......+.-.......+..-....+..-......+.-..........+..-...+.-....+..-...............+..-..+..-.............+..-...+.-....+..-.........+..-....+..-......+.-.......+.-......+.-........+.-.....+.-<++[->.......+..-........+.-...+.-.<]>........+.-.......+.-<++++[->.....+.-..<]>..........+..-.........+..-........+..-.........+.-...+...-.+.-.+..-...........+.-.......+.-..............+.-.....+.....-............+.-....+.-.+...-.+.-..+.-.+..-.+..-......+.-..+...-..+.-..+.......-.+...-....+...-.....+..-.+...-.........+.-.+.-.....+...-.+..-..+.-......+.-.+.-.....+......-..+.-......+.-.+.-.....+..-......+.-.....+..-.+..-<+++++++[->.....<]>+...-.....+.-..............+...-.+.-.+.-..<++++++[->.+.-<]>..+...-.........+.-.+.-.+.-.+.-................+.-.+.-..............+.....-................+.........-............+...-.......+...-.<++[->........+..-...<]>....+..-.+.-.........+.-.+..-<++[->.....+..-..+..-..<]>..+.-...+.-.+.-.....+.-.+.-...+.-..<+++[->..+.-...+.-<]>........+.-...+.-.+.-...+.-............+.-....+.-.<++[->...+.-.........<]>+.-..............+.-..+.-.+.-...........+....-..+.....-.+.-..+....-...


                                Try it online!



                                I will probably golf this even further soon.






                                share|improve this answer











                                $endgroup$


















                                  6












                                  $begingroup$

                                  Brainfuck, 2360 2008 1938 bytes



                                  -[>+<-----]>---......+.-.+.-.+.-.+.-............+.-.+.-.....+.-.+.-.......+.-.<++++[->.+.-..<]>+.-.+..-.<+++++++++[->.+.-<]>..+.-..+.-<++++++[->......<]>.+.<++[->.-...................+..-.+<]>.-..................+.-.+.-.+.-..................+.....-<++++++++[->....<]>+..-....+...-...+..-....+..-...+.-.............+..-..+.-....+..-.+.-...+..-...+..-....+..-.+<++++[->.-.+....<]>.-<+++++[->.....<]>.+.-.................+.-............................+.-.................+......-.............+.....-.......................+..-....+..-....+...-...+..-...+.-.......+.-.........+.-....+..-.+.-....+..-...+...-..+..-.+.-.+.....-.+.....-.+.....-.+.....-..........................+.-......+..-.........+.-...........+..-...............+.-.....+..-..........+......-.....+..-......+.....-..........+..-.....<+++[->........+.-<]>.....+.-......+..-.......+.-.......+..-....+..-......+.-..........+..-...+.-....+..-...............+..-..+..-.............+..-...+.-....+..-.........+..-....+..-......+.-.......+.-......+.-........+.-.....+.-<++[->.......+..-........+.-...+.-.<]>........+.-.......+.-<++++[->.....+.-..<]>..........+..-.........+..-........+..-.........+.-...+...-.+.-.+..-...........+.-.......+.-..............+.-.....+.....-............+.-....+.-.+...-.+.-..+.-.+..-.+..-......+.-..+...-..+.-..+.......-.+...-....+...-.....+..-.+...-.........+.-.+.-.....+...-.+..-..+.-......+.-.+.-.....+......-..+.-......+.-.+.-.....+..-......+.-.....+..-.+..-<+++++++[->.....<]>+...-.....+.-..............+...-.+.-.+.-..<++++++[->.+.-<]>..+...-.........+.-.+.-.+.-.+.-................+.-.+.-..............+.....-................+.........-............+...-.......+...-.<++[->........+..-...<]>....+..-.+.-.........+.-.+..-<++[->.....+..-..+..-..<]>..+.-...+.-.+.-.....+.-.+.-...+.-..<+++[->..+.-...+.-<]>........+.-...+.-.+.-...+.-............+.-....+.-.<++[->...+.-.........<]>+.-..............+.-..+.-.+.-...........+....-..+.....-.+.-..+....-...


                                  Try it online!



                                  I will probably golf this even further soon.






                                  share|improve this answer











                                  $endgroup$
















                                    6












                                    6








                                    6





                                    $begingroup$

                                    Brainfuck, 2360 2008 1938 bytes



                                    -[>+<-----]>---......+.-.+.-.+.-.+.-............+.-.+.-.....+.-.+.-.......+.-.<++++[->.+.-..<]>+.-.+..-.<+++++++++[->.+.-<]>..+.-..+.-<++++++[->......<]>.+.<++[->.-...................+..-.+<]>.-..................+.-.+.-.+.-..................+.....-<++++++++[->....<]>+..-....+...-...+..-....+..-...+.-.............+..-..+.-....+..-.+.-...+..-...+..-....+..-.+<++++[->.-.+....<]>.-<+++++[->.....<]>.+.-.................+.-............................+.-.................+......-.............+.....-.......................+..-....+..-....+...-...+..-...+.-.......+.-.........+.-....+..-.+.-....+..-...+...-..+..-.+.-.+.....-.+.....-.+.....-.+.....-..........................+.-......+..-.........+.-...........+..-...............+.-.....+..-..........+......-.....+..-......+.....-..........+..-.....<+++[->........+.-<]>.....+.-......+..-.......+.-.......+..-....+..-......+.-..........+..-...+.-....+..-...............+..-..+..-.............+..-...+.-....+..-.........+..-....+..-......+.-.......+.-......+.-........+.-.....+.-<++[->.......+..-........+.-...+.-.<]>........+.-.......+.-<++++[->.....+.-..<]>..........+..-.........+..-........+..-.........+.-...+...-.+.-.+..-...........+.-.......+.-..............+.-.....+.....-............+.-....+.-.+...-.+.-..+.-.+..-.+..-......+.-..+...-..+.-..+.......-.+...-....+...-.....+..-.+...-.........+.-.+.-.....+...-.+..-..+.-......+.-.+.-.....+......-..+.-......+.-.+.-.....+..-......+.-.....+..-.+..-<+++++++[->.....<]>+...-.....+.-..............+...-.+.-.+.-..<++++++[->.+.-<]>..+...-.........+.-.+.-.+.-.+.-................+.-.+.-..............+.....-................+.........-............+...-.......+...-.<++[->........+..-...<]>....+..-.+.-.........+.-.+..-<++[->.....+..-..+..-..<]>..+.-...+.-.+.-.....+.-.+.-...+.-..<+++[->..+.-...+.-<]>........+.-...+.-.+.-...+.-............+.-....+.-.<++[->...+.-.........<]>+.-..............+.-..+.-.+.-...........+....-..+.....-.+.-..+....-...


                                    Try it online!



                                    I will probably golf this even further soon.






                                    share|improve this answer











                                    $endgroup$



                                    Brainfuck, 2360 2008 1938 bytes



                                    -[>+<-----]>---......+.-.+.-.+.-.+.-............+.-.+.-.....+.-.+.-.......+.-.<++++[->.+.-..<]>+.-.+..-.<+++++++++[->.+.-<]>..+.-..+.-<++++++[->......<]>.+.<++[->.-...................+..-.+<]>.-..................+.-.+.-.+.-..................+.....-<++++++++[->....<]>+..-....+...-...+..-....+..-...+.-.............+..-..+.-....+..-.+.-...+..-...+..-....+..-.+<++++[->.-.+....<]>.-<+++++[->.....<]>.+.-.................+.-............................+.-.................+......-.............+.....-.......................+..-....+..-....+...-...+..-...+.-.......+.-.........+.-....+..-.+.-....+..-...+...-..+..-.+.-.+.....-.+.....-.+.....-.+.....-..........................+.-......+..-.........+.-...........+..-...............+.-.....+..-..........+......-.....+..-......+.....-..........+..-.....<+++[->........+.-<]>.....+.-......+..-.......+.-.......+..-....+..-......+.-..........+..-...+.-....+..-...............+..-..+..-.............+..-...+.-....+..-.........+..-....+..-......+.-.......+.-......+.-........+.-.....+.-<++[->.......+..-........+.-...+.-.<]>........+.-.......+.-<++++[->.....+.-..<]>..........+..-.........+..-........+..-.........+.-...+...-.+.-.+..-...........+.-.......+.-..............+.-.....+.....-............+.-....+.-.+...-.+.-..+.-.+..-.+..-......+.-..+...-..+.-..+.......-.+...-....+...-.....+..-.+...-.........+.-.+.-.....+...-.+..-..+.-......+.-.+.-.....+......-..+.-......+.-.+.-.....+..-......+.-.....+..-.+..-<+++++++[->.....<]>+...-.....+.-..............+...-.+.-.+.-..<++++++[->.+.-<]>..+...-.........+.-.+.-.+.-.+.-................+.-.+.-..............+.....-................+.........-............+...-.......+...-.<++[->........+..-...<]>....+..-.+.-.........+.-.+..-<++[->.....+..-..+..-..<]>..+.-...+.-.+.-.....+.-.+.-...+.-..<+++[->..+.-...+.-<]>........+.-...+.-.+.-...+.-............+.-....+.-.<++[->...+.-.........<]>+.-..............+.-..+.-.+.-...........+....-..+.....-.+.-..+....-...


                                    Try it online!



                                    I will probably golf this even further soon.







                                    share|improve this answer














                                    share|improve this answer



                                    share|improve this answer








                                    edited 10 hours ago

























                                    answered 2 days ago









                                    orthoplexorthoplex

                                    1614




                                    1614























                                        3












                                        $begingroup$


                                        C# (Visual C# Interactive Compiler), 366 332 329 319 bytes





                                        int i;foreach(var g in"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ")Write(Convert.ToString(g,2).PadLeft(12-i++%2,'0'));


                                        Replace all instances of with to test.



                                        Try it online!




                                        C# (Visual C# Interactive Compiler), 305 bytes, 210 chars





                                        _=>"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ".Select((g,i)=>Convert.ToString(g,2).PadLeft(12-i%2,'0'))


                                        Same with above, replace with with to test. Output as IEnumerable<string>.



                                        Try it online!(Courtesy of Jo King)






                                        share|improve this answer











                                        $endgroup$













                                        • $begingroup$
                                          TIO link with NUL bytes
                                          $endgroup$
                                          – Jo King
                                          yesterday










                                        • $begingroup$
                                          I believe the ++ in 12-i++%2 is a nop (at least, it worked for me when I removed it)
                                          $endgroup$
                                          – someone
                                          yesterday










                                        • $begingroup$
                                          @someone They are a copy-paste from the old answer I forgot to remove
                                          $endgroup$
                                          – Embodiment of Ignorance
                                          yesterday
















                                        3












                                        $begingroup$


                                        C# (Visual C# Interactive Compiler), 366 332 329 319 bytes





                                        int i;foreach(var g in"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ")Write(Convert.ToString(g,2).PadLeft(12-i++%2,'0'));


                                        Replace all instances of with to test.



                                        Try it online!




                                        C# (Visual C# Interactive Compiler), 305 bytes, 210 chars





                                        _=>"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ".Select((g,i)=>Convert.ToString(g,2).PadLeft(12-i%2,'0'))


                                        Same with above, replace with with to test. Output as IEnumerable<string>.



                                        Try it online!(Courtesy of Jo King)






                                        share|improve this answer











                                        $endgroup$













                                        • $begingroup$
                                          TIO link with NUL bytes
                                          $endgroup$
                                          – Jo King
                                          yesterday










                                        • $begingroup$
                                          I believe the ++ in 12-i++%2 is a nop (at least, it worked for me when I removed it)
                                          $endgroup$
                                          – someone
                                          yesterday










                                        • $begingroup$
                                          @someone They are a copy-paste from the old answer I forgot to remove
                                          $endgroup$
                                          – Embodiment of Ignorance
                                          yesterday














                                        3












                                        3








                                        3





                                        $begingroup$


                                        C# (Visual C# Interactive Compiler), 366 332 329 319 bytes





                                        int i;foreach(var g in"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ")Write(Convert.ToString(g,2).PadLeft(12-i++%2,'0'));


                                        Replace all instances of with to test.



                                        Try it online!




                                        C# (Visual C# Interactive Compiler), 305 bytes, 210 chars





                                        _=>"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ".Select((g,i)=>Convert.ToString(g,2).PadLeft(12-i%2,'0'))


                                        Same with above, replace with with to test. Output as IEnumerable<string>.



                                        Try it online!(Courtesy of Jo King)






                                        share|improve this answer











                                        $endgroup$




                                        C# (Visual C# Interactive Compiler), 366 332 329 319 bytes





                                        int i;foreach(var g in"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ")Write(Convert.ToString(g,2).PadLeft(12-i++%2,'0'));


                                        Replace all instances of with to test.



                                        Try it online!




                                        C# (Visual C# Interactive Compiler), 305 bytes, 210 chars





                                        _=>"*ЀʂЄ࢈ҲપԤ␀␀␀؀ȀȀȀ؀␀␀సؘࠀƐഘؚ྾ߟ␀␀Ā␀␀ྀ␀␀రܘࠈഌΚ྾ߟ␀␀ă␀ྃ␀ȁăÃ1`ƀ1`ÃĂȃЃЁȂĀ`ÀƀȺ؀Ȃ␀ȏЀȗɛ'Ŀஇ7;ȅ?ȅ0ȍЀ␀␀΂␀ΨՕ΀Ŕ␀ŀЀ?܀àǀƀ`̀°٠Ƙѐʈш҈EB@Ѐޟɸ".Select((g,i)=>Convert.ToString(g,2).PadLeft(12-i%2,'0'))


                                        Same with above, replace with with to test. Output as IEnumerable<string>.



                                        Try it online!(Courtesy of Jo King)







                                        share|improve this answer














                                        share|improve this answer



                                        share|improve this answer








                                        edited yesterday

























                                        answered 2 days ago









                                        Embodiment of IgnoranceEmbodiment of Ignorance

                                        2,946127




                                        2,946127












                                        • $begingroup$
                                          TIO link with NUL bytes
                                          $endgroup$
                                          – Jo King
                                          yesterday










                                        • $begingroup$
                                          I believe the ++ in 12-i++%2 is a nop (at least, it worked for me when I removed it)
                                          $endgroup$
                                          – someone
                                          yesterday










                                        • $begingroup$
                                          @someone They are a copy-paste from the old answer I forgot to remove
                                          $endgroup$
                                          – Embodiment of Ignorance
                                          yesterday


















                                        • $begingroup$
                                          TIO link with NUL bytes
                                          $endgroup$
                                          – Jo King
                                          yesterday










                                        • $begingroup$
                                          I believe the ++ in 12-i++%2 is a nop (at least, it worked for me when I removed it)
                                          $endgroup$
                                          – someone
                                          yesterday










                                        • $begingroup$
                                          @someone They are a copy-paste from the old answer I forgot to remove
                                          $endgroup$
                                          – Embodiment of Ignorance
                                          yesterday
















                                        $begingroup$
                                        TIO link with NUL bytes
                                        $endgroup$
                                        – Jo King
                                        yesterday




                                        $begingroup$
                                        TIO link with NUL bytes
                                        $endgroup$
                                        – Jo King
                                        yesterday












                                        $begingroup$
                                        I believe the ++ in 12-i++%2 is a nop (at least, it worked for me when I removed it)
                                        $endgroup$
                                        – someone
                                        yesterday




                                        $begingroup$
                                        I believe the ++ in 12-i++%2 is a nop (at least, it worked for me when I removed it)
                                        $endgroup$
                                        – someone
                                        yesterday












                                        $begingroup$
                                        @someone They are a copy-paste from the old answer I forgot to remove
                                        $endgroup$
                                        – Embodiment of Ignorance
                                        yesterday




                                        $begingroup$
                                        @someone They are a copy-paste from the old answer I forgot to remove
                                        $endgroup$
                                        – Embodiment of Ignorance
                                        yesterday











                                        2












                                        $begingroup$


                                        Deadfish~, 1115 bytes



                                        ooooooiodoiodoiodoiod{o}{i}c{d}ooiodoiodoooooiodoiodoooooooiodoo{i}c{d}iodoooiodoooiodoooiodooiodoioodooiodo{i}c{d}iodoiodoiodoiodoiodoiodoiodoiodooiodooiodoo{i}c{d}{oo}ooo{i}c{d}{o}ooioodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}oooooooooiodoiodoiodooooooooo{i}c{d}oooooooooiooooodooooooooo{i}c{d}{oo}ooo{i}c{d}ioodooooiooodoooioodooooioodooo{i}c{d}iod{o}oooioodooiodoooo{i}c{d}ioodoiodoooioodoooioodooooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiod{o}oooooooiodo{i}c{d}{oo}ooo{i}c{d}ooooiod{o}oooooooiod{i}c{d}ioooood{o}oooioooood{i}c{d}{oo}ooo{i}c{d}ioodooooioodooooiooodoooioodooo{i}c{d}iodoooooooiodoooooooooiodoooo{i}c{d}ioodoiodooooioodoooiooodooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiodooooooioodoooooooooiodo{i}c{d}{o}iood{o}o{i}c{d}ooooiodoooooiood{o}iod{i}c{d}iooooodoooooioodooooooioooood{i}c{d}{o}iood{o}o{i}c{d}ooiodooooooooiodooooooooiodoo{i}c{d}oooiodooooooioodoooooooiodooo{i}c{d}ooooioodooooioodooooooiodoooo{i}c{d}ooooooioodoooiodooooioodooooo{i}c{d}{o}ioodooioodooooooo{i}c{d}ooooooioodoooiodooooioodooooo


                                        Try it online!



                                        If someone has the patience to golf this further, I salute you ahead of time. :P






                                        share|improve this answer









                                        $endgroup$


















                                          2












                                          $begingroup$


                                          Deadfish~, 1115 bytes



                                          ooooooiodoiodoiodoiod{o}{i}c{d}ooiodoiodoooooiodoiodoooooooiodoo{i}c{d}iodoooiodoooiodoooiodooiodoioodooiodo{i}c{d}iodoiodoiodoiodoiodoiodoiodoiodooiodooiodoo{i}c{d}{oo}ooo{i}c{d}{o}ooioodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}oooooooooiodoiodoiodooooooooo{i}c{d}oooooooooiooooodooooooooo{i}c{d}{oo}ooo{i}c{d}ioodooooiooodoooioodooooioodooo{i}c{d}iod{o}oooioodooiodoooo{i}c{d}ioodoiodoooioodoooioodooooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiod{o}oooooooiodo{i}c{d}{oo}ooo{i}c{d}ooooiod{o}oooooooiod{i}c{d}ioooood{o}oooioooood{i}c{d}{oo}ooo{i}c{d}ioodooooioodooooiooodoooioodooo{i}c{d}iodoooooooiodoooooooooiodoooo{i}c{d}ioodoiodooooioodoooiooodooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiodooooooioodoooooooooiodo{i}c{d}{o}iood{o}o{i}c{d}ooooiodoooooiood{o}iod{i}c{d}iooooodoooooioodooooooioooood{i}c{d}{o}iood{o}o{i}c{d}ooiodooooooooiodooooooooiodoo{i}c{d}oooiodooooooioodoooooooiodooo{i}c{d}ooooioodooooioodooooooiodoooo{i}c{d}ooooooioodoooiodooooioodooooo{i}c{d}{o}ioodooioodooooooo{i}c{d}ooooooioodoooiodooooioodooooo


                                          Try it online!



                                          If someone has the patience to golf this further, I salute you ahead of time. :P






                                          share|improve this answer









                                          $endgroup$
















                                            2












                                            2








                                            2





                                            $begingroup$


                                            Deadfish~, 1115 bytes



                                            ooooooiodoiodoiodoiod{o}{i}c{d}ooiodoiodoooooiodoiodoooooooiodoo{i}c{d}iodoooiodoooiodoooiodooiodoioodooiodo{i}c{d}iodoiodoiodoiodoiodoiodoiodoiodooiodooiodoo{i}c{d}{oo}ooo{i}c{d}{o}ooioodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}oooooooooiodoiodoiodooooooooo{i}c{d}oooooooooiooooodooooooooo{i}c{d}{oo}ooo{i}c{d}ioodooooiooodoooioodooooioodooo{i}c{d}iod{o}oooioodooiodoooo{i}c{d}ioodoiodoooioodoooioodooooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiod{o}oooooooiodo{i}c{d}{oo}ooo{i}c{d}ooooiod{o}oooooooiod{i}c{d}ioooood{o}oooioooood{i}c{d}{oo}ooo{i}c{d}ioodooooioodooooiooodoooioodooo{i}c{d}iodoooooooiodoooooooooiodoooo{i}c{d}ioodoiodooooioodoooiooodooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiodooooooioodoooooooooiodo{i}c{d}{o}iood{o}o{i}c{d}ooooiodoooooiood{o}iod{i}c{d}iooooodoooooioodooooooioooood{i}c{d}{o}iood{o}o{i}c{d}ooiodooooooooiodooooooooiodoo{i}c{d}oooiodooooooioodoooooooiodooo{i}c{d}ooooioodooooioodooooooiodoooo{i}c{d}ooooooioodoooiodooooioodooooo{i}c{d}{o}ioodooioodooooooo{i}c{d}ooooooioodoooiodooooioodooooo


                                            Try it online!



                                            If someone has the patience to golf this further, I salute you ahead of time. :P






                                            share|improve this answer









                                            $endgroup$




                                            Deadfish~, 1115 bytes



                                            ooooooiodoiodoiodoiod{o}{i}c{d}ooiodoiodoooooiodoiodoooooooiodoo{i}c{d}iodoooiodoooiodoooiodooiodoioodooiodo{i}c{d}iodoiodoiodoiodoiodoiodoiodoiodooiodooiodoo{i}c{d}{oo}ooo{i}c{d}{o}ooioodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}{o}ioodoiodooooooooo{i}c{d}oooooooooiodoiodoiodooooooooo{i}c{d}oooooooooiooooodooooooooo{i}c{d}{oo}ooo{i}c{d}ioodooooiooodoooioodooooioodooo{i}c{d}iod{o}oooioodooiodoooo{i}c{d}ioodoiodoooioodoooioodooooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiod{o}oooooooiodo{i}c{d}{oo}ooo{i}c{d}ooooiod{o}oooooooiod{i}c{d}ioooood{o}oooioooood{i}c{d}{oo}ooo{i}c{d}ioodooooioodooooiooodoooioodooo{i}c{d}iodoooooooiodoooooooooiodoooo{i}c{d}ioodoiodooooioodoooiooodooioodoiodo{i}c{d}iooooodoiooooodoiooooodoioooood{i}c{d}{oo}ooo{i}c{d}oooiodooooooioodoooooooooiodo{i}c{d}{o}iood{o}o{i}c{d}ooooiodoooooiood{o}iod{i}c{d}iooooodoooooioodooooooioooood{i}c{d}{o}iood{o}o{i}c{d}ooiodooooooooiodooooooooiodoo{i}c{d}oooiodooooooioodoooooooiodooo{i}c{d}ooooioodooooioodooooooiodoooo{i}c{d}ooooooioodoooiodooooioodooooo{i}c{d}{o}ioodooioodooooooo{i}c{d}ooooooioodoooiodooooioodooooo


                                            Try it online!



                                            If someone has the patience to golf this further, I salute you ahead of time. :P







                                            share|improve this answer












                                            share|improve this answer



                                            share|improve this answer










                                            answered 2 days ago









                                            squidsquid

                                            1214




                                            1214























                                                2












                                                $begingroup$


                                                Perl 6, 368 bytes



                                                .say for :36('FJXOE0PDDNF5Y5EHGB8M9SWMXQOXIKIT9F6ZKWWDEACHCBGXL1N2H60CN0CJ4EMKF7D6MODSKYJVNR4SFTDR6NSM421LQ67B6MWF0G5BQATFOJJJBQ0UFQM64T0MWSQN41C4S5D1QR5KJM2L9UTYMMKUBBQWY45YCMRGO8ZRGTQH7LXMZBUASLCTKX30IH0AYKYEPHO8HFHX8GAY5WM38YOSUX0HABYSH2PPBLRDRZIN5ANAQ3V8PLOZ6EHC0UI95EVJVYD1820T6J14HGX85NWFQET2NWOMSNUT0JW4LHMY90X094TEE9KXJXSNN6YPERFQW').base(2).substr(1).comb(23)


                                                Try it online!



                                                The long string is the message as a single base-36 number (with a single prefixed 1 bit to preserve the leading zeroes) which is then converted back to binary and printed 23 bits at a time.






                                                share|improve this answer









                                                $endgroup$













                                                • $begingroup$
                                                  You can use >>.say and &{S/.//} to save bytes. Have you thought about using a different base instead?
                                                  $endgroup$
                                                  – Jo King
                                                  2 days ago












                                                • $begingroup$
                                                  Yes, I tried using base 65536/Unicode, but the message runs into some forbidden surrogate codepoints. I was able to avoid that by adding a fixed offset to each codepoint, but astonishingly, some of the generated strings crashed Emacs a few times. Resolving the issues started taking more time than I could afford to commit. I'll probably revisit the problem later.
                                                  $endgroup$
                                                  – Sean
                                                  2 days ago










                                                • $begingroup$
                                                  There's no point going into multiple byte characters, since that increases your byte count. 289 bytes by implementing my tips from above and using base 122 (to avoid carriage returns)
                                                  $endgroup$
                                                  – Jo King
                                                  2 days ago


















                                                2












                                                $begingroup$


                                                Perl 6, 368 bytes



                                                .say for :36('FJXOE0PDDNF5Y5EHGB8M9SWMXQOXIKIT9F6ZKWWDEACHCBGXL1N2H60CN0CJ4EMKF7D6MODSKYJVNR4SFTDR6NSM421LQ67B6MWF0G5BQATFOJJJBQ0UFQM64T0MWSQN41C4S5D1QR5KJM2L9UTYMMKUBBQWY45YCMRGO8ZRGTQH7LXMZBUASLCTKX30IH0AYKYEPHO8HFHX8GAY5WM38YOSUX0HABYSH2PPBLRDRZIN5ANAQ3V8PLOZ6EHC0UI95EVJVYD1820T6J14HGX85NWFQET2NWOMSNUT0JW4LHMY90X094TEE9KXJXSNN6YPERFQW').base(2).substr(1).comb(23)


                                                Try it online!



                                                The long string is the message as a single base-36 number (with a single prefixed 1 bit to preserve the leading zeroes) which is then converted back to binary and printed 23 bits at a time.






                                                share|improve this answer









                                                $endgroup$













                                                • $begingroup$
                                                  You can use >>.say and &{S/.//} to save bytes. Have you thought about using a different base instead?
                                                  $endgroup$
                                                  – Jo King
                                                  2 days ago












                                                • $begingroup$
                                                  Yes, I tried using base 65536/Unicode, but the message runs into some forbidden surrogate codepoints. I was able to avoid that by adding a fixed offset to each codepoint, but astonishingly, some of the generated strings crashed Emacs a few times. Resolving the issues started taking more time than I could afford to commit. I'll probably revisit the problem later.
                                                  $endgroup$
                                                  – Sean
                                                  2 days ago










                                                • $begingroup$
                                                  There's no point going into multiple byte characters, since that increases your byte count. 289 bytes by implementing my tips from above and using base 122 (to avoid carriage returns)
                                                  $endgroup$
                                                  – Jo King
                                                  2 days ago
















                                                2












                                                2








                                                2





                                                $begingroup$


                                                Perl 6, 368 bytes



                                                .say for :36('FJXOE0PDDNF5Y5EHGB8M9SWMXQOXIKIT9F6ZKWWDEACHCBGXL1N2H60CN0CJ4EMKF7D6MODSKYJVNR4SFTDR6NSM421LQ67B6MWF0G5BQATFOJJJBQ0UFQM64T0MWSQN41C4S5D1QR5KJM2L9UTYMMKUBBQWY45YCMRGO8ZRGTQH7LXMZBUASLCTKX30IH0AYKYEPHO8HFHX8GAY5WM38YOSUX0HABYSH2PPBLRDRZIN5ANAQ3V8PLOZ6EHC0UI95EVJVYD1820T6J14HGX85NWFQET2NWOMSNUT0JW4LHMY90X094TEE9KXJXSNN6YPERFQW').base(2).substr(1).comb(23)


                                                Try it online!



                                                The long string is the message as a single base-36 number (with a single prefixed 1 bit to preserve the leading zeroes) which is then converted back to binary and printed 23 bits at a time.






                                                share|improve this answer









                                                $endgroup$




                                                Perl 6, 368 bytes



                                                .say for :36('FJXOE0PDDNF5Y5EHGB8M9SWMXQOXIKIT9F6ZKWWDEACHCBGXL1N2H60CN0CJ4EMKF7D6MODSKYJVNR4SFTDR6NSM421LQ67B6MWF0G5BQATFOJJJBQ0UFQM64T0MWSQN41C4S5D1QR5KJM2L9UTYMMKUBBQWY45YCMRGO8ZRGTQH7LXMZBUASLCTKX30IH0AYKYEPHO8HFHX8GAY5WM38YOSUX0HABYSH2PPBLRDRZIN5ANAQ3V8PLOZ6EHC0UI95EVJVYD1820T6J14HGX85NWFQET2NWOMSNUT0JW4LHMY90X094TEE9KXJXSNN6YPERFQW').base(2).substr(1).comb(23)


                                                Try it online!



                                                The long string is the message as a single base-36 number (with a single prefixed 1 bit to preserve the leading zeroes) which is then converted back to binary and printed 23 bits at a time.







                                                share|improve this answer












                                                share|improve this answer



                                                share|improve this answer










                                                answered 2 days ago









                                                SeanSean

                                                3,54637




                                                3,54637












                                                • $begingroup$
                                                  You can use >>.say and &{S/.//} to save bytes. Have you thought about using a different base instead?
                                                  $endgroup$
                                                  – Jo King
                                                  2 days ago












                                                • $begingroup$
                                                  Yes, I tried using base 65536/Unicode, but the message runs into some forbidden surrogate codepoints. I was able to avoid that by adding a fixed offset to each codepoint, but astonishingly, some of the generated strings crashed Emacs a few times. Resolving the issues started taking more time than I could afford to commit. I'll probably revisit the problem later.
                                                  $endgroup$
                                                  – Sean
                                                  2 days ago










                                                • $begingroup$
                                                  There's no point going into multiple byte characters, since that increases your byte count. 289 bytes by implementing my tips from above and using base 122 (to avoid carriage returns)
                                                  $endgroup$
                                                  – Jo King
                                                  2 days ago




















                                                • $begingroup$
                                                  You can use >>.say and &{S/.//} to save bytes. Have you thought about using a different base instead?
                                                  $endgroup$
                                                  – Jo King
                                                  2 days ago












                                                • $begingroup$
                                                  Yes, I tried using base 65536/Unicode, but the message runs into some forbidden surrogate codepoints. I was able to avoid that by adding a fixed offset to each codepoint, but astonishingly, some of the generated strings crashed Emacs a few times. Resolving the issues started taking more time than I could afford to commit. I'll probably revisit the problem later.
                                                  $endgroup$
                                                  – Sean
                                                  2 days ago










                                                • $begingroup$
                                                  There's no point going into multiple byte characters, since that increases your byte count. 289 bytes by implementing my tips from above and using base 122 (to avoid carriage returns)
                                                  $endgroup$
                                                  – Jo King
                                                  2 days ago


















                                                $begingroup$
                                                You can use >>.say and &{S/.//} to save bytes. Have you thought about using a different base instead?
                                                $endgroup$
                                                – Jo King
                                                2 days ago






                                                $begingroup$
                                                You can use >>.say and &{S/.//} to save bytes. Have you thought about using a different base instead?
                                                $endgroup$
                                                – Jo King
                                                2 days ago














                                                $begingroup$
                                                Yes, I tried using base 65536/Unicode, but the message runs into some forbidden surrogate codepoints. I was able to avoid that by adding a fixed offset to each codepoint, but astonishingly, some of the generated strings crashed Emacs a few times. Resolving the issues started taking more time than I could afford to commit. I'll probably revisit the problem later.
                                                $endgroup$
                                                – Sean
                                                2 days ago




                                                $begingroup$
                                                Yes, I tried using base 65536/Unicode, but the message runs into some forbidden surrogate codepoints. I was able to avoid that by adding a fixed offset to each codepoint, but astonishingly, some of the generated strings crashed Emacs a few times. Resolving the issues started taking more time than I could afford to commit. I'll probably revisit the problem later.
                                                $endgroup$
                                                – Sean
                                                2 days ago












                                                $begingroup$
                                                There's no point going into multiple byte characters, since that increases your byte count. 289 bytes by implementing my tips from above and using base 122 (to avoid carriage returns)
                                                $endgroup$
                                                – Jo King
                                                2 days ago






                                                $begingroup$
                                                There's no point going into multiple byte characters, since that increases your byte count. 289 bytes by implementing my tips from above and using base 122 (to avoid carriage returns)
                                                $endgroup$
                                                – Jo King
                                                2 days ago













                                                2












                                                $begingroup$


                                                Wolfram Language (Mathematica), 383 bytes



                                                StringPartition[Uncompress@"1:eJylVNsRwjAM44s92KBaBTZgAUZhZXqtHUuOWrgjfSRRHFlO4tyer/vjfb1clq0gHirZLRjby986hppcT5p+L3BmgJ3t4Ul4GsNyG++7YbaXLh0ZTPhXa4Sn+X/s9Qfk3Hx2cOaSIuNYaVu5laschvgzSqAjHeZBhilKgKBDEhw0upJRg+HOK4MyNC29sfbc3RV0VPDqeLiRTsG1ulExq1IitpunOa7asnYM9siDZ6eidUCkEzBOUbCkGIig4aTyUGBYWAX6W6aXIWGGI/HlhmsqzSU0QTZjkMVpaX5sBsm1OGKVg1qdjKP0EdyqZBRLhukn8DLBQav6kccgz8OKfgBzjj6Z",23]


                                                Try it online!






                                                share|improve this answer









                                                $endgroup$


















                                                  2












                                                  $begingroup$


                                                  Wolfram Language (Mathematica), 383 bytes



                                                  StringPartition[Uncompress@"1:eJylVNsRwjAM44s92KBaBTZgAUZhZXqtHUuOWrgjfSRRHFlO4tyer/vjfb1clq0gHirZLRjby986hppcT5p+L3BmgJ3t4Ul4GsNyG++7YbaXLh0ZTPhXa4Sn+X/s9Qfk3Hx2cOaSIuNYaVu5laschvgzSqAjHeZBhilKgKBDEhw0upJRg+HOK4MyNC29sfbc3RV0VPDqeLiRTsG1ulExq1IitpunOa7asnYM9siDZ6eidUCkEzBOUbCkGIig4aTyUGBYWAX6W6aXIWGGI/HlhmsqzSU0QTZjkMVpaX5sBsm1OGKVg1qdjKP0EdyqZBRLhukn8DLBQav6kccgz8OKfgBzjj6Z",23]


                                                  Try it online!






                                                  share|improve this answer









                                                  $endgroup$
















                                                    2












                                                    2








                                                    2





                                                    $begingroup$


                                                    Wolfram Language (Mathematica), 383 bytes



                                                    StringPartition[Uncompress@"1:eJylVNsRwjAM44s92KBaBTZgAUZhZXqtHUuOWrgjfSRRHFlO4tyer/vjfb1clq0gHirZLRjby986hppcT5p+L3BmgJ3t4Ul4GsNyG++7YbaXLh0ZTPhXa4Sn+X/s9Qfk3Hx2cOaSIuNYaVu5laschvgzSqAjHeZBhilKgKBDEhw0upJRg+HOK4MyNC29sfbc3RV0VPDqeLiRTsG1ulExq1IitpunOa7asnYM9siDZ6eidUCkEzBOUbCkGIig4aTyUGBYWAX6W6aXIWGGI/HlhmsqzSU0QTZjkMVpaX5sBsm1OGKVg1qdjKP0EdyqZBRLhukn8DLBQav6kccgz8OKfgBzjj6Z",23]


                                                    Try it online!






                                                    share|improve this answer









                                                    $endgroup$




                                                    Wolfram Language (Mathematica), 383 bytes



                                                    StringPartition[Uncompress@"1:eJylVNsRwjAM44s92KBaBTZgAUZhZXqtHUuOWrgjfSRRHFlO4tyer/vjfb1clq0gHirZLRjby986hppcT5p+L3BmgJ3t4Ul4GsNyG++7YbaXLh0ZTPhXa4Sn+X/s9Qfk3Hx2cOaSIuNYaVu5laschvgzSqAjHeZBhilKgKBDEhw0upJRg+HOK4MyNC29sfbc3RV0VPDqeLiRTsG1ulExq1IitpunOa7asnYM9siDZ6eidUCkEzBOUbCkGIig4aTyUGBYWAX6W6aXIWGGI/HlhmsqzSU0QTZjkMVpaX5sBsm1OGKVg1qdjKP0EdyqZBRLhukn8DLBQav6kccgz8OKfgBzjj6Z",23]


                                                    Try it online!







                                                    share|improve this answer












                                                    share|improve this answer



                                                    share|improve this answer










                                                    answered 2 days ago









                                                    J42161217J42161217

                                                    13.9k21353




                                                    13.9k21353























                                                        2












                                                        $begingroup$


                                                        Node.js, 333 bytes



                                                        Returns a binary string of 1,679 characters.





                                                        _=>Buffer(")SI)=.);1K?>>>2333A3,93/I3>3)g33)AEAAI)5JQZJTddda3)*3*33+3,e)*e3)//0/1+)1C/7Cgggg3395)9)A3IY)h*IH),39+)995*)AA-)59Y)*O3Z,)//*)91**)A*-)Y+1)I11+)I1)/)5)Y*0?)+)I)-0Y)1@;_*7<gaE/a)Q7[*9HM+IY16I33)a1)*^.><I+S3.38I)*hY)7)a)Y)A,9*A5Y/A:9=9K:1I-=9)19I)9*329)GH<").map(x=>s+=(x-51&&x-41).toString(2).padStart(x-51?6:12,0),s='')&&s


                                                        Try it online! (with formatted output)





                                                        JavaScript (ES8), 413 bytes



                                                        Returns a binary string of 1,679 characters.





                                                        _=>atob('AsKoAFBQEiIlwpVVUk!!ABwo!DQ!Gg!V!Aw7g!!GHGHCi!yGjHChsK+w7vDr8K!!Q!Q!!g!/DgAHDs!AGGHDhiAgCGhjwprDu8Ovwr4!ABAw4AQAcK!MKDAD8GB8OAD!QCAQQMBAYYEAMQwABwpgAMQwBwoYEBAgEEBgEQDAIwoAgIMKAwoDCgMKABgDDgDAEdcKACAgAEHwAIXTCtgTDpMO+w6HDgcK4AsKDwrIFB8OkCgwINg!!A4IAB1FVTDoArCo!U!/CgAB/w4ADwoDDoAwAYDQBYMOMBmEUFEIkSMKARR!woQgAQB!MKUAHnDtA'.split`!`.join`AA`).replace(/[sS]/g,c=>c.charCodeAt().toString(2).padStart(8,0))


                                                        Try it online! (with formatted output)






                                                        share|improve this answer











                                                        $endgroup$


















                                                          2












                                                          $begingroup$


                                                          Node.js, 333 bytes



                                                          Returns a binary string of 1,679 characters.





                                                          _=>Buffer(")SI)=.);1K?>>>2333A3,93/I3>3)g33)AEAAI)5JQZJTddda3)*3*33+3,e)*e3)//0/1+)1C/7Cgggg3395)9)A3IY)h*IH),39+)995*)AA-)59Y)*O3Z,)//*)91**)A*-)Y+1)I11+)I1)/)5)Y*0?)+)I)-0Y)1@;_*7<gaE/a)Q7[*9HM+IY16I33)a1)*^.><I+S3.38I)*hY)7)a)Y)A,9*A5Y/A:9=9K:1I-=9)19I)9*329)GH<").map(x=>s+=(x-51&&x-41).toString(2).padStart(x-51?6:12,0),s='')&&s


                                                          Try it online! (with formatted output)





                                                          JavaScript (ES8), 413 bytes



                                                          Returns a binary string of 1,679 characters.





                                                          _=>atob('AsKoAFBQEiIlwpVVUk!!ABwo!DQ!Gg!V!Aw7g!!GHGHCi!yGjHChsK+w7vDr8K!!Q!Q!!g!/DgAHDs!AGGHDhiAgCGhjwprDu8Ovwr4!ABAw4AQAcK!MKDAD8GB8OAD!QCAQQMBAYYEAMQwABwpgAMQwBwoYEBAgEEBgEQDAIwoAgIMKAwoDCgMKABgDDgDAEdcKACAgAEHwAIXTCtgTDpMO+w6HDgcK4AsKDwrIFB8OkCgwINg!!A4IAB1FVTDoArCo!U!/CgAB/w4ADwoDDoAwAYDQBYMOMBmEUFEIkSMKARR!woQgAQB!MKUAHnDtA'.split`!`.join`AA`).replace(/[sS]/g,c=>c.charCodeAt().toString(2).padStart(8,0))


                                                          Try it online! (with formatted output)






                                                          share|improve this answer











                                                          $endgroup$
















                                                            2












                                                            2








                                                            2





                                                            $begingroup$


                                                            Node.js, 333 bytes



                                                            Returns a binary string of 1,679 characters.





                                                            _=>Buffer(")SI)=.);1K?>>>2333A3,93/I3>3)g33)AEAAI)5JQZJTddda3)*3*33+3,e)*e3)//0/1+)1C/7Cgggg3395)9)A3IY)h*IH),39+)995*)AA-)59Y)*O3Z,)//*)91**)A*-)Y+1)I11+)I1)/)5)Y*0?)+)I)-0Y)1@;_*7<gaE/a)Q7[*9HM+IY16I33)a1)*^.><I+S3.38I)*hY)7)a)Y)A,9*A5Y/A:9=9K:1I-=9)19I)9*329)GH<").map(x=>s+=(x-51&&x-41).toString(2).padStart(x-51?6:12,0),s='')&&s


                                                            Try it online! (with formatted output)





                                                            JavaScript (ES8), 413 bytes



                                                            Returns a binary string of 1,679 characters.





                                                            _=>atob('AsKoAFBQEiIlwpVVUk!!ABwo!DQ!Gg!V!Aw7g!!GHGHCi!yGjHChsK+w7vDr8K!!Q!Q!!g!/DgAHDs!AGGHDhiAgCGhjwprDu8Ovwr4!ABAw4AQAcK!MKDAD8GB8OAD!QCAQQMBAYYEAMQwABwpgAMQwBwoYEBAgEEBgEQDAIwoAgIMKAwoDCgMKABgDDgDAEdcKACAgAEHwAIXTCtgTDpMO+w6HDgcK4AsKDwrIFB8OkCgwINg!!A4IAB1FVTDoArCo!U!/CgAB/w4ADwoDDoAwAYDQBYMOMBmEUFEIkSMKARR!woQgAQB!MKUAHnDtA'.split`!`.join`AA`).replace(/[sS]/g,c=>c.charCodeAt().toString(2).padStart(8,0))


                                                            Try it online! (with formatted output)






                                                            share|improve this answer











                                                            $endgroup$




                                                            Node.js, 333 bytes



                                                            Returns a binary string of 1,679 characters.





                                                            _=>Buffer(")SI)=.);1K?>>>2333A3,93/I3>3)g33)AEAAI)5JQZJTddda3)*3*33+3,e)*e3)//0/1+)1C/7Cgggg3395)9)A3IY)h*IH),39+)995*)AA-)59Y)*O3Z,)//*)91**)A*-)Y+1)I11+)I1)/)5)Y*0?)+)I)-0Y)1@;_*7<gaE/a)Q7[*9HM+IY16I33)a1)*^.><I+S3.38I)*hY)7)a)Y)A,9*A5Y/A:9=9K:1I-=9)19I)9*329)GH<").map(x=>s+=(x-51&&x-41).toString(2).padStart(x-51?6:12,0),s='')&&s


                                                            Try it online! (with formatted output)





                                                            JavaScript (ES8), 413 bytes



                                                            Returns a binary string of 1,679 characters.





                                                            _=>atob('AsKoAFBQEiIlwpVVUk!!ABwo!DQ!Gg!V!Aw7g!!GHGHCi!yGjHChsK+w7vDr8K!!Q!Q!!g!/DgAHDs!AGGHDhiAgCGhjwprDu8Ovwr4!ABAw4AQAcK!MKDAD8GB8OAD!QCAQQMBAYYEAMQwABwpgAMQwBwoYEBAgEEBgEQDAIwoAgIMKAwoDCgMKABgDDgDAEdcKACAgAEHwAIXTCtgTDpMO+w6HDgcK4AsKDwrIFB8OkCgwINg!!A4IAB1FVTDoArCo!U!/CgAB/w4ADwoDDoAwAYDQBYMOMBmEUFEIkSMKARR!woQgAQB!MKUAHnDtA'.split`!`.join`AA`).replace(/[sS]/g,c=>c.charCodeAt().toString(2).padStart(8,0))


                                                            Try it online! (with formatted output)







                                                            share|improve this answer














                                                            share|improve this answer



                                                            share|improve this answer








                                                            edited 2 days ago

























                                                            answered 2 days ago









                                                            ArnauldArnauld

                                                            80.8k797334




                                                            80.8k797334























                                                                2












                                                                $begingroup$

                                                                Bubblegum, 275 236 bytes



                                                                00000000: e006 8e00 e45d 0018 6988 6507 a228 f86f  .....]..i.e..(.o
                                                                00000010: f042 c62f d4d7 b99e 38bc 56c4 52e8 2630 .B./....8.V.R.&0
                                                                00000020: 8aaa 7252 d47d 5ef4 c96a 511f 6842 423f ..rR.}^..jQ.hBB?
                                                                00000030: 4532 ca9f 22d3 1633 e0c4 665a d5dc 4e68 E2.."..3..fZ..Nh
                                                                00000040: 7b09 76ae 3c7e f9d4 fa4a 05e0 4163 c580 {.v.<~...J..Ac..
                                                                00000050: c585 a383 2396 4ca9 1f48 a4b9 744e 37c8 ....#.L..H..tN7.
                                                                00000060: 68c5 af23 645d 59a7 542a e6d1 23b9 3aba h..#d]Y.T*..#.:.
                                                                00000070: f0e6 2738 dfd5 b0a3 c6a3 60bf c5b6 5ae6 ..'8......`...Z.
                                                                00000080: 7893 30a8 ae04 edf9 298b b777 4d56 285b x.0.....)..wMV([
                                                                00000090: cb74 07cc 7a7b a399 3dc7 c6e7 b693 e715 .t..z{..=.......
                                                                000000a0: d908 876e 001f 7408 3c6a 5fcd 37cb 02c4 ...n..t.<j_.7...
                                                                000000b0: 93de 33c2 a11e 5bac cd12 d99a fac3 e0fa ..3...[.........
                                                                000000c0: 5268 94f7 d640 0f73 cede f79d 821f 39d1 Rh...@.s......9.
                                                                000000d0: dc49 ff06 6962 6c31 dc29 a077 01c3 7690 .I..ibl1.).w..v.
                                                                000000e0: 85ef bbec 31d7 5c7f f9fc 8c00 ....1......


                                                                Try it online!






                                                                share|improve this answer











                                                                $endgroup$


















                                                                  2












                                                                  $begingroup$

                                                                  Bubblegum, 275 236 bytes



                                                                  00000000: e006 8e00 e45d 0018 6988 6507 a228 f86f  .....]..i.e..(.o
                                                                  00000010: f042 c62f d4d7 b99e 38bc 56c4 52e8 2630 .B./....8.V.R.&0
                                                                  00000020: 8aaa 7252 d47d 5ef4 c96a 511f 6842 423f ..rR.}^..jQ.hBB?
                                                                  00000030: 4532 ca9f 22d3 1633 e0c4 665a d5dc 4e68 E2.."..3..fZ..Nh
                                                                  00000040: 7b09 76ae 3c7e f9d4 fa4a 05e0 4163 c580 {.v.<~...J..Ac..
                                                                  00000050: c585 a383 2396 4ca9 1f48 a4b9 744e 37c8 ....#.L..H..tN7.
                                                                  00000060: 68c5 af23 645d 59a7 542a e6d1 23b9 3aba h..#d]Y.T*..#.:.
                                                                  00000070: f0e6 2738 dfd5 b0a3 c6a3 60bf c5b6 5ae6 ..'8......`...Z.
                                                                  00000080: 7893 30a8 ae04 edf9 298b b777 4d56 285b x.0.....)..wMV([
                                                                  00000090: cb74 07cc 7a7b a399 3dc7 c6e7 b693 e715 .t..z{..=.......
                                                                  000000a0: d908 876e 001f 7408 3c6a 5fcd 37cb 02c4 ...n..t.<j_.7...
                                                                  000000b0: 93de 33c2 a11e 5bac cd12 d99a fac3 e0fa ..3...[.........
                                                                  000000c0: 5268 94f7 d640 0f73 cede f79d 821f 39d1 Rh...@.s......9.
                                                                  000000d0: dc49 ff06 6962 6c31 dc29 a077 01c3 7690 .I..ibl1.).w..v.
                                                                  000000e0: 85ef bbec 31d7 5c7f f9fc 8c00 ....1......


                                                                  Try it online!






                                                                  share|improve this answer











                                                                  $endgroup$
















                                                                    2












                                                                    2








                                                                    2





                                                                    $begingroup$

                                                                    Bubblegum, 275 236 bytes



                                                                    00000000: e006 8e00 e45d 0018 6988 6507 a228 f86f  .....]..i.e..(.o
                                                                    00000010: f042 c62f d4d7 b99e 38bc 56c4 52e8 2630 .B./....8.V.R.&0
                                                                    00000020: 8aaa 7252 d47d 5ef4 c96a 511f 6842 423f ..rR.}^..jQ.hBB?
                                                                    00000030: 4532 ca9f 22d3 1633 e0c4 665a d5dc 4e68 E2.."..3..fZ..Nh
                                                                    00000040: 7b09 76ae 3c7e f9d4 fa4a 05e0 4163 c580 {.v.<~...J..Ac..
                                                                    00000050: c585 a383 2396 4ca9 1f48 a4b9 744e 37c8 ....#.L..H..tN7.
                                                                    00000060: 68c5 af23 645d 59a7 542a e6d1 23b9 3aba h..#d]Y.T*..#.:.
                                                                    00000070: f0e6 2738 dfd5 b0a3 c6a3 60bf c5b6 5ae6 ..'8......`...Z.
                                                                    00000080: 7893 30a8 ae04 edf9 298b b777 4d56 285b x.0.....)..wMV([
                                                                    00000090: cb74 07cc 7a7b a399 3dc7 c6e7 b693 e715 .t..z{..=.......
                                                                    000000a0: d908 876e 001f 7408 3c6a 5fcd 37cb 02c4 ...n..t.<j_.7...
                                                                    000000b0: 93de 33c2 a11e 5bac cd12 d99a fac3 e0fa ..3...[.........
                                                                    000000c0: 5268 94f7 d640 0f73 cede f79d 821f 39d1 Rh...@.s......9.
                                                                    000000d0: dc49 ff06 6962 6c31 dc29 a077 01c3 7690 .I..ibl1.).w..v.
                                                                    000000e0: 85ef bbec 31d7 5c7f f9fc 8c00 ....1......


                                                                    Try it online!






                                                                    share|improve this answer











                                                                    $endgroup$



                                                                    Bubblegum, 275 236 bytes



                                                                    00000000: e006 8e00 e45d 0018 6988 6507 a228 f86f  .....]..i.e..(.o
                                                                    00000010: f042 c62f d4d7 b99e 38bc 56c4 52e8 2630 .B./....8.V.R.&0
                                                                    00000020: 8aaa 7252 d47d 5ef4 c96a 511f 6842 423f ..rR.}^..jQ.hBB?
                                                                    00000030: 4532 ca9f 22d3 1633 e0c4 665a d5dc 4e68 E2.."..3..fZ..Nh
                                                                    00000040: 7b09 76ae 3c7e f9d4 fa4a 05e0 4163 c580 {.v.<~...J..Ac..
                                                                    00000050: c585 a383 2396 4ca9 1f48 a4b9 744e 37c8 ....#.L..H..tN7.
                                                                    00000060: 68c5 af23 645d 59a7 542a e6d1 23b9 3aba h..#d]Y.T*..#.:.
                                                                    00000070: f0e6 2738 dfd5 b0a3 c6a3 60bf c5b6 5ae6 ..'8......`...Z.
                                                                    00000080: 7893 30a8 ae04 edf9 298b b777 4d56 285b x.0.....)..wMV([
                                                                    00000090: cb74 07cc 7a7b a399 3dc7 c6e7 b693 e715 .t..z{..=.......
                                                                    000000a0: d908 876e 001f 7408 3c6a 5fcd 37cb 02c4 ...n..t.<j_.7...
                                                                    000000b0: 93de 33c2 a11e 5bac cd12 d99a fac3 e0fa ..3...[.........
                                                                    000000c0: 5268 94f7 d640 0f73 cede f79d 821f 39d1 Rh...@.s......9.
                                                                    000000d0: dc49 ff06 6962 6c31 dc29 a077 01c3 7690 .I..ibl1.).w..v.
                                                                    000000e0: 85ef bbec 31d7 5c7f f9fc 8c00 ....1......


                                                                    Try it online!







                                                                    share|improve this answer














                                                                    share|improve this answer



                                                                    share|improve this answer








                                                                    edited yesterday

























                                                                    answered 2 days ago









                                                                    orthoplexorthoplex

                                                                    1614




                                                                    1614























                                                                        1












                                                                        $begingroup$


                                                                        Perl 5, 460 bytes





                                                                        printf"%023b",oct"0x$_"for qw/15400 141404 4444b2 555524 0 600 1a00 1a00 2a00 3e00 0 61c618 400190 68c61a 7df7df 0 80002 0 40001 7c001f 0 618718 404010 68639a 7df7df 0 81802 1800 41801 7c181f 1800 100804 81808 61810 18860 1980 18860 61810 81008 101804 201804 200808 101010 80060 60180 11d600 101000 107c00 10ba5b 1393f 5c3837 283b 10283f 102830 106c00 0 1c1000 1d4555 1c0154 140 7c00 1ff00 701c0 c0060 1a00b0 330198 228288 224488 22880 21080 20080 9400 3cfa78/


                                                                        Try it online!






                                                                        share|improve this answer









                                                                        $endgroup$


















                                                                          1












                                                                          $begingroup$


                                                                          Perl 5, 460 bytes





                                                                          printf"%023b",oct"0x$_"for qw/15400 141404 4444b2 555524 0 600 1a00 1a00 2a00 3e00 0 61c618 400190 68c61a 7df7df 0 80002 0 40001 7c001f 0 618718 404010 68639a 7df7df 0 81802 1800 41801 7c181f 1800 100804 81808 61810 18860 1980 18860 61810 81008 101804 201804 200808 101010 80060 60180 11d600 101000 107c00 10ba5b 1393f 5c3837 283b 10283f 102830 106c00 0 1c1000 1d4555 1c0154 140 7c00 1ff00 701c0 c0060 1a00b0 330198 228288 224488 22880 21080 20080 9400 3cfa78/


                                                                          Try it online!






                                                                          share|improve this answer









                                                                          $endgroup$
















                                                                            1












                                                                            1








                                                                            1





                                                                            $begingroup$


                                                                            Perl 5, 460 bytes





                                                                            printf"%023b",oct"0x$_"for qw/15400 141404 4444b2 555524 0 600 1a00 1a00 2a00 3e00 0 61c618 400190 68c61a 7df7df 0 80002 0 40001 7c001f 0 618718 404010 68639a 7df7df 0 81802 1800 41801 7c181f 1800 100804 81808 61810 18860 1980 18860 61810 81008 101804 201804 200808 101010 80060 60180 11d600 101000 107c00 10ba5b 1393f 5c3837 283b 10283f 102830 106c00 0 1c1000 1d4555 1c0154 140 7c00 1ff00 701c0 c0060 1a00b0 330198 228288 224488 22880 21080 20080 9400 3cfa78/


                                                                            Try it online!






                                                                            share|improve this answer









                                                                            $endgroup$




                                                                            Perl 5, 460 bytes





                                                                            printf"%023b",oct"0x$_"for qw/15400 141404 4444b2 555524 0 600 1a00 1a00 2a00 3e00 0 61c618 400190 68c61a 7df7df 0 80002 0 40001 7c001f 0 618718 404010 68639a 7df7df 0 81802 1800 41801 7c181f 1800 100804 81808 61810 18860 1980 18860 61810 81008 101804 201804 200808 101010 80060 60180 11d600 101000 107c00 10ba5b 1393f 5c3837 283b 10283f 102830 106c00 0 1c1000 1d4555 1c0154 140 7c00 1ff00 701c0 c0060 1a00b0 330198 228288 224488 22880 21080 20080 9400 3cfa78/


                                                                            Try it online!







                                                                            share|improve this answer












                                                                            share|improve this answer



                                                                            share|improve this answer










                                                                            answered 2 days ago









                                                                            XcaliXcali

                                                                            5,505520




                                                                            5,505520























                                                                                1












                                                                                $begingroup$

                                                                                bash + GNU tools, 351 bytes



                                                                                base64 -d<<<H4sIAPnNrVwCA6WUCRLDIAwDv8T+/3NNG4wvkTBTcisGSyA8xrcxj9Ds02F+Z7yuf3hnPyz0vYEGz+FG3IKBs+x3oL2PSh0TM/PnaGamft9nPUCew3uCp5RBWdRKGz+qNJn8qRKkkNaTBgeVIFXWOdi8VCaIeUnsfHo6TXpaFa3H5olf6J5MuIHLoEi0uKcRFCvEXG4xseglKzZg7kpYJSLMA3M7wXKR+/L2WiK0kvg+TDASLp6Co1KEVIlVmFzhCktRhBBDdSZYU1xKHrmDUllcWpNR/YNW2QNcHtF0rSySb0MXk/SDUgEwG5gfLvQDxuEdDo8GAAA=|gunzip


                                                                                TIO






                                                                                share|improve this answer











                                                                                $endgroup$













                                                                                • $begingroup$
                                                                                  didn't see your bash post before I posted mine - so much smaller!
                                                                                  $endgroup$
                                                                                  – Noodle9
                                                                                  yesterday
















                                                                                1












                                                                                $begingroup$

                                                                                bash + GNU tools, 351 bytes



                                                                                base64 -d<<<H4sIAPnNrVwCA6WUCRLDIAwDv8T+/3NNG4wvkTBTcisGSyA8xrcxj9Ds02F+Z7yuf3hnPyz0vYEGz+FG3IKBs+x3oL2PSh0TM/PnaGamft9nPUCew3uCp5RBWdRKGz+qNJn8qRKkkNaTBgeVIFXWOdi8VCaIeUnsfHo6TXpaFa3H5olf6J5MuIHLoEi0uKcRFCvEXG4xseglKzZg7kpYJSLMA3M7wXKR+/L2WiK0kvg+TDASLp6Co1KEVIlVmFzhCktRhBBDdSZYU1xKHrmDUllcWpNR/YNW2QNcHtF0rSySb0MXk/SDUgEwG5gfLvQDxuEdDo8GAAA=|gunzip


                                                                                TIO






                                                                                share|improve this answer











                                                                                $endgroup$













                                                                                • $begingroup$
                                                                                  didn't see your bash post before I posted mine - so much smaller!
                                                                                  $endgroup$
                                                                                  – Noodle9
                                                                                  yesterday














                                                                                1












                                                                                1








                                                                                1





                                                                                $begingroup$

                                                                                bash + GNU tools, 351 bytes



                                                                                base64 -d<<<H4sIAPnNrVwCA6WUCRLDIAwDv8T+/3NNG4wvkTBTcisGSyA8xrcxj9Ds02F+Z7yuf3hnPyz0vYEGz+FG3IKBs+x3oL2PSh0TM/PnaGamft9nPUCew3uCp5RBWdRKGz+qNJn8qRKkkNaTBgeVIFXWOdi8VCaIeUnsfHo6TXpaFa3H5olf6J5MuIHLoEi0uKcRFCvEXG4xseglKzZg7kpYJSLMA3M7wXKR+/L2WiK0kvg+TDASLp6Co1KEVIlVmFzhCktRhBBDdSZYU1xKHrmDUllcWpNR/YNW2QNcHtF0rSySb0MXk/SDUgEwG5gfLvQDxuEdDo8GAAA=|gunzip


                                                                                TIO






                                                                                share|improve this answer











                                                                                $endgroup$



                                                                                bash + GNU tools, 351 bytes



                                                                                base64 -d<<<H4sIAPnNrVwCA6WUCRLDIAwDv8T+/3NNG4wvkTBTcisGSyA8xrcxj9Ds02F+Z7yuf3hnPyz0vYEGz+FG3IKBs+x3oL2PSh0TM/PnaGamft9nPUCew3uCp5RBWdRKGz+qNJn8qRKkkNaTBgeVIFXWOdi8VCaIeUnsfHo6TXpaFa3H5olf6J5MuIHLoEi0uKcRFCvEXG4xseglKzZg7kpYJSLMA3M7wXKR+/L2WiK0kvg+TDASLp6Co1KEVIlVmFzhCktRhBBDdSZYU1xKHrmDUllcWpNR/YNW2QNcHtF0rSySb0MXk/SDUgEwG5gfLvQDxuEdDo8GAAA=|gunzip


                                                                                TIO







                                                                                share|improve this answer














                                                                                share|improve this answer



                                                                                share|improve this answer








                                                                                edited yesterday

























                                                                                answered yesterday









                                                                                Nahuel FouilleulNahuel Fouilleul

                                                                                3,025211




                                                                                3,025211












                                                                                • $begingroup$
                                                                                  didn't see your bash post before I posted mine - so much smaller!
                                                                                  $endgroup$
                                                                                  – Noodle9
                                                                                  yesterday


















                                                                                • $begingroup$
                                                                                  didn't see your bash post before I posted mine - so much smaller!
                                                                                  $endgroup$
                                                                                  – Noodle9
                                                                                  yesterday
















                                                                                $begingroup$
                                                                                didn't see your bash post before I posted mine - so much smaller!
                                                                                $endgroup$
                                                                                – Noodle9
                                                                                yesterday




                                                                                $begingroup$
                                                                                didn't see your bash post before I posted mine - so much smaller!
                                                                                $endgroup$
                                                                                – Noodle9
                                                                                yesterday











                                                                                1












                                                                                $begingroup$


                                                                                Java (OpenJDK 8), 364 bytes





                                                                                n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replaceAll("2","0000")


                                                                                Try it online!



                                                                                Explanation: First had n->new java.math.BigInteger(str,36).toString(2), just converting a radix 36 number to binary, but that needed nine extra chars for leading zeroes. Then, I got the idea of run-length encoding some zeroes as twos. A length of four zeroes seems to minimize the radix 36 length, so n->new java.math.BigInteger(str,36).toString(3).replaceAll("2","0000")



                                                                                See the discussion under this answer for the leading zeroes bug fix by @KevinCruijssen






                                                                                share|improve this answer









                                                                                $endgroup$













                                                                                • $begingroup$
                                                                                  Nice. It's impressively short for Java!
                                                                                  $endgroup$
                                                                                  – Eric Duminil
                                                                                  18 hours ago
















                                                                                1












                                                                                $begingroup$


                                                                                Java (OpenJDK 8), 364 bytes





                                                                                n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replaceAll("2","0000")


                                                                                Try it online!



                                                                                Explanation: First had n->new java.math.BigInteger(str,36).toString(2), just converting a radix 36 number to binary, but that needed nine extra chars for leading zeroes. Then, I got the idea of run-length encoding some zeroes as twos. A length of four zeroes seems to minimize the radix 36 length, so n->new java.math.BigInteger(str,36).toString(3).replaceAll("2","0000")



                                                                                See the discussion under this answer for the leading zeroes bug fix by @KevinCruijssen






                                                                                share|improve this answer









                                                                                $endgroup$













                                                                                • $begingroup$
                                                                                  Nice. It's impressively short for Java!
                                                                                  $endgroup$
                                                                                  – Eric Duminil
                                                                                  18 hours ago














                                                                                1












                                                                                1








                                                                                1





                                                                                $begingroup$


                                                                                Java (OpenJDK 8), 364 bytes





                                                                                n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replaceAll("2","0000")


                                                                                Try it online!



                                                                                Explanation: First had n->new java.math.BigInteger(str,36).toString(2), just converting a radix 36 number to binary, but that needed nine extra chars for leading zeroes. Then, I got the idea of run-length encoding some zeroes as twos. A length of four zeroes seems to minimize the radix 36 length, so n->new java.math.BigInteger(str,36).toString(3).replaceAll("2","0000")



                                                                                See the discussion under this answer for the leading zeroes bug fix by @KevinCruijssen






                                                                                share|improve this answer









                                                                                $endgroup$




                                                                                Java (OpenJDK 8), 364 bytes





                                                                                n->new java.math.BigInteger("in95mzupnpa2r0khpoepyql6ioqyn413avucdtfay6indx4wh9dehe3sn18klobtf4z9g9q17umqmwpegr2khb5eqinn7azl4jpfp2a8eui0xfrx5qwrou6gd65jh4ge3ls14k5lu7qrvmg6942ms29u5rb8fa6yrdhfoh5zoi9bdi7uh5ig0u0ff9kounth8sh357x7qox4m3oqviqsbrvakonbka4ahp21bgzi5v1akzzuqoncszhpabbru9q1uo2g11zr73iuyiqr5ikr69zn7cdv7e1lhd6ese9",36).toString(3).replaceAll("2","0000")


                                                                                Try it online!



                                                                                Explanation: First had n->new java.math.BigInteger(str,36).toString(2), just converting a radix 36 number to binary, but that needed nine extra chars for leading zeroes. Then, I got the idea of run-length encoding some zeroes as twos. A length of four zeroes seems to minimize the radix 36 length, so n->new java.math.BigInteger(str,36).toString(3).replaceAll("2","0000")



                                                                                See the discussion under this answer for the leading zeroes bug fix by @KevinCruijssen







                                                                                share|improve this answer












                                                                                share|improve this answer



                                                                                share|improve this answer










                                                                                answered yesterday









                                                                                JollyJokerJollyJoker

                                                                                39116




                                                                                39116












                                                                                • $begingroup$
                                                                                  Nice. It's impressively short for Java!
                                                                                  $endgroup$
                                                                                  – Eric Duminil
                                                                                  18 hours ago


















                                                                                • $begingroup$
                                                                                  Nice. It's impressively short for Java!
                                                                                  $endgroup$
                                                                                  – Eric Duminil
                                                                                  18 hours ago
















                                                                                $begingroup$
                                                                                Nice. It's impressively short for Java!
                                                                                $endgroup$
                                                                                – Eric Duminil
                                                                                18 hours ago




                                                                                $begingroup$
                                                                                Nice. It's impressively short for Java!
                                                                                $endgroup$
                                                                                – Eric Duminil
                                                                                18 hours ago











                                                                                1












                                                                                $begingroup$

                                                                                [Python 2], 346 bytes





                                                                                s='';
                                                                                for c in '''%pG+K$K&j h!kk ppjGDI2S2S1[1e?v~vw,x"z wgqcde e9G0G;G0eG,e6vv~w&G(gn wy uuuuG9G%I(G*I.G$I)eG$I%e)I,G'G'G$G%I&G&vI%G)w#I.y,w#I(vI%G&G%G'G$G&I'W'I'W(G&G$G&G&G&G+I(I'I(iq*G&G-G$e+g c!sG%m!md~ M$}(K$cO%K$eO%K$I%G$aBM$G-c hpoI(pG/K-e/eU+M&M(I*I&S(Q$y&y#hG$ng"j j G'hW+g#G+G(G-k*''':c=ord(c)-31;s+=c<39and'0'*c or bin(c-39)[2:]
                                                                                print s


                                                                                I encoded the length of strings of 0s as a byte starting at chr(31). Then I encoded the remaining 10101 as binary numbers starting at chr(70) up to chr(126). Binary strings that didn't fit were split up into smaller chunks.



                                                                                Edit: Reduced to 326 bytes. Thanks Jo King
                                                                                Edit: Fixed a bug in the code generator program






                                                                                share|improve this answer










                                                                                New contributor




                                                                                Benjamin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                Check out our Code of Conduct.






                                                                                $endgroup$













                                                                                • $begingroup$
                                                                                  Actually, a list comprehension is even shorter. [bin(c-39)[2:],'0'*c][c<39]. You're also missing the link part of your answer
                                                                                  $endgroup$
                                                                                  – Jo King
                                                                                  1 hour ago












                                                                                • $begingroup$
                                                                                  You don't need to save the big string in o to a variable.
                                                                                  $endgroup$
                                                                                  – xnor
                                                                                  1 hour ago
















                                                                                1












                                                                                $begingroup$

                                                                                [Python 2], 346 bytes





                                                                                s='';
                                                                                for c in '''%pG+K$K&j h!kk ppjGDI2S2S1[1e?v~vw,x"z wgqcde e9G0G;G0eG,e6vv~w&G(gn wy uuuuG9G%I(G*I.G$I)eG$I%e)I,G'G'G$G%I&G&vI%G)w#I.y,w#I(vI%G&G%G'G$G&I'W'I'W(G&G$G&G&G&G+I(I'I(iq*G&G-G$e+g c!sG%m!md~ M$}(K$cO%K$eO%K$I%G$aBM$G-c hpoI(pG/K-e/eU+M&M(I*I&S(Q$y&y#hG$ng"j j G'hW+g#G+G(G-k*''':c=ord(c)-31;s+=c<39and'0'*c or bin(c-39)[2:]
                                                                                print s


                                                                                I encoded the length of strings of 0s as a byte starting at chr(31). Then I encoded the remaining 10101 as binary numbers starting at chr(70) up to chr(126). Binary strings that didn't fit were split up into smaller chunks.



                                                                                Edit: Reduced to 326 bytes. Thanks Jo King
                                                                                Edit: Fixed a bug in the code generator program






                                                                                share|improve this answer










                                                                                New contributor




                                                                                Benjamin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                Check out our Code of Conduct.






                                                                                $endgroup$













                                                                                • $begingroup$
                                                                                  Actually, a list comprehension is even shorter. [bin(c-39)[2:],'0'*c][c<39]. You're also missing the link part of your answer
                                                                                  $endgroup$
                                                                                  – Jo King
                                                                                  1 hour ago












                                                                                • $begingroup$
                                                                                  You don't need to save the big string in o to a variable.
                                                                                  $endgroup$
                                                                                  – xnor
                                                                                  1 hour ago














                                                                                1












                                                                                1








                                                                                1





                                                                                $begingroup$

                                                                                [Python 2], 346 bytes





                                                                                s='';
                                                                                for c in '''%pG+K$K&j h!kk ppjGDI2S2S1[1e?v~vw,x"z wgqcde e9G0G;G0eG,e6vv~w&G(gn wy uuuuG9G%I(G*I.G$I)eG$I%e)I,G'G'G$G%I&G&vI%G)w#I.y,w#I(vI%G&G%G'G$G&I'W'I'W(G&G$G&G&G&G+I(I'I(iq*G&G-G$e+g c!sG%m!md~ M$}(K$cO%K$eO%K$I%G$aBM$G-c hpoI(pG/K-e/eU+M&M(I*I&S(Q$y&y#hG$ng"j j G'hW+g#G+G(G-k*''':c=ord(c)-31;s+=c<39and'0'*c or bin(c-39)[2:]
                                                                                print s


                                                                                I encoded the length of strings of 0s as a byte starting at chr(31). Then I encoded the remaining 10101 as binary numbers starting at chr(70) up to chr(126). Binary strings that didn't fit were split up into smaller chunks.



                                                                                Edit: Reduced to 326 bytes. Thanks Jo King
                                                                                Edit: Fixed a bug in the code generator program






                                                                                share|improve this answer










                                                                                New contributor




                                                                                Benjamin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                Check out our Code of Conduct.






                                                                                $endgroup$



                                                                                [Python 2], 346 bytes





                                                                                s='';
                                                                                for c in '''%pG+K$K&j h!kk ppjGDI2S2S1[1e?v~vw,x"z wgqcde e9G0G;G0eG,e6vv~w&G(gn wy uuuuG9G%I(G*I.G$I)eG$I%e)I,G'G'G$G%I&G&vI%G)w#I.y,w#I(vI%G&G%G'G$G&I'W'I'W(G&G$G&G&G&G+I(I'I(iq*G&G-G$e+g c!sG%m!md~ M$}(K$cO%K$eO%K$I%G$aBM$G-c hpoI(pG/K-e/eU+M&M(I*I&S(Q$y&y#hG$ng"j j G'hW+g#G+G(G-k*''':c=ord(c)-31;s+=c<39and'0'*c or bin(c-39)[2:]
                                                                                print s


                                                                                I encoded the length of strings of 0s as a byte starting at chr(31). Then I encoded the remaining 10101 as binary numbers starting at chr(70) up to chr(126). Binary strings that didn't fit were split up into smaller chunks.



                                                                                Edit: Reduced to 326 bytes. Thanks Jo King
                                                                                Edit: Fixed a bug in the code generator program







                                                                                share|improve this answer










                                                                                New contributor




                                                                                Benjamin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                Check out our Code of Conduct.









                                                                                share|improve this answer



                                                                                share|improve this answer








                                                                                edited 35 mins ago





















                                                                                New contributor




                                                                                Benjamin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                Check out our Code of Conduct.









                                                                                answered 2 hours ago









                                                                                BenjaminBenjamin

                                                                                112




                                                                                112




                                                                                New contributor




                                                                                Benjamin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                Check out our Code of Conduct.





                                                                                New contributor





                                                                                Benjamin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                Check out our Code of Conduct.






                                                                                Benjamin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                                                                                Check out our Code of Conduct.












                                                                                • $begingroup$
                                                                                  Actually, a list comprehension is even shorter. [bin(c-39)[2:],'0'*c][c<39]. You're also missing the link part of your answer
                                                                                  $endgroup$
                                                                                  – Jo King
                                                                                  1 hour ago












                                                                                • $begingroup$
                                                                                  You don't need to save the big string in o to a variable.
                                                                                  $endgroup$
                                                                                  – xnor
                                                                                  1 hour ago


















                                                                                • $begingroup$
                                                                                  Actually, a list comprehension is even shorter. [bin(c-39)[2:],'0'*c][c<39]. You're also missing the link part of your answer
                                                                                  $endgroup$
                                                                                  – Jo King
                                                                                  1 hour ago












                                                                                • $begingroup$
                                                                                  You don't need to save the big string in o to a variable.
                                                                                  $endgroup$
                                                                                  – xnor
                                                                                  1 hour ago
















                                                                                $begingroup$
                                                                                Actually, a list comprehension is even shorter. [bin(c-39)[2:],'0'*c][c<39]. You're also missing the link part of your answer
                                                                                $endgroup$
                                                                                – Jo King
                                                                                1 hour ago






                                                                                $begingroup$
                                                                                Actually, a list comprehension is even shorter. [bin(c-39)[2:],'0'*c][c<39]. You're also missing the link part of your answer
                                                                                $endgroup$
                                                                                – Jo King
                                                                                1 hour ago














                                                                                $begingroup$
                                                                                You don't need to save the big string in o to a variable.
                                                                                $endgroup$
                                                                                – xnor
                                                                                1 hour ago




                                                                                $begingroup$
                                                                                You don't need to save the big string in o to a variable.
                                                                                $endgroup$
                                                                                – xnor
                                                                                1 hour ago











                                                                                0












                                                                                $begingroup$


                                                                                Python 2, 336 bytes





                                                                                print bin(int('gVQAKCgJERLKqqkgAAAAAMAABoAADQAAKgAAfAAAAAMOMMQAGQ0Yw19998AAAAgAAgAAABAAB+AA+AAADDDjEBAENDHNffffAAAAIGAIAMAAQYAfgwPgBgAIBAIIGAgMMCAGIYAAzAAYhgDDAgIEAggMAiAYBEAQEEBAQEADAGAYAjrABAQACD4AELpbAnJ/cODcAUHZAoPyBQYEGwAAAAAcEAA6iqpwBVAACgAHwAA/4AHAcAYAMBoAsGYDMIoKIRIkQCKIAEIQAIAgAEoAPPp4'.decode('base64').encode('hex'),16))[3:]


                                                                                Try it online!



                                                                                Prints a string of bytes






                                                                                share|improve this answer









                                                                                $endgroup$


















                                                                                  0












                                                                                  $begingroup$


                                                                                  Python 2, 336 bytes





                                                                                  print bin(int('gVQAKCgJERLKqqkgAAAAAMAABoAADQAAKgAAfAAAAAMOMMQAGQ0Yw19998AAAAgAAgAAABAAB+AA+AAADDDjEBAENDHNffffAAAAIGAIAMAAQYAfgwPgBgAIBAIIGAgMMCAGIYAAzAAYhgDDAgIEAggMAiAYBEAQEEBAQEADAGAYAjrABAQACD4AELpbAnJ/cODcAUHZAoPyBQYEGwAAAAAcEAA6iqpwBVAACgAHwAA/4AHAcAYAMBoAsGYDMIoKIRIkQCKIAEIQAIAgAEoAPPp4'.decode('base64').encode('hex'),16))[3:]


                                                                                  Try it online!



                                                                                  Prints a string of bytes






                                                                                  share|improve this answer









                                                                                  $endgroup$
















                                                                                    0












                                                                                    0








                                                                                    0





                                                                                    $begingroup$


                                                                                    Python 2, 336 bytes





                                                                                    print bin(int('gVQAKCgJERLKqqkgAAAAAMAABoAADQAAKgAAfAAAAAMOMMQAGQ0Yw19998AAAAgAAgAAABAAB+AA+AAADDDjEBAENDHNffffAAAAIGAIAMAAQYAfgwPgBgAIBAIIGAgMMCAGIYAAzAAYhgDDAgIEAggMAiAYBEAQEEBAQEADAGAYAjrABAQACD4AELpbAnJ/cODcAUHZAoPyBQYEGwAAAAAcEAA6iqpwBVAACgAHwAA/4AHAcAYAMBoAsGYDMIoKIRIkQCKIAEIQAIAgAEoAPPp4'.decode('base64').encode('hex'),16))[3:]


                                                                                    Try it online!



                                                                                    Prints a string of bytes






                                                                                    share|improve this answer









                                                                                    $endgroup$




                                                                                    Python 2, 336 bytes





                                                                                    print bin(int('gVQAKCgJERLKqqkgAAAAAMAABoAADQAAKgAAfAAAAAMOMMQAGQ0Yw19998AAAAgAAgAAABAAB+AA+AAADDDjEBAENDHNffffAAAAIGAIAMAAQYAfgwPgBgAIBAIIGAgMMCAGIYAAzAAYhgDDAgIEAggMAiAYBEAQEEBAQEADAGAYAjrABAQACD4AELpbAnJ/cODcAUHZAoPyBQYEGwAAAAAcEAA6iqpwBVAACgAHwAA/4AHAcAYAMBoAsGYDMIoKIRIkQCKIAEIQAIAgAEoAPPp4'.decode('base64').encode('hex'),16))[3:]


                                                                                    Try it online!



                                                                                    Prints a string of bytes







                                                                                    share|improve this answer












                                                                                    share|improve this answer



                                                                                    share|improve this answer










                                                                                    answered yesterday









                                                                                    TFeldTFeld

                                                                                    16.5k21451




                                                                                    16.5k21451























                                                                                        0












                                                                                        $begingroup$


                                                                                        Bash, 702 697 bytes





                                                                                        xxd -r -p<<X|xz -dc
                                                                                        fd377a585a000004e6d6b4460200210116000000742fe5a3e006d7010c5d
                                                                                        0018698865079cf6752c9e9a501a87a798b4844f9fcfdaaf87733b9d8239
                                                                                        48c816d860a938767f6cb81299f3e8a638effe3068c0e096a8949c81d706
                                                                                        7dff3ec44e5df185b3a48e5b5857724386e8c37cfbd5c856b12614ee78ec
                                                                                        c41df4db3aea71fd3a8fa474905609f78eb3fd66e246557965e4ab6dfd67
                                                                                        efbd9202f542ded9cf98a6401ee2d23afb2f544bd2442c6f428fd612397c
                                                                                        f2c6ec50847ddccc5832185e487712e5a7676b97058d7e485d5a3536166a
                                                                                        44ab3c689c93073cdda73b5306a83c4cd268e79db238bfa2d08ac912a578
                                                                                        75020bc7828342d5a62ce367aff7fd89290336128d119fa4272da2b2a79f
                                                                                        5973c71935af054f2d91c1bd3ea4847a3502d6dc8c975114dacf8a4de600
                                                                                        622d80986dbb0cd00001a802d80d00001b16e2a7b1c467fb020000000004
                                                                                        595a
                                                                                        X


                                                                                        Try it online!






                                                                                        share|improve this answer











                                                                                        $endgroup$


















                                                                                          0












                                                                                          $begingroup$


                                                                                          Bash, 702 697 bytes





                                                                                          xxd -r -p<<X|xz -dc
                                                                                          fd377a585a000004e6d6b4460200210116000000742fe5a3e006d7010c5d
                                                                                          0018698865079cf6752c9e9a501a87a798b4844f9fcfdaaf87733b9d8239
                                                                                          48c816d860a938767f6cb81299f3e8a638effe3068c0e096a8949c81d706
                                                                                          7dff3ec44e5df185b3a48e5b5857724386e8c37cfbd5c856b12614ee78ec
                                                                                          c41df4db3aea71fd3a8fa474905609f78eb3fd66e246557965e4ab6dfd67
                                                                                          efbd9202f542ded9cf98a6401ee2d23afb2f544bd2442c6f428fd612397c
                                                                                          f2c6ec50847ddccc5832185e487712e5a7676b97058d7e485d5a3536166a
                                                                                          44ab3c689c93073cdda73b5306a83c4cd268e79db238bfa2d08ac912a578
                                                                                          75020bc7828342d5a62ce367aff7fd89290336128d119fa4272da2b2a79f
                                                                                          5973c71935af054f2d91c1bd3ea4847a3502d6dc8c975114dacf8a4de600
                                                                                          622d80986dbb0cd00001a802d80d00001b16e2a7b1c467fb020000000004
                                                                                          595a
                                                                                          X


                                                                                          Try it online!






                                                                                          share|improve this answer











                                                                                          $endgroup$
















                                                                                            0












                                                                                            0








                                                                                            0





                                                                                            $begingroup$


                                                                                            Bash, 702 697 bytes





                                                                                            xxd -r -p<<X|xz -dc
                                                                                            fd377a585a000004e6d6b4460200210116000000742fe5a3e006d7010c5d
                                                                                            0018698865079cf6752c9e9a501a87a798b4844f9fcfdaaf87733b9d8239
                                                                                            48c816d860a938767f6cb81299f3e8a638effe3068c0e096a8949c81d706
                                                                                            7dff3ec44e5df185b3a48e5b5857724386e8c37cfbd5c856b12614ee78ec
                                                                                            c41df4db3aea71fd3a8fa474905609f78eb3fd66e246557965e4ab6dfd67
                                                                                            efbd9202f542ded9cf98a6401ee2d23afb2f544bd2442c6f428fd612397c
                                                                                            f2c6ec50847ddccc5832185e487712e5a7676b97058d7e485d5a3536166a
                                                                                            44ab3c689c93073cdda73b5306a83c4cd268e79db238bfa2d08ac912a578
                                                                                            75020bc7828342d5a62ce367aff7fd89290336128d119fa4272da2b2a79f
                                                                                            5973c71935af054f2d91c1bd3ea4847a3502d6dc8c975114dacf8a4de600
                                                                                            622d80986dbb0cd00001a802d80d00001b16e2a7b1c467fb020000000004
                                                                                            595a
                                                                                            X


                                                                                            Try it online!






                                                                                            share|improve this answer











                                                                                            $endgroup$




                                                                                            Bash, 702 697 bytes





                                                                                            xxd -r -p<<X|xz -dc
                                                                                            fd377a585a000004e6d6b4460200210116000000742fe5a3e006d7010c5d
                                                                                            0018698865079cf6752c9e9a501a87a798b4844f9fcfdaaf87733b9d8239
                                                                                            48c816d860a938767f6cb81299f3e8a638effe3068c0e096a8949c81d706
                                                                                            7dff3ec44e5df185b3a48e5b5857724386e8c37cfbd5c856b12614ee78ec
                                                                                            c41df4db3aea71fd3a8fa474905609f78eb3fd66e246557965e4ab6dfd67
                                                                                            efbd9202f542ded9cf98a6401ee2d23afb2f544bd2442c6f428fd612397c
                                                                                            f2c6ec50847ddccc5832185e487712e5a7676b97058d7e485d5a3536166a
                                                                                            44ab3c689c93073cdda73b5306a83c4cd268e79db238bfa2d08ac912a578
                                                                                            75020bc7828342d5a62ce367aff7fd89290336128d119fa4272da2b2a79f
                                                                                            5973c71935af054f2d91c1bd3ea4847a3502d6dc8c975114dacf8a4de600
                                                                                            622d80986dbb0cd00001a802d80d00001b16e2a7b1c467fb020000000004
                                                                                            595a
                                                                                            X


                                                                                            Try it online!







                                                                                            share|improve this answer














                                                                                            share|improve this answer



                                                                                            share|improve this answer








                                                                                            edited yesterday

























                                                                                            answered yesterday









                                                                                            Noodle9Noodle9

                                                                                            30137




                                                                                            30137























                                                                                                0












                                                                                                $begingroup$


                                                                                                Ruby, 362 bytes





                                                                                                puts"5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0".to_i(36).to_s(2).rjust(1679,?0)


                                                                                                Integer written in base 36. There's surely a more efficient way to compress the integer, e.g. with zlib or base64.



                                                                                                Try it online!






                                                                                                share|improve this answer











                                                                                                $endgroup$


















                                                                                                  0












                                                                                                  $begingroup$


                                                                                                  Ruby, 362 bytes





                                                                                                  puts"5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0".to_i(36).to_s(2).rjust(1679,?0)


                                                                                                  Integer written in base 36. There's surely a more efficient way to compress the integer, e.g. with zlib or base64.



                                                                                                  Try it online!






                                                                                                  share|improve this answer











                                                                                                  $endgroup$
















                                                                                                    0












                                                                                                    0








                                                                                                    0





                                                                                                    $begingroup$


                                                                                                    Ruby, 362 bytes





                                                                                                    puts"5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0".to_i(36).to_s(2).rjust(1679,?0)


                                                                                                    Integer written in base 36. There's surely a more efficient way to compress the integer, e.g. with zlib or base64.



                                                                                                    Try it online!






                                                                                                    share|improve this answer











                                                                                                    $endgroup$




                                                                                                    Ruby, 362 bytes





                                                                                                    puts"5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0".to_i(36).to_s(2).rjust(1679,?0)


                                                                                                    Integer written in base 36. There's surely a more efficient way to compress the integer, e.g. with zlib or base64.



                                                                                                    Try it online!







                                                                                                    share|improve this answer














                                                                                                    share|improve this answer



                                                                                                    share|improve this answer








                                                                                                    edited yesterday

























                                                                                                    answered yesterday









                                                                                                    Eric DuminilEric Duminil

                                                                                                    46128




                                                                                                    46128























                                                                                                        0












                                                                                                        $begingroup$

                                                                                                        [C++ (VC++)(but tested with gcc as well)], 585 bytes





                                                                                                        #define l(x,y)for(int x=0;x<y;x++)
                                                                                                        void f(){const char*a="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";int x=1679;l(i,365){int d=a[i],c=0;d-=(d>47&d<58)?48:((d>64&d<71)?55:0);if(d>70&d<91)c=91-d,d=a[i-1];for(c;c>=0;c--)l(j,4){if(x--)cout<<(int)((d&(8>>j))>0);}}}



                                                                                                        Try it online!



                                                                                                        ungolfed Version (lacks the break after the 1679th element though and goes until the 1680th):



                                                                                                        #include <stdio.h>
                                                                                                        #include <iostream>
                                                                                                        using namespace std;
                                                                                                        int main()
                                                                                                        {
                                                                                                        const char arecibo="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";
                                                                                                        int i = 0,j;
                                                                                                        while (i<sizeof(arecibo)-1)
                                                                                                        {
                                                                                                        char digit = arecibo[i];
                                                                                                        int count=0;
                                                                                                        if (digit >= '0' & digit <= '9')
                                                                                                        {
                                                                                                        digit -= '0';
                                                                                                        }
                                                                                                        else if (digit>='A'& digit<='F')
                                                                                                        {
                                                                                                        digit -= 'A'-10;
                                                                                                        }
                                                                                                        else if (digit > 'F'&digit<='Z')
                                                                                                        {
                                                                                                        //digit does not contain any valid hex digit in this case
                                                                                                        count = 'Z' - digit+1; //digit = Z means repeat 2 more times...
                                                                                                        digit = arecibo[i - 1];
                                                                                                        }
                                                                                                        for (count; count >= 0; count--)
                                                                                                        {
                                                                                                        for (j = 0; j<4; j++)
                                                                                                        {
                                                                                                        cout << (int)(((digit)&(8 >> j))>0);
                                                                                                        }
                                                                                                        }
                                                                                                        i++;
                                                                                                        }
                                                                                                        return 0;
                                                                                                        }


                                                                                                        as an Explanation: i concatenated the 73 lines of sample output given to one long line.
                                                                                                        i encoded them in hexadecimal where the bit order is msbfirst (using this program https://github.com/Marc-Bender/longBinaryStreamToHex/releases/download/addedErrorCode-4/longBinaryStreamToHex.exe)
                                                                                                        i shortened the Output of that by about 70 hexadecimal Digits by using the letters 'G'-'Z' as a sign to repeat the last Digit for a certain amount of times (Z = 2more times, Y = 3more times …)
                                                                                                        the rest should be relatively self explainatory for Code-Golfers. abusing the preprocessor to shorten loops, abusing the , Operator and the like.



                                                                                                        Output Format is uninterrupted stream of 1679 0/1-values.






                                                                                                        share|improve this answer









                                                                                                        $endgroup$













                                                                                                        • $begingroup$
                                                                                                          before anybody asks the const is for compatibility with VC++ (what the main development work was done with)
                                                                                                          $endgroup$
                                                                                                          – der bender
                                                                                                          yesterday
















                                                                                                        0












                                                                                                        $begingroup$

                                                                                                        [C++ (VC++)(but tested with gcc as well)], 585 bytes





                                                                                                        #define l(x,y)for(int x=0;x<y;x++)
                                                                                                        void f(){const char*a="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";int x=1679;l(i,365){int d=a[i],c=0;d-=(d>47&d<58)?48:((d>64&d<71)?55:0);if(d>70&d<91)c=91-d,d=a[i-1];for(c;c>=0;c--)l(j,4){if(x--)cout<<(int)((d&(8>>j))>0);}}}



                                                                                                        Try it online!



                                                                                                        ungolfed Version (lacks the break after the 1679th element though and goes until the 1680th):



                                                                                                        #include <stdio.h>
                                                                                                        #include <iostream>
                                                                                                        using namespace std;
                                                                                                        int main()
                                                                                                        {
                                                                                                        const char arecibo="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";
                                                                                                        int i = 0,j;
                                                                                                        while (i<sizeof(arecibo)-1)
                                                                                                        {
                                                                                                        char digit = arecibo[i];
                                                                                                        int count=0;
                                                                                                        if (digit >= '0' & digit <= '9')
                                                                                                        {
                                                                                                        digit -= '0';
                                                                                                        }
                                                                                                        else if (digit>='A'& digit<='F')
                                                                                                        {
                                                                                                        digit -= 'A'-10;
                                                                                                        }
                                                                                                        else if (digit > 'F'&digit<='Z')
                                                                                                        {
                                                                                                        //digit does not contain any valid hex digit in this case
                                                                                                        count = 'Z' - digit+1; //digit = Z means repeat 2 more times...
                                                                                                        digit = arecibo[i - 1];
                                                                                                        }
                                                                                                        for (count; count >= 0; count--)
                                                                                                        {
                                                                                                        for (j = 0; j<4; j++)
                                                                                                        {
                                                                                                        cout << (int)(((digit)&(8 >> j))>0);
                                                                                                        }
                                                                                                        }
                                                                                                        i++;
                                                                                                        }
                                                                                                        return 0;
                                                                                                        }


                                                                                                        as an Explanation: i concatenated the 73 lines of sample output given to one long line.
                                                                                                        i encoded them in hexadecimal where the bit order is msbfirst (using this program https://github.com/Marc-Bender/longBinaryStreamToHex/releases/download/addedErrorCode-4/longBinaryStreamToHex.exe)
                                                                                                        i shortened the Output of that by about 70 hexadecimal Digits by using the letters 'G'-'Z' as a sign to repeat the last Digit for a certain amount of times (Z = 2more times, Y = 3more times …)
                                                                                                        the rest should be relatively self explainatory for Code-Golfers. abusing the preprocessor to shorten loops, abusing the , Operator and the like.



                                                                                                        Output Format is uninterrupted stream of 1679 0/1-values.






                                                                                                        share|improve this answer









                                                                                                        $endgroup$













                                                                                                        • $begingroup$
                                                                                                          before anybody asks the const is for compatibility with VC++ (what the main development work was done with)
                                                                                                          $endgroup$
                                                                                                          – der bender
                                                                                                          yesterday














                                                                                                        0












                                                                                                        0








                                                                                                        0





                                                                                                        $begingroup$

                                                                                                        [C++ (VC++)(but tested with gcc as well)], 585 bytes





                                                                                                        #define l(x,y)for(int x=0;x<y;x++)
                                                                                                        void f(){const char*a="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";int x=1679;l(i,365){int d=a[i],c=0;d-=(d>47&d<58)?48:((d>64&d<71)?55:0);if(d>70&d<91)c=91-d,d=a[i-1];for(c;c>=0;c--)l(j,4){if(x--)cout<<(int)((d&(8>>j))>0);}}}



                                                                                                        Try it online!



                                                                                                        ungolfed Version (lacks the break after the 1679th element though and goes until the 1680th):



                                                                                                        #include <stdio.h>
                                                                                                        #include <iostream>
                                                                                                        using namespace std;
                                                                                                        int main()
                                                                                                        {
                                                                                                        const char arecibo="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";
                                                                                                        int i = 0,j;
                                                                                                        while (i<sizeof(arecibo)-1)
                                                                                                        {
                                                                                                        char digit = arecibo[i];
                                                                                                        int count=0;
                                                                                                        if (digit >= '0' & digit <= '9')
                                                                                                        {
                                                                                                        digit -= '0';
                                                                                                        }
                                                                                                        else if (digit>='A'& digit<='F')
                                                                                                        {
                                                                                                        digit -= 'A'-10;
                                                                                                        }
                                                                                                        else if (digit > 'F'&digit<='Z')
                                                                                                        {
                                                                                                        //digit does not contain any valid hex digit in this case
                                                                                                        count = 'Z' - digit+1; //digit = Z means repeat 2 more times...
                                                                                                        digit = arecibo[i - 1];
                                                                                                        }
                                                                                                        for (count; count >= 0; count--)
                                                                                                        {
                                                                                                        for (j = 0; j<4; j++)
                                                                                                        {
                                                                                                        cout << (int)(((digit)&(8 >> j))>0);
                                                                                                        }
                                                                                                        }
                                                                                                        i++;
                                                                                                        }
                                                                                                        return 0;
                                                                                                        }


                                                                                                        as an Explanation: i concatenated the 73 lines of sample output given to one long line.
                                                                                                        i encoded them in hexadecimal where the bit order is msbfirst (using this program https://github.com/Marc-Bender/longBinaryStreamToHex/releases/download/addedErrorCode-4/longBinaryStreamToHex.exe)
                                                                                                        i shortened the Output of that by about 70 hexadecimal Digits by using the letters 'G'-'Z' as a sign to repeat the last Digit for a certain amount of times (Z = 2more times, Y = 3more times …)
                                                                                                        the rest should be relatively self explainatory for Code-Golfers. abusing the preprocessor to shorten loops, abusing the , Operator and the like.



                                                                                                        Output Format is uninterrupted stream of 1679 0/1-values.






                                                                                                        share|improve this answer









                                                                                                        $endgroup$



                                                                                                        [C++ (VC++)(but tested with gcc as well)], 585 bytes





                                                                                                        #define l(x,y)for(int x=0;x<y;x++)
                                                                                                        void f(){const char*a="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";int x=1679;l(i,365){int d=a[i],c=0;d-=(d>47&d<58)?48:((d>64&d<71)?55:0);if(d>70&d<91)c=91-d,d=a[i-1];for(c;c>=0;c--)l(j,4){if(x--)cout<<(int)((d&(8>>j))>0);}}}



                                                                                                        Try it online!



                                                                                                        ungolfed Version (lacks the break after the 1679th element though and goes until the 1680th):



                                                                                                        #include <stdio.h>
                                                                                                        #include <iostream>
                                                                                                        using namespace std;
                                                                                                        int main()
                                                                                                        {
                                                                                                        const char arecibo="02A800505012Y595Y240U180YD0Y1A0Y540YF80V61C618800321A3186BEFBEF80X10Y40W20YFC001F0X1861C620200868639AFBEFBE0W40C0100180Z83003F0607C00C001008041030101860400C430Z19800310C018604040804101804403008802020808080800600C030047580080800107C002174B604E4FEE1C1B80283B20507E40A0C08360U3820Z751554E00AA0Z140ZF80Z7FC00380E00C0060340160CC06611414422448804510Z8420010040Z940079F4F0";
                                                                                                        int i = 0,j;
                                                                                                        while (i<sizeof(arecibo)-1)
                                                                                                        {
                                                                                                        char digit = arecibo[i];
                                                                                                        int count=0;
                                                                                                        if (digit >= '0' & digit <= '9')
                                                                                                        {
                                                                                                        digit -= '0';
                                                                                                        }
                                                                                                        else if (digit>='A'& digit<='F')
                                                                                                        {
                                                                                                        digit -= 'A'-10;
                                                                                                        }
                                                                                                        else if (digit > 'F'&digit<='Z')
                                                                                                        {
                                                                                                        //digit does not contain any valid hex digit in this case
                                                                                                        count = 'Z' - digit+1; //digit = Z means repeat 2 more times...
                                                                                                        digit = arecibo[i - 1];
                                                                                                        }
                                                                                                        for (count; count >= 0; count--)
                                                                                                        {
                                                                                                        for (j = 0; j<4; j++)
                                                                                                        {
                                                                                                        cout << (int)(((digit)&(8 >> j))>0);
                                                                                                        }
                                                                                                        }
                                                                                                        i++;
                                                                                                        }
                                                                                                        return 0;
                                                                                                        }


                                                                                                        as an Explanation: i concatenated the 73 lines of sample output given to one long line.
                                                                                                        i encoded them in hexadecimal where the bit order is msbfirst (using this program https://github.com/Marc-Bender/longBinaryStreamToHex/releases/download/addedErrorCode-4/longBinaryStreamToHex.exe)
                                                                                                        i shortened the Output of that by about 70 hexadecimal Digits by using the letters 'G'-'Z' as a sign to repeat the last Digit for a certain amount of times (Z = 2more times, Y = 3more times …)
                                                                                                        the rest should be relatively self explainatory for Code-Golfers. abusing the preprocessor to shorten loops, abusing the , Operator and the like.



                                                                                                        Output Format is uninterrupted stream of 1679 0/1-values.







                                                                                                        share|improve this answer












                                                                                                        share|improve this answer



                                                                                                        share|improve this answer










                                                                                                        answered yesterday









                                                                                                        der benderder bender

                                                                                                        212




                                                                                                        212












                                                                                                        • $begingroup$
                                                                                                          before anybody asks the const is for compatibility with VC++ (what the main development work was done with)
                                                                                                          $endgroup$
                                                                                                          – der bender
                                                                                                          yesterday


















                                                                                                        • $begingroup$
                                                                                                          before anybody asks the const is for compatibility with VC++ (what the main development work was done with)
                                                                                                          $endgroup$
                                                                                                          – der bender
                                                                                                          yesterday
















                                                                                                        $begingroup$
                                                                                                        before anybody asks the const is for compatibility with VC++ (what the main development work was done with)
                                                                                                        $endgroup$
                                                                                                        – der bender
                                                                                                        yesterday




                                                                                                        $begingroup$
                                                                                                        before anybody asks the const is for compatibility with VC++ (what the main development work was done with)
                                                                                                        $endgroup$
                                                                                                        – der bender
                                                                                                        yesterday











                                                                                                        0












                                                                                                        $begingroup$


                                                                                                        Perl 6, 348 bytes





                                                                                                        {"000000"~:36<5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0>.base(2)}


                                                                                                        Based on Benjamin Urquhart's Java solution.



                                                                                                        Uses a straight stream of 0 and 1 characters. The link below has some code to prettify the output.



                                                                                                        Try it online!






                                                                                                        share|improve this answer









                                                                                                        $endgroup$


















                                                                                                          0












                                                                                                          $begingroup$


                                                                                                          Perl 6, 348 bytes





                                                                                                          {"000000"~:36<5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0>.base(2)}


                                                                                                          Based on Benjamin Urquhart's Java solution.



                                                                                                          Uses a straight stream of 0 and 1 characters. The link below has some code to prettify the output.



                                                                                                          Try it online!






                                                                                                          share|improve this answer









                                                                                                          $endgroup$
















                                                                                                            0












                                                                                                            0








                                                                                                            0





                                                                                                            $begingroup$


                                                                                                            Perl 6, 348 bytes





                                                                                                            {"000000"~:36<5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0>.base(2)}


                                                                                                            Based on Benjamin Urquhart's Java solution.



                                                                                                            Uses a straight stream of 0 and 1 characters. The link below has some code to prettify the output.



                                                                                                            Try it online!






                                                                                                            share|improve this answer









                                                                                                            $endgroup$




                                                                                                            Perl 6, 348 bytes





                                                                                                            {"000000"~:36<5r0afnfm8wyke8tfy1pwt7xnuaxyh3wodfp7bhsdufyw0xbdp1pumrz2xir652tuc0ss9oec8yad9vefivd66j126wybhefgk2lv38uqqiur11u26q275jk3h2ucithd59awpaenqpqi1pszh52179zw0ddqtbrvo6kyrrgv8c34pqrp83j8estjp63v29t4hqp9yg2hhzjlq1e9zqx6gh20n9lsttimz3nbq060ritrphxaru7quwmv3oujhd9xjddpbacq4bnpf270znhgto59yn0980itylf95pxw9x7rvkvi7mfql1sx46puo8rg4dq0>.base(2)}


                                                                                                            Based on Benjamin Urquhart's Java solution.



                                                                                                            Uses a straight stream of 0 and 1 characters. The link below has some code to prettify the output.



                                                                                                            Try it online!







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                                                                                                            answered 22 hours ago









                                                                                                            bb94bb94

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